Soru

Zorluk: KolayEven-Odd Properties and Sign Rules

If xx is an odd integer and yy is an even integer, which of the following expressions must result in an even integer? Select all that apply.

  1. A
    xy+xxy + x
  2. xy+yxy + yCevap
  3. (x+1)(y+1)(x + 1)(y + 1)Cevap
  4. D
    x2+yx^2 + y
  5. E
    x(y+3)x(y + 3)

Cevap

The expressions that must be even are xy+yxy + y and (x+1)(y+1)(x + 1)(y + 1).
The expression xy+yxy + y is guaranteed to be even because xyxy is even (product of odd and even) and adding another even integer yy produces an even sum. The expression (x+1)(y+1)(x + 1)(y + 1) is also guaranteed to be even because adding 1 to an odd integer xx creates an even integer x+1x + 1, and multiplying an even number by any integer always yields an even product.

Adım Adım Çözüm

1
Analyze fundamental parity rules for addition and multiplication of integers.
Recall that odd×even=even\text{odd} \times \text{even} = \text{even}, odd×odd=odd\text{odd} \times \text{odd} = \text{odd}, even+even=even\text{even} + \text{even} = \text{even}, and odd+even=odd\text{odd} + \text{even} = \text{odd}.
Parity rules govern the even/odd behavior of combined expressions.
2
Evaluate the expression xy+yxy + y.
Since xx is odd and yy is even, xyxy is even. Then even+y(even)=even\text{even} + y\,(\text{even}) = \text{even}.
Adding two even terms always results in an even number.
3
Evaluate the expression (x+1)(y+1)(x + 1)(y + 1).
Since xx is odd, x+1x + 1 is even. The product of an even integer and any integer (y+1y + 1) is always even.
An even factor guarantees an even product.

Anahtar Kavram

Even and Odd Parity Rules under Arithmetic Operations
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