For real numbers , , and , none of which is equal to zero, suppose that , , and . Which of the following inequalities MUST be true?
- Cevap
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Cevap
The condition reduces to because . The condition reduces to because , implying and have opposite signs (). Substituting into forces . Furthermore, with requires . Then and force . Consequently, and are both negative numbers, so is negative. Dividing this negative sum by the positive number guarantees that MUST be true.
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Anahtar Kavram
Deduction of positive and negative variable signs from products, quotients, and sums in inequalities.
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