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Zorluk: KolaySimplifying and Factoring Algebraic Expressions

For all real numbers xx such that x3x \neq -3, which of the following expressions is equivalent to 2x2184x+12\frac{2x^2 - 18}{4x + 12}?

  1. x32\frac{x - 3}{2}Cevap
  2. B
    x+32\frac{x + 3}{2}
  3. C
    (x3)22(x+3)\frac{(x - 3)^2}{2(x + 3)}
  4. D
    2x34\frac{2x - 3}{4}
  5. E
    x92\frac{x - 9}{2}

Cevap

The expression x32\frac{x - 3}{2} is equivalent to the given rational expression.
Factoring the numerator gives 2(x29)=2(x3)(x+3)2(x^2 - 9) = 2(x - 3)(x + 3) and factoring the denominator gives 4(x+3)4(x + 3). Canceling the non-zero common terms 2(x+3)2(x + 3) leaves x32\frac{x - 3}{2}.

Adım Adım Çözüm

1
Factor out the greatest common factor from the numerator and denominator.
Numerator: 2x218=2(x29)2x^2 - 18 = 2(x^2 - 9); Denominator: 4x+12=4(x+3)4x + 12 = 4(x + 3).
Factoring out common numerical coefficients simplifies the expression and reveals algebraic patterns.
2
Apply the difference of squares formula to factor x29x^2 - 9.
x29=(x3)(x+3)x^2 - 9 = (x - 3)(x + 3), so the numerator becomes 2(x3)(x+3)2(x - 3)(x + 3).
The algebraic identity a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b) allows complete factoring of the numerator.
3
Cancel common factors shared by the numerator and denominator.
\frac{2(x - 3)(x + 3)}{4(x + 3)} = \frac{2(x - 3)}{4} = \frac{x - 3}{2}.
Since x3x \neq -3, the factor (x+3)(x + 3) is non-zero and can be safely canceled along with reducing the constant ratio 24\frac{2}{4} to 12\frac{1}{2}.

Anahtar Kavram

Simplifying rational algebraic expressions by factoring common numerical factors and applying the difference of squares identity.
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