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Zorluk: OrtaPrime Factorization, GCD, and LCM

A positive integer nn has the prime factorization n=2a3b5cn = 2^a \cdot 3^b \cdot 5^c, where aa, bb, and cc are positive integers. If nn is divisible by 3636 and is a divisor of 54005{}400, which of the following values could be the total number of positive divisors of nn? Select all such values.

  1. 18Cevap
  2. B
    20
  3. 27Cevap
  4. 32Cevap
  5. E
    40

Cevap

18, 27, and 32 are all possible total numbers of positive divisors for nn.
Prime factorization gives 36=223236 = 2^2 \cdot 3^2 and 5400=2333525{}400 = 2^3 \cdot 3^3 \cdot 5^2. For n=2a3b5cn = 2^a \cdot 3^b \cdot 5^c to be a multiple of 36 and a divisor of 5,400 with positive integer exponents, a{2,3}a \in \{2,3\}, b{2,3}b \in \{2,3\}, and c{1,2}c \in \{1,2\}. The total number of divisors is (a+1)(b+1)(c+1)(a+1)(b+1)(c+1). The possible values for this product are 18, 24, 27, 32, 36, and 48. Among the choices, 18, 27, and 32 are valid values.

Adım Adım Çözüm

1
Find the prime factorizations of the boundary numbers 36 and 5,400.
36=223236 = 2^2 \cdot 3^2 and 5400=2333525{}400 = 2^3 \cdot 3^3 \cdot 5^2.
Establishing the prime factor bounds determines the range of possible values for exponents aa, bb, and cc.
2
Determine the constraints on exponents aa, bb, and cc.
Since 36n36 \mid n, a2a \ge 2, b2b \ge 2, and c1c \ge 1 (given cc is a positive integer). Since n5400n \mid 5{}400, a3a \le 3, b3b \le 3, and c2c \le 2. Thus, a{2,3}a \in \{2, 3\}, b{2,3}b \in \{2, 3\}, and c{1,2}c \in \{1, 2\}.
Divisibility rules require prime factor exponents of a multiple to be greater than or equal to those of the divisor, and exponents of a divisor to be less than or equal to those of the multiple.
3
Calculate all possible total divisor counts using the formula d(n)=(a+1)(b+1)(c+1)d(n) = (a+1)(b+1)(c+1).
Possible factor values are (a+1){3,4}(a+1) \in \{3, 4\}, (b+1){3,4}(b+1) \in \{3, 4\}, and (c+1){2,3}(c+1) \in \{2, 3\}. Evaluating all combinations yields: 332=183 \cdot 3 \cdot 2 = 18, 333=273 \cdot 3 \cdot 3 = 27, 342=243 \cdot 4 \cdot 2 = 24, 343=363 \cdot 4 \cdot 3 = 36, 442=324 \cdot 4 \cdot 2 = 32, and 443=484 \cdot 4 \cdot 3 = 48.
The total number of positive integer divisors is found by adding 1 to each exponent in the prime factorization and multiplying the results.
4
Compare the calculated divisor counts with the options provided.
The values 18, 27, and 32 appear in the calculated set of possible total divisors.
Direct matching identifies all valid options.

Anahtar Kavram

Prime factor exponent bounds and total number of positive divisors formula
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