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Zorluk: ZorCircles, Arc Lengths, and Sector Areas

In circle OO, points PP and QQ lie on the circumference such that the ratio of the minor arc length PQPQ to the radius rr of the circle is 5π6\frac{5\pi}{6}. If the area of sector POQPOQ is 30π30\pi, what is the total perimeter of sector POQPOQ?

  1. 122+52π12\sqrt{2} + 5\sqrt{2}\piCevap
  2. B
    12+5π12 + 5\pi
  3. C
    52π5\sqrt{2}\pi
  4. D
    12+10π12 + 10\pi
  5. E
    122+122π12\sqrt{2} + 12\sqrt{2}\pi

Cevap

122+52π12\sqrt{2} + 5\sqrt{2}\pi
The central angle θ\theta in radians is equal to the ratio of minor arc length to radius, so θ=5π6\theta = \frac{5\pi}{6}. Using the area of a sector formula A=12r2θA = \frac{1}{2}r^2\theta, we substitute A=30πA = 30\pi to get 12r2(5π6)=30π\frac{1}{2}r^2\left(\frac{5\pi}{6}\right) = 30\pi, which simplifies to r2=72r^2 = 72, or r=62r = 6\sqrt{2}. The arc length is then s=rθ=(62)(5π6)=52πs = r\theta = (6\sqrt{2})\left(\frac{5\pi}{6}\right) = 5\sqrt{2}\pi. The total perimeter of the sector includes both bounding radii and the arc length: 2r+s=122+52π2r + s = 12\sqrt{2} + 5\sqrt{2}\pi.

Adım Adım Çözüm

1
Relate the central angle in radians to the given ratio of arc length to radius.
The central angle θ\theta in radians is given by θ=arc lengthr=5π6\theta = \frac{\text{arc length}}{r} = \frac{5\pi}{6}.
By definition of radian measure, arc length s=rθs = r\theta, so sr=θ\frac{s}{r} = \theta.
2
Use the sector area formula to solve for the radius rr.
Setting 12r2(5π6)=30π\frac{1}{2}r^2\left(\frac{5\pi}{6}\right) = 30\pi yields 5π12r2=30π    r2=72    r=62\frac{5\pi}{12}r^2 = 30\pi \implies r^2 = 72 \implies r = 6\sqrt{2}.
The area of a sector with central angle θ\theta (in radians) is A=12r2θA = \frac{1}{2}r^2\theta.
3
Calculate the minor arc length ss.
Arc length s=rθ=(62)(5π6)=52πs = r\theta = (6\sqrt{2})\left(\frac{5\pi}{6}\right) = 5\sqrt{2}\pi.
Multiplying the radius by the central angle in radians gives the length of the subtended arc.
4
Calculate the total perimeter of sector POQPOQ.
Perimeter =2r+s=2(62)+52π=122+52π= 2r + s = 2(6\sqrt{2}) + 5\sqrt{2}\pi = 12\sqrt{2} + 5\sqrt{2}\pi.
The perimeter of a sector consists of the two bounding radii plus the arc length.

Anahtar Kavram

Relationship between radian measure, sector area, arc length, and sector perimeter
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