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Zorluk: OrtaVolume and Surface Area of Solids

A rectangular box has a square base with side length xx inches and a height of 55 inches. The total surface area of the box is 192192 square inches. What is the value of xx?

Cevap: 6 inches

Cevap

The value of xx is 66.
The total surface area is found by adding the areas of all six faces. The top and bottom faces are squares with side length xx, so their combined area is 2x22x^2. The four vertical sides are rectangles with dimensions xx by 55, so their combined area is 4(5x)=20x4(5x) = 20x. Setting their sum equal to the total surface area gives 2x2+20x=1922x^2 + 20x = 192. Dividing by 22 yields x2+10x96=0x^2 + 10x - 96 = 0, which factors as (x+16)(x6)=0(x + 16)(x - 6) = 0. Since xx must be positive, x=6x = 6.

Adım Adım Çözüm

1
Set up the equation for the total surface area of the rectangular box.
Total Surface Area=2x2+20x=192\text{Total Surface Area} = 2x^2 + 20x = 192
The total surface area of a rectangular box with a square base of side length xx and height hh consists of two square bases (top and bottom) of area x2x^2 each, and four rectangular sides of area xhxh each. Substituting h=5h = 5 gives 2x2+4(5x)=2x2+20x2x^2 + 4(5x) = 2x^2 + 20x.
2
Simplify and set the quadratic equation to zero.
x2+10x96=0x^2 + 10x - 96 = 0
Dividing all terms by 22 simplifies the equation to x2+10x=96x^2 + 10x = 96. Subtracting 9696 from both sides sets the quadratic equation to standard form ax2+bx+c=0ax^2 + bx + c = 0.
3
Factor the quadratic equation and solve for the positive value of xx.
x=6x = 6
Factoring the equation gives (x+16)(x6)=0(x + 16)(x - 6) = 0, which yields solutions of x=16x = -16 and x=6x = 6. Since the side length of a geometric solid must be positive, we reject the negative solution.

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