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Zorluk: OrtaQuadratic Functions and Graphs

The graph of the quadratic equation y=2x212x+cy = 2x^2 - 12x + c, where cc is a constant, is a parabola in the xyxy-plane. If the yy-coordinate of the vertex of this parabola is 5-5, what is the value of cc?

Cevap: 13

Cevap

13
To find the value of the constant cc, we calculate the coordinates of the vertex of the parabola. The x-coordinate of the vertex for a quadratic function in standard form y=ax2+bx+cy = ax^2 + bx + c is given by x=b2ax = -\frac{b}{2a}. Substituting a=2a = 2 and b=12b = -12 gives x=122(2)=3x = -\frac{-12}{2(2)} = 3. Evaluating the quadratic equation at x=3x = 3 gives the y-coordinate of the vertex: y=2(3)212(3)+c=1836+c=c18y = 2(3)^2 - 12(3) + c = 18 - 36 + c = c - 18. Since we are given that the y-coordinate of the vertex is 5-5, we set c18=5c - 18 = -5 and solve to find c=13c = 13.

Adım Adım Çözüm

1
Calculate the x-coordinate of the vertex using the vertex formula.
x=3x = 3
The axis of symmetry and the x-coordinate of the vertex are located at x=b2ax = -\frac{b}{2a}.
2
Substitute the x-coordinate of the vertex into the equation to express the y-coordinate in terms of cc.
y=c18y = c - 18
Evaluating the quadratic function at the vertex's x-coordinate gives the minimum or maximum value of the function.
3
Equate the expression for the y-coordinate to the given vertex y-coordinate of 5-5 and solve for cc.
c=13c = 13
Setting the calculated y-coordinate expression equal to the given value allows us to isolate and solve for the unknown constant.

Anahtar Kavram

Determining the vertex of a quadratic function from its standard form and solving for a constant coefficient.

Alternatif Yöntem

Alternatively, we can complete the square to write the quadratic equation in vertex form, y=a(xh)2+ky = a(x-h)^2 + k. Factoring the leading coefficient from the variable terms gives y=2(x26x)+cy = 2(x^2 - 6x) + c. To complete the square inside the parentheses, add and subtract 99: y=2(x26x+99)+c=2((x3)29)+c=2(x3)218+cy = 2(x^2 - 6x + 9 - 9) + c = 2((x-3)^2 - 9) + c = 2(x-3)^2 - 18 + c. In this vertex form, the y-coordinate of the vertex is k=c18k = c - 18. Since the vertex y-coordinate is 5-5, we set c18=5c - 18 = -5 to get c=13c = 13.
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