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Zorluk: KolayLinear Inequalities and Absolute Value

If ∣2x−4∣≤6|2x - 4| \le 6, which of the following values could be a solution for xx? Select all that apply.

  1. A
    −3-3
  2. −1-1Cevap
  3. 22Cevap
  4. 55Cevap
  5. E
    66

Cevap

The values −1-1, 22, and 55 are solutions to the inequality.
Solving ∣2x−4∣≤6|2x - 4| \le 6 yields −6≤2x−4≤6-6 \le 2x - 4 \le 6. Adding 44 gives −2≤2x≤10-2 \le 2x \le 10, and dividing by 22 gives −1≤x≤5-1 \le x \le 5. The options stating −1-1, 22, and 55 are all within this interval [−1,5][-1, 5].

Adım Adım Çözüm

1
Rewrite the absolute value inequality as a compound inequality.
−6≤2x−4≤6-6 \le 2x - 4 \le 6
An inequality of the form ∣u∣≤c|u| \le c (where c≥0c \ge 0) is equivalent to −c≤u≤c-c \le u \le c.
2
Add 44 to all three parts of the compound inequality.
−2≤2x≤10-2 \le 2x \le 10
Isolate the variable term 2x2x in the middle.
3
Divide all three parts by 22.
−1≤x≤5-1 \le x \le 5
Isolate xx. Since 22 is positive, the inequality signs remain unchanged.
4
Test which of the given choices fall within the interval [−1,5][-1, 5].
−1-1, 22, and 55 lie within the range [−1,5][-1, 5], while −3-3 and 66 lie outside.
Values equal to or between −1-1 and 55 inclusive are valid solutions.

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Linear Inequalities and Absolute Value
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