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Zorluk: OrtaEstimation, Rounding, and Sequences

A sequence of 40 numbers a1,a2,,a40a_1, a_2, \dots, a_{40} is defined by the formula ak=15+3k8a_k = 15 + \frac{3k}{8} for each integer kk from 1 to 40. Each term aka_k is rounded to the nearest integer to form a new sequence b1,b2,,b40b_1, b_2, \dots, b_{40}. (Note: numbers ending in .5.5 are rounded up to the next integer.) What is the value of k=140bkk=140ak\sum_{k=1}^{40} b_k - \sum_{k=1}^{40} a_k?

  1. 2.52.5Cevap
  2. B
    0.00.0
  3. C
    5.05.0
  4. D
    2.5-2.5
  5. E
    1.01.0

Cevap

The sum of the rounded sequence exceeds the sum of the exact sequence by 2.52.5.
Evaluating ak=15+3k8a_k = 15 + \frac{3k}{8} for k=1,2,,8k = 1, 2, \dots, 8 yields fractional parts of 0.375,0.75,0.125,0.5,0.875,0.25,0.625,0.375, 0.75, 0.125, 0.5, 0.875, 0.25, 0.625, and 0.00.0. The individual rounding errors (bkak)(b_k - a_k) for these terms are 0.375,+0.25,0.125,+0.5,+0.125,0.25,+0.375,-0.375, +0.25, -0.125, +0.5, +0.125, -0.25, +0.375, and 0.00.0. Summing these errors yields +0.5+0.5 per 8-term period. For 40 terms (5 full periods), the total error sum is 5×0.5=2.55 \times 0.5 = 2.5.

Adım Adım Çözüm

1
Analyze the fractional part of ak=15+3k8a_k = 15 + \frac{3k}{8} over one complete 8-term period.
The fractional parts for k=1,2,,8k = 1, 2, \dots, 8 are 0.375,0.75,0.125,0.5,0.875,0.25,0.625,0.00.375, 0.75, 0.125, 0.5, 0.875, 0.25, 0.625, 0.0 respectively.
Since 3k8\frac{3k}{8} repeats its fractional pattern modulo 8, examining one period reveals the periodic rounding behavior.
2
Calculate the rounding error (bkak)(b_k - a_k) for each term in the 8-term cycle.
The differences (bkak)(b_k - a_k) for k=1k=1 to 88 are: 0.375,+0.25,0.125,+0.5,+0.125,0.25,+0.375,0.0-0.375, +0.25, -0.125, +0.5, +0.125, -0.25, +0.375, 0.0.
Rounding to the nearest integer shifts each number by its distance to that integer. Half-integers like 0.50.5 round up, yielding a +0.5+0.5 difference.
3
Sum the rounding errors over one 8-term cycle.
(0.375+0.375)+(0.250.25)+(0.125+0.125)+0.5+0.0=+0.5(-0.375 + 0.375) + (0.25 - 0.25) + (-0.125 + 0.125) + 0.5 + 0.0 = +0.5.
Symmetric fractional pairs cancel out, leaving only the +0.5+0.5 error from the half-integer term.
4
Multiply the single-cycle error sum by the number of full cycles in 40 terms.
Since 40=5×840 = 5 \times 8, total difference =5×0.5=2.5= 5 \times 0.5 = 2.5.
The 40 terms consist of 5 identical 8-term periodic cycles.

Anahtar Kavram

Periodic error analysis in sequence rounding and summation
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