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Zorluk: ZorPythagorean Theorem and Special Right Triangles

In the xyxy-coordinate plane, point AA has coordinates (9,0)(-9, 0) and point CC has coordinates (0,12)(0, 12). Point BB lies on the positive xx-axis such that line segment BDBD is perpendicular to segment ACAC, with point DD lying on segment ACAC. If the area of right triangle ABDABD is 5454, what is the length of segment OBOB, where OO is the origin (0,0)(0,0)?

Cevap: 6

Cevap

The length of segment OBOB is 66.
The length of segment OBOB is 66. Using the Pythagorean theorem on AOC\triangle AOC, hypotenuse AC=15AC = 15, establishing a 3:4:53:4:5 side ratio for AOC\triangle AOC. Because ABD\triangle ABD shares acute angle A\angle A with AOC\triangle AOC and has a right angle at DD, ABD\triangle ABD is also a 3:4:53:4:5 right triangle with hypotenuse ABAB. Expressing the area 12×(35AB)×(45AB)=54\frac{1}{2} \times \left(\frac{3}{5}AB\right) \times \left(\frac{4}{5}AB\right) = 54 yields AB=15AB = 15. Since AA is at (9,0)(-9,0), point BB is at (6,0)(6,0), making OB=6OB = 6.

Adım Adım Çözüm

1
Find the side lengths and hypotenuse of right triangle AOCAOC.
Leg AO=9AO = 9, leg OC=12OC = 12, and by the Pythagorean theorem, hypotenuse AC=92+122=81+144=225=15AC = \sqrt{9^2 + 12^2} = \sqrt{81 + 144} = \sqrt{225} = 15.
The coordinates of A(9,0)A(-9,0) and C(0,12)C(0,12) form a right triangle at the origin O(0,0)O(0,0).
2
Use angle similarity to determine the side ratio of right triangle ABDABD.
Triangle ABDABD is similar to triangle AOCAOC because both contain a right angle and share DAO\angle DAO. Thus, the sides of ABD\triangle ABD maintain the ratio AD:BD:AB=3:4:5AD : BD : AB = 3 : 4 : 5.
Right triangles with a shared acute angle are similar.
3
Express legs ADAD and BDBD in terms of hypotenuse ABAB and set up the area equation.
AD=35ABAD = \frac{3}{5}AB and BD=45ABBD = \frac{4}{5}AB. The area of ABD=12×AD×BD=12×35AB×45AB=625AB2\triangle ABD = \frac{1}{2} \times AD \times BD = \frac{1}{2} \times \frac{3}{5}AB \times \frac{4}{5}AB = \frac{6}{25}AB^2. Setting 625AB2=54\frac{6}{25}AB^2 = 54 yields AB2=225AB^2 = 225, so AB=15AB = 15.
The area of a right triangle is half the product of its perpendicular legs.
4
Calculate the length of segment OBOB.
Since point AA is at (9,0)(-9,0) and BB lies on the positive xx-axis, AB=xB(9)=15    xB=6AB = x_B - (-9) = 15 \implies x_B = 6. Therefore, the length of OBOB is 66.
The distance from the origin (0,0)(0,0) to (6,0)(6,0) on the xx-axis is equal to the xx-coordinate 66.

Anahtar Kavram

Applying Pythagorean triples (3-4-5 right triangle family) and similar right triangles in coordinate geometry.
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