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Zorluk: ZorRatios, Rates, and Proportions

A logistics company operates a fleet of 1414 vans consisting solely of Model XX and Model YY vans.

- The ratio of the cargo volume capacity of one Model XX van to one Model YY van is 3:53 : 5.
- The ratio of the energy consumption rate (in kWh per mile) of one Model XX van to one Model YY van is 4:54 : 5.
- When fully loaded, a Model XX van carries 30 m330\text{ m}^3 of cargo and a Model YY van carries 50 m350\text{ m}^3 of cargo.
- The entire fleet of 1414 vans, when fully loaded, transports a total of 620 m3620\text{ m}^3 of cargo in one trip.
- A Model XX van consumes 2 kWh2\text{ kWh} of energy per mile.

Which of the following statements must be true? Select all such statements.

  1. There are exactly 44 Model XX vans in the fleet.Cevap
  2. B
    Model XX vans account for 38\frac{3}{8} of the total cargo capacity transported by the fleet.
  3. The total energy consumed by the entire fleet per mile is 33 kWh33\text{ kWh}.Cevap
  4. D
    The average energy consumption rate per van in the fleet is 2.25 kWh2.25\text{ kWh} per mile.
  5. E
    If the cargo capacity of each Model YY van is increased by 20%20\%, the total cargo capacity of the entire fleet would increase by 20%20\%.

Cevap

The correct statements are that there are exactly 4 Model X vans in the fleet and that the total energy consumed by the entire fleet per mile is 33 kWh.
The statement specifying that there are exactly 4 Model X vans is correct because solving the system nX+nY=14n_X + n_Y = 14 and 30nX+50nY=62030 n_X + 50 n_Y = 620 gives nX=4n_X = 4. The statement asserting that total fleet energy consumption per mile is 33 kWh is also correct because 4(2 kWh)+10(2.5 kWh)=33 kWh4(2\text{ kWh}) + 10(2.5\text{ kWh}) = 33\text{ kWh}.

Adım Adım Çözüm

1
Determine the number of Model X and Model Y vans using fleet totals.
Let nXn_X be the number of Model X vans and nYn_Y be the number of Model Y vans. Given nX+nY=14n_X + n_Y = 14, substitute nY=14nXn_Y = 14 - n_X into the total cargo equation: 30nX+50(14nX)=620    70020nX=620    20nX=80    nX=430 n_X + 50(14 - n_X) = 620 \implies 700 - 20 n_X = 620 \implies 20 n_X = 80 \implies n_X = 4. Thus, nY=10n_Y = 10.
This establishes the exact composition of the fleet.
2
Evaluate the fraction of cargo carried by Model X vans.
Total cargo carried by Model X vans = 4×30=120 m34 \times 30 = 120\text{ m}^3. Fleet total cargo = 620 m3620\text{ m}^3. Fraction = 120620=631\frac{120}{620} = \frac{6}{31}.
Shows that the fleet cargo share depends on the van counts, not just the single-van ratio of 3 to 5.
3
Calculate individual consumption rates and total fleet consumption per mile.
The consumption rate ratio of Model X to Model Y is 4:54 : 5. Given Model X rate is 2 kWh/mile2\text{ kWh/mile}, Model Y rate is 2×54=2.5 kWh/mile2 \times \frac{5}{4} = 2.5\text{ kWh/mile}. Total fleet consumption per mile = 4(2)+10(2.5)=8+25=33 kWh4(2) + 10(2.5) = 8 + 25 = 33\text{ kWh}.
Applies unit rates to the known number of each van model to find total rate.
4
Calculate the true weighted average consumption rate per van.
Average consumption rate per van = Total energy per mileTotal vans=33 kWh14 vans2.36 kWh/mile\frac{\text{Total energy per mile}}{\text{Total vans}} = \frac{33\text{ kWh}}{14\text{ vans}} \approx 2.36\text{ kWh/mile}.
Demonstrates why taking an unweighted mean (2.0+2.5)/2=2.25(2.0 + 2.5)/2 = 2.25 is incorrect when group sizes are unequal.
5
Analyze the impact of a 20% increase in Model Y capacity.
Initial Model Y total capacity = 10×50=500 m310 \times 50 = 500\text{ m}^3. A 20%20\% increase adds 0.20×500=100 m30.20 \times 500 = 100\text{ m}^3. Percent increase in total fleet capacity = 10062016.13%\frac{100}{620} \approx 16.13\%.
A percentage change in a part does not equal the percentage change in the whole.

Anahtar Kavram

Weighted averages and component vs. whole relationships in multi-part ratios and rates.
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