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Zorluk: ZorLinear Functions and Graphs

In the xyxy-plane, the graph of the linear function ff is perpendicular to the line with equation y=2x7y = 2x - 7. If the region in the first quadrant bounded by the graph of ff, the xx-axis, and the yy-axis has an area of 3636, what is the xx-intercept of the graph of ff?

Cevap: 12

Cevap

The xx-intercept of the graph of ff is 1212.
The correct answer is 1212. Since the graph of ff is perpendicular to the line y=2x7y = 2x - 7, its slope is 12-\frac{1}{2}. The equation of the line is f(x)=12x+bf(x) = -\frac{1}{2}x + b, which has a yy-intercept of (0,b)(0, b) and an xx-intercept of (2b,0)(2b, 0). In the first quadrant, these intercepts form a right triangle with the axes, having legs of length bb and 2b2b. The area of this triangle is 12(2b)(b)=b2\frac{1}{2}(2b)(b) = b^2. Setting the area equal to 3636 gives b2=36b^2 = 36, so b=6b = 6 (since b>0b > 0). The xx-intercept is 2b=2(6)=122b = 2(6) = 12.

Adım Adım Çözüm

1
Find the slope of the perpendicular line ff.
The slope of ff is 12-\frac{1}{2}.
Perpendicular lines in the coordinate plane have slopes that are negative reciprocals of each other. The given line has a slope of 22, so the slope of ff must be 12-\frac{1}{2}.
2
Express the yy-intercept and xx-intercept of ff in terms of a single variable.
The yy-intercept is (0,b)(0, b) and the xx-intercept is (2b,0)(2b, 0), where b>0b > 0.
The equation of ff can be written as f(x)=12x+bf(x) = -\frac{1}{2}x + b. Setting x=0x = 0 gives the yy-intercept bb. Setting f(x)=0f(x) = 0 and solving for xx gives the xx-intercept 2b2b.
3
Set up the area equation for the triangle in the first quadrant.
The area is represented by b2=36b^2 = 36.
The region bounded by the graph of ff and the coordinate axes in the first quadrant forms a right triangle with perpendicular sides of lengths bb and 2b2b. The area of this triangle is 12×base×height=12×2b×b=b2\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 2b \times b = b^2.
4
Solve for bb and calculate the xx-intercept.
The xx-intercept is 1212.
Solving b2=36b^2 = 36 with the condition b>0b > 0 yields b=6b = 6. The xx-intercept is 2b2b, which equals 2(6)=122(6) = 12.

Anahtar Kavram

Using perpendicular slopes and intercepts of linear functions to analyze geometric areas in the coordinate plane.
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