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Zorluk: Çok zorCoordinate Geometry and Lines

In the xyxy-plane, line 1\ell_1 passes through the point (3,7)(3, 7) and is perpendicular to line 2\ell_2, which is defined by the equation 2x5y=102x - 5y = 10. Line 3\ell_3 is parallel to line 1\ell_1 and has a yy-intercept that is 66 units greater than the yy-intercept of line 1\ell_1. If line 3\ell_3 intersects the xx-axis at the point (a,0)(a, 0), what is the value of aa?

Cevap: 8.2

Cevap

The value of aa is 8.2 (or 415\frac{41}{5}).
Converting 2x5y=102x - 5y = 10 to slope-intercept form yields y=25x2y = \frac{2}{5}x - 2, so the slope of line 2\ell_2 is 25\frac{2}{5}. Line 1\ell_1 is perpendicular to 2\ell_2, giving it a slope of m1=52m_1 = -\frac{5}{2}. Using the point (3,7)(3, 7), the line equation for 1\ell_1 is y7=2.5(x3)y - 7 = -2.5(x - 3), which simplifies to y=2.5x+14.5y = -2.5x + 14.5. Line 3\ell_3 is parallel to 1\ell_1, so m3=2.5m_3 = -2.5, and its yy-intercept is 14.5+6=20.514.5 + 6 = 20.5. Writing the equation for line 3\ell_3 as y=2.5x+20.5y = -2.5x + 20.5 and setting y=0y = 0 gives 0=2.5a+20.5    2.5a=20.5    a=8.20 = -2.5a + 20.5 \implies 2.5a = 20.5 \implies a = 8.2.

Adım Adım Çözüm

1
Determine the slope of line 2\ell_2
The slope of line 2\ell_2 is 25\frac{2}{5}.
Convert 2x5y=102x - 5y = 10 into slope-intercept form y=25x2y = \frac{2}{5}x - 2.
2
Determine the slope of line 1\ell_1
The slope of line 1\ell_1 is 52-\frac{5}{2}.
Perpendicular lines have slopes that are negative reciprocals of each other.
3
Find the yy-intercept of line 1\ell_1
The yy-intercept of 1\ell_1 is 292=14.5\frac{29}{2} = 14.5.
Apply point-slope form with point (3,7)(3, 7): y7=52(x3)    y=52x+292y - 7 = -\frac{5}{2}(x - 3) \implies y = -\frac{5}{2}x + \frac{29}{2}.
4
Construct the equation for line 3\ell_3
The equation of 3\ell_3 is y=52x+412y = -\frac{5}{2}x + \frac{41}{2}.
Line 3\ell_3 has the same slope as 1\ell_1 (52-\frac{5}{2}) and its yy-intercept is 14.5+6=20.5=41214.5 + 6 = 20.5 = \frac{41}{2}.
5
Calculate the xx-intercept coordinate aa of line 3\ell_3
a=8.2a = 8.2.
Substitute y=0y = 0 into the equation for 3\ell_3: 0=52a+412    5a=41    a=8.20 = -\frac{5}{2}a + \frac{41}{2} \implies 5a = 41 \implies a = 8.2.

Anahtar Kavram

Perpendicular and parallel slopes, point-slope equation derivation, line transformations, and intercept determination.
Tahmini Süre:2m 30s
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