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Zorluk: ZorData Distributions and Measures

A group of 2525 students took a history quiz, and their scores are summarized in the frequency table below.

ScoreFrequency
62
74
810
96
103

The teacher decides to remove the scores of the 22 students who scored 66 because they were absent on the day of the quiz and took it later under different conditions. Which of the following statements describes the effect of removing these two scores on the mean, median, and standard deviation of the quiz scores?

  1. The mean increases, the median remains unchanged, and the standard deviation decreases.Cevap
  2. B
    The mean increases, the median increases, and the standard deviation decreases.
  3. C
    The mean remains unchanged, the median remains unchanged, and the standard deviation increases.
  4. D
    The mean increases, the median remains unchanged, and the standard deviation increases.

Cevap

The mean increases, the median remains unchanged, and the standard deviation decreases.
The correct answer is the statement indicating that the mean increases, the median remains unchanged, and the standard deviation decreases. Removing the two lowest scores (66) eliminates the values that pull the average down, resulting in an increased mean. The median remains at 88 because the middle position of the sorted scores still lies within the class of 88 s. The standard deviation decreases because the overall spread of the data is reduced when the lowest and most distant values are removed.

Adım Adım Çözüm

1
Calculate the original mean and locate the original median.
Original Mean = 8.168.16; Original Median = 88.
The original sum of scores is (2×6)+(4×7)+(10×8)+(6×9)+(3×10)=204(2 \times 6) + (4 \times 7) + (10 \times 8) + (6 \times 9) + (3 \times 10) = 204. With 2525 students, the mean is 204/25=8.16204 / 25 = 8.16. The median is the 13th13\text{th} value in the sorted list of 2525 scores. Looking at the cumulative frequencies, the first 22 scores are 66, the next 44 are 77 (cumulative 66), and the next 1010 are 88 (cumulative 1616). Thus, the 13th13\text{th} value is 88.
2
Calculate the new mean and locate the new median after removing the two scores of 66.
New Mean 8.35\approx 8.35; New Median = 88.
Removing the two scores of 66 reduces the sum by 1212 (new sum = 192192) and the count of students to 2323. The new mean is 192/238.35192 / 23 \approx 8.35, which is an increase. The new median is the 12th12\text{th} value of the remaining 2323 sorted scores. The first 44 scores are 77, and the next 1010 are 88 (cumulative 1414). The 12th12\text{th} value is still 88, so the median remains unchanged.
3
Analyze the change in the standard deviation.
The standard deviation decreases.
Standard deviation measures the spread of the data. The scores of 66 are the minimum scores and are the furthest from the mean of the distribution. Removing these extreme values reduces the variability and concentrates the remaining scores closer to the mean, which decreases the standard deviation.

Anahtar Kavram

Analyzing the effects of removing extreme data values on the mean, median, and standard deviation of a dataset.
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