Soru

Zorluk: KolayLinear Inequalities in One Variable

For which values of xx is the inequality 2−3(x+4)≥112 - 3(x + 4) \geq 11 true?

  1. x≤−7x \leq -7Cevap
  2. B
    x≥−7x \geq -7
  3. C
    x≤1x \leq 1
  4. D
    x≤−1x \leq -1

Cevap

The correct inequality is x≤−7x \leq -7.
Subtracting 2 from both sides of 2−3(x+4)≥112 - 3(x + 4) \geq 11 gives −3(x+4)≥9-3(x + 4) \geq 9. Dividing both sides by the negative number −3-3 requires reversing the inequality sign, yielding x+4≤−3x + 4 \leq -3. Subtracting 4 from both sides completes the isolation of xx, yielding the correct solution x≤−7x \leq -7.

Adım Adım Çözüm

1
Subtract 2 from both sides of the inequality.
−3(x+4)≥9-3(x + 4) \geq 9
This isolates the term containing the parentheses on one side of the inequality.
2
Divide both sides of the inequality by −3-3 and reverse the direction of the inequality sign.
x+4≤−3x + 4 \leq -3
Dividing an inequality by a negative number requires reversing the direction of the inequality symbol to maintain equivalence.
3
Subtract 4 from both sides of the inequality.
x≤−7x \leq -7
This isolates the variable xx on one side of the inequality, providing the final solution set.

Anahtar Kavram

Solving multi-step linear inequalities in one variable, including distributing negative constants and reversing the inequality direction when dividing by a negative number.
Bu soruyu puanla