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Zorluk: ZorPolynomial Factors and Graphs

The function ff is defined by f(x)=x33x210x+kf(x) = x^3 - 3x^2 - 10x + k, where kk is a constant. In the xyxy-plane, the graph of y=f(x)y = f(x) has xx-intercepts at (c,0)(c, 0) and (2c,0)(2c, 0), where cc is a positive constant. What is the value of kk?

Cevap: 24

Cevap

24
By applying the factor theorem to the two xx-intercepts (c,0)(c,0) and (2c,0)(2c,0), we establish the system c33c210c+k=0c^3 - 3c^2 - 10c + k = 0 and 8c312c220c+k=08c^3 - 12c^2 - 20c + k = 0. Subtracting these equations yields 7c39c210c=07c^3 - 9c^2 - 10c = 0. Since c>0c > 0, dividing by cc gives 7c29c10=07c^2 - 9c - 10 = 0, which factors as (7c+5)(c2)=0(7c+5)(c-2)=0, yielding the positive solution c=2c=2. Substituting c=2c=2 back into the first equation gives 81220+k=08 - 12 - 20 + k = 0, which solves to k=24k = 24.

Adım Adım Çözüm

1
Set up equations for the roots cc and 2c2c using the factor theorem.
f(c)=c33c210c+k=0f(c) = c^3 - 3c^2 - 10c + k = 0 and f(2c)=8c312c220c+k=0f(2c) = 8c^3 - 12c^2 - 20c + k = 0
An xx-intercept at (r,0)(r, 0) means that rr is a root of the polynomial, so f(r)=0f(r) = 0.
2
Subtract the first equation from the second to eliminate the constant kk.
7c39c210c=07c^3 - 9c^2 - 10c = 0
Eliminating kk allows us to solve for the root cc directly.
3
Solve the polynomial equation for the positive constant cc.
c=2c = 2
Dividing the equation by cc (since c>0c > 0) yields 7c29c10=07c^2 - 9c - 10 = 0, which factors as (7c+5)(c2)=0(7c+5)(c-2) = 0. Since cc must be positive, c=2c = 2.
4
Substitute c=2c = 2 back into the equation for f(c)=0f(c) = 0 to solve for kk.
k=24k = 24
Substituting the known root value allows us to find the value of the constant coefficient kk.

Anahtar Kavram

The relationship between a polynomial's algebraic factors, its roots, and its xx-intercepts in the coordinate plane.
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