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Zorluk: OrtaTrigonometric Ratios and Identities

In right triangle ABCABC, the measure of angle BB is 9090^\circ. The acute angles AA and CC satisfy sin(A)=k3\sin(A) = \frac{k}{3} and cos(C)=4k+4\cos(C) = \frac{4}{k+4} for some positive constant kk. What is the value of kk?

  1. A
    6
  2. B
    8
  3. 2Cevap
  4. D
    12

Cevap

2
In right triangle ABCABC, the measure of angle BB is 9090^\circ, which means the acute angles AA and CC are complementary. Therefore, the co-function identity states that sin(A)=cos(C)\sin(A) = \cos(C). Equating the given expressions yields k3=4k+4\frac{k}{3} = \frac{4}{k+4}. Cross-multiplying results in k(k+4)=12k(k+4) = 12, which simplifies to k2+4k12=0k^2 + 4k - 12 = 0. Factoring this equation gives (k+6)(k2)=0(k+6)(k-2) = 0. This quadratic has solutions k=6k = -6 and k=2k = 2. Since kk must be positive, the value of kk is 22.

Adım Adım Çözüm

1
Identify the relationship between the acute angles in a right triangle.
Since the measure of angle BB is 9090^\circ, the sum of angles AA and CC is 9090^\circ, which means they are complementary angles. By the co-function identity, sin(A)=cos(C)\sin(A) = \cos(C).
In a right triangle, the sine of one acute angle equals the cosine of the other acute angle.
2
Equate the expressions for sin(A)\sin(A) and cos(C)\cos(C) and set up the equation for kk.
k3=4k+4\frac{k}{3} = \frac{4}{k+4}
This sets up the algebraic relation to solve for kk using the given trigonometric expressions.
3
Solve the algebraic equation for kk.
Cross-multiplying gives k(k+4)=12k(k+4) = 12, which expands to k2+4k=12k^2 + 4k = 12. Subtracting 1212 from both sides results in the quadratic equation k2+4k12=0k^2 + 4k - 12 = 0. Factoring this equation yields (k+6)(k2)=0(k+6)(k-2) = 0.
Cross-multiplication eliminates the denominators, converting the equation to a quadratic form that can be solved by factoring.
4
Determine the valid positive value for kk.
The solutions to the equation (k+6)(k2)=0(k+6)(k-2) = 0 are k=6k = -6 and k=2k = 2. Since kk must be a positive constant, we select k=2k = 2.
The problem specifies that kk is a positive constant, so the negative solution is discarded.

Anahtar Kavram

Co-function identity relating sine and cosine of complementary angles
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