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Zorluk: OrtaInterpreting Linear Relationships in Context

A commercial bakery uses an automated flour silo. The mass of the flour in the silo, FF, in kilograms, is modeled as a linear function of the time tt, in hours, after the bakery opens. The table below shows the mass of the flour remaining in the silo at two different times during the day:

Time (hours), ttMass of flour (kilograms), FF
331,8501,850
771,4901,490

If the mass of the flour in the silo decreases at a constant rate of rr kilograms per hour, what is the value of rr?

Cevap: 90 kilograms per hour

Cevap

90
The rate of decrease of the flour is represented by the magnitude of the slope of the linear relationship. Using the points (3,1850)(3, 1850) and (7,1490)(7, 1490) from the table, the slope is calculated as 1490185073=3604=90\frac{1490 - 1850}{7 - 3} = \frac{-360}{4} = -90. This indicates that the mass of the flour decreases by 9090 kilograms per hour. Therefore, the value of rr is 9090.

Adım Adım Çözüm

1
Identify the data points representing time and mass from the table.
(t1,F1)=(3,1850)(t_1, F_1) = (3, 1850) and (t2,F2)=(7,1490)(t_2, F_2) = (7, 1490)
We need two coordinates to find the slope of the linear relationship.
2
Calculate the slope (rate of change) of the linear function.
Slope = 1490185073=90\frac{1490 - 1850}{7 - 3} = -90
The slope formula y2y1x2x1\frac{y_2 - y_1}{x_2 - x_1} gives the rate of change of the mass of the flour per hour.
3
Determine the value of rr based on the rate of decrease.
r=90r = 90
The rate of decrease is the positive magnitude of the rate of change.

Anahtar Kavram

Interpreting rate of change (slope) from tabular data in a linear context
Tahmini Süre:1m 30s
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