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Zorluk: OrtaLinear Inequalities in One Variable

A science museum offers two ticketing options for groups. Option A is a flat group rate of 125plus125 plus 9.50 per person. Option B is a flat group rate of 50plus50 plus 12.50 per person. For a group of pp people, Option A is less expensive than Option B. What is the minimum number of people in the group for this to be true?

Cevap: 26 people

Cevap

The minimum number of people in the group is 26.
To find when Option A is less expensive than Option B, we set up the inequality representing their respective costs: 125+9.5p<50+12.5p125 + 9.5p < 50 + 12.5p. Subtracting 9.5p9.5p from both sides gives 125<50+3p125 < 50 + 3p. Subtracting 5050 from both sides yields 75<3p75 < 3p. Dividing by 33 gives p>25p > 25. Because the group must consist of a whole number of people, the minimum integer value of pp that is strictly greater than 2525 is 2626.

Adım Adım Çözüm

1
Write the inequality representing the cost comparison between the two ticketing options.
125+9.5p<50+12.5p125 + 9.5p < 50 + 12.5p
Option A's cost must be strictly less than Option B's cost for Option A to be less expensive.
2
Isolate the variable pp by subtracting 9.5p9.5p and 5050 from both sides of the inequality.
p>25p > 25
Subtracting 9.5p9.5p yields 125<50+3p125 < 50 + 3p. Subtracting 5050 yields 75<3p75 < 3p. Dividing by 33 yields p>25p > 25.
3
Identify the minimum integer value of pp that satisfies the inequality.
26
Since the number of people must be a positive integer, the smallest integer strictly greater than 2525 is 2626.

Anahtar Kavram

Solving linear inequalities in one variable and interpreting the solution set within a discrete real-world context.
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