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Zorluk: OrtaMeasures of Central Tendency (Mean, Median, Mode)

A university department tracked the number of research articles published by its 8 faculty members over a five-year period. The numbers of publications for 7 of the faculty members were 4,7,9,12,15,18,4, 7, 9, 12, 15, 18, and 2323. If the arithmetic mean of the number of publications for all 8 faculty members is equal to 1.251.25 times their median, what is the number of publications for the 8th faculty member?

Cevap: 47 publications

Cevap

47
The sum of the 7 known values is 8888, making the total sum 88+x88 + x and the arithmetic mean 88+x8\frac{88 + x}{8}. Assuming x15x \ge 15, the 4th and 5th numbers when sorted are 1212 and 1515, yielding a median of 13.513.5. Setting the mean equal to 1.25×13.5=16.8751.25 \times 13.5 = 16.875 gives 88+x8=16.875\frac{88 + x}{8} = 16.875, which simplifies to 88+x=13588 + x = 135 and yields x=47x = 47.

Adım Adım Çözüm

1
Calculate the sum of the 7 known data points and express the mean in terms of the unknown 8th value xx.
Sum of 7 known values = 4+7+9+12+15+18+23=884 + 7 + 9 + 12 + 15 + 18 + 23 = 88. Total mean = 88+x8\frac{88 + x}{8}.
The arithmetic mean of nn values is the sum of all values divided by nn.
2
Analyze the position of xx in sorted order to determine the median.
Assuming x15x \ge 15, the 4th and 5th values in ascending order are 1212 and 1515, giving a median of 12+152=13.5\frac{12 + 15}{2} = 13.5.
For an even number of data points (88), the median is the average of the 4th and 5th terms in sorted order.
3
Formulate and solve the equation linking the mean and median.
88+x8=1.25×13.5=16.875    88+x=135    x=47\frac{88 + x}{8} = 1.25 \times 13.5 = 16.875 \implies 88 + x = 135 \implies x = 47.
The problem specifies that the mean is equal to 1.251.25 times the median.

Anahtar Kavram

Calculating mean and median of a dataset containing an unknown value.
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