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Zorluk: OrtaEven-Odd Properties and Sign Rules

For how many integer values of nn in the interval 15n15-15 \le n \le 15 is the value of the expression (1)n2+n(1)3n(-1)^{n^2 + n} - (-1)^{3n} equal to 22?

Cevap: 16

Cevap

The correct answer is 16.
Because n2+n=n(n+1)n^2 + n = n(n + 1) is the product of two consecutive integers, it is guaranteed to be even for every integer nn. Consequently, (1)n2+n=1(-1)^{n^2 + n} = 1. Substituting this into the given equation yields 1(1)3n=21 - (-1)^{3n} = 2, which reduces to (1)3n=1(-1)^{3n} = -1. A power of 1-1 equals 1-1 if and only if the exponent is odd, so 3n3n must be odd, which requires nn itself to be odd. In the interval [15,15][-15, 15], there are 16 odd integers: 8 negative odd integers and 8 positive odd integers.

Adım Adım Çözüm

1
Determine the parity of n2+nn^2 + n
The expression n2+n=n(n+1)n^2 + n = n(n + 1) represents the product of two consecutive integers. Because one of any two consecutive integers is even, their product is always even. Therefore, (1)n2+n=1(-1)^{n^2 + n} = 1 for all integers nn.
Simplifying the exponent with a known parity rule reduces the expression to a constant.
2
Isolate (1)3n(-1)^{3n} in the equation
Substituting 11 into the original equation gives 1(1)3n=21 - (-1)^{3n} = 2, which simplifies to (1)3n=1(-1)^{3n} = -1.
Isolating the exponential term reveals the sign condition required for the equality to hold.
3
Find the parity condition for nn
For (1)3n(-1)^{3n} to equal 1-1, the exponent 3n3n must be an odd integer. Since 33 is odd, the product 3n3n is odd if and only if nn is odd.
Applying the product parity rule (odd×odd=odd\text{odd} \times \text{odd} = \text{odd}) relates the condition on 3n3n back to nn.
4
Count the odd integers in the interval [15,15][-15, 15]
The odd integers in the interval are 15,13,11,9,7,5,3,1,1,3,5,7,9,11,13,15-15, -13, -11, -9, -7, -5, -3, -1, 1, 3, 5, 7, 9, 11, 13, 15. There are 16 such integers.
Counting all qualifying values within the specified range yields the final numeric answer.

Anahtar Kavram

Parity rules for consecutive integers and exponents of negative numbers
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