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Zorluk: OrtaLinear Equations in One Variable

If xx is the solution to the linear equation 4x33x+24=5x6\frac{4x - 3}{3} - \frac{x + 2}{4} = \frac{5x}{6}, which of the following statements about xx must be true? Select all such statements.

  1. xx is a multiple of 3Cevap
  2. 2x5>62x - 5 > 6Cevap
  3. x25x=6x^2 - 5x = 6Cevap
  4. D
    xx is a prime number
  5. E
    x<5x < 5

Cevap

The statements establishing that xx is a multiple of 3, that 2x5>62x - 5 > 6, and that x25x=6x^2 - 5x = 6 are all true.
Solving the linear equation yields x=6x = 6. Substituting x=6x = 6 into each statement shows that xx is a multiple of 3 (6=3×26 = 3 \times 2), 2x5>62x - 5 > 6 evaluates to 7>67 > 6, and x25x=6x^2 - 5x = 6 evaluates to 3630=636 - 30 = 6. All three statements are correct.

Adım Adım Çözüm

1
Clear denominators by multiplying both sides by the least common multiple.
12(4x33x+24)=12(5x6)    4(4x3)3(x+2)=2(5x)12 \cdot \left(\frac{4x - 3}{3} - \frac{x + 2}{4}\right) = 12 \cdot \left(\frac{5x}{6}\right) \implies 4(4x - 3) - 3(x + 2) = 2(5x)
The least common multiple of 3, 4, and 6 is 12.
2
Distribute factors and combine like terms.
16x123x6=10x    13x18=10x16x - 12 - 3x - 6 = 10x \implies 13x - 18 = 10x
Distributing 3-3 into (x+2)(x + 2) yields 3x6-3x - 6.
3
Isolate xx on one side of the equation.
13x10x=18    3x=18    x=613x - 10x = 18 \implies 3x = 18 \implies x = 6
Subtract 10x10x and add 18 to isolate the variable term.
4
Evaluate each given statement using x=6x = 6.
Statement 1: 66 is a multiple of 3 (True). Statement 2: 2(6)5=7>62(6) - 5 = 7 > 6 (True). Statement 3: 625(6)=66^2 - 5(6) = 6 (True). Statement 4: 6 is prime (False). Statement 5: 6<56 < 5 (False).
Test each option against the calculated solution x=6x = 6.

Anahtar Kavram

Linear Equations in One Variable
Tahmini Süre:1m 30s
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