Soru

Zorluk: ZorMeasures of Dispersion and Position (Range, IQR, Standard Deviation, Percentiles)

A quality control engineer records the thickness, in millimeters, of 9 sample components: 11,13,15,17,19,21,23,25,11, 13, 15, 17, 19, 21, 23, 25, and 2727. Each thickness measurement xx is then converted to a scaled rating yy using the linear formula y=1.5x+4.8y = 1.5x + 4.8. What is the interquartile range (IQR) of the transformed dataset of yy-values?

Cevap: 15

Cevap

The interquartile range of the transformed dataset is 15.
The interquartile range (IQR) measures the spread of the middle 50% of the data (Q3Q1Q_3 - Q_1). For the original dataset 11,13,15,17,19,21,23,25,2711, 13, 15, 17, 19, 21, 23, 25, 27, the median is 1919. Q1Q_1 is the median of the lower half {11,13,15,17}\{11, 13, 15, 17\}, which is 13+152=14\frac{13+15}{2} = 14. Q3Q_3 is the median of the upper half {21,23,25,27}\{21, 23, 25, 27\}, which is 23+252=24\frac{23+25}{2} = 24. Thus, the original IQR=2414=10\text{IQR} = 24 - 14 = 10. Under a linear transformation y=ax+by = ax + b, measures of position shift by ax+ba x + b, so Q1(y)=1.5(14)+4.8=25.8Q_1(y) = 1.5(14) + 4.8 = 25.8 and Q3(y)=1.5(24)+4.8=40.8Q_3(y) = 1.5(24) + 4.8 = 40.8. Subtracting these yields IQR(y)=40.825.8=15\text{IQR}(y) = 40.8 - 25.8 = 15. Notice that this is simply 1.5×101.5 \times 10, as adding a constant shifts the location of the distribution but leaves measures of spread unchanged.

Adım Adım Çözüm

1
Find the quartiles of the original 9-element dataset.
Q1=14Q_1 = 14 and Q3=24Q_3 = 24
The median of the dataset is 19 (the 5th value). The lower half of the data consists of 11,13,15,1711, 13, 15, 17, so Q1=13+152=14Q_1 = \frac{13 + 15}{2} = 14. The upper half consists of 21,23,25,2721, 23, 25, 27, so Q3=23+252=24Q_3 = \frac{23 + 25}{2} = 24.
2
Calculate the interquartile range of the original dataset.
IQRx=10\text{IQR}_x = 10
IQRx=Q3Q1=2414=10\text{IQR}_x = Q_3 - Q_1 = 24 - 14 = 10.
3
Apply the linear transformation rules to find the transformed interquartile range.
IQRy=15\text{IQR}_y = 15
For a linear transformation y=ax+by = ax + b, the interquartile range scales by a|a|, so IQRy=aIQRx=1.5×10=15\text{IQR}_y = |a| \cdot \text{IQR}_x = 1.5 \times 10 = 15. The constant addition of 4.84.8 shifts all values equally and does not affect the spread/IQR.

Anahtar Kavram

Effect of linear transformations on measures of dispersion (IQR, standard deviation, range)

Alternatif Yöntem

Transform the individual quartiles directly: Q1(y)=1.5(14)+4.8=25.8Q_1(y) = 1.5(14) + 4.8 = 25.8 and Q3(y)=1.5(24)+4.8=40.8Q_3(y) = 1.5(24) + 4.8 = 40.8. Then calculate the new IQR directly as 40.825.8=1540.8 - 25.8 = 15.
Tahmini Süre:1m 30s
Bu soruyu puanla