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Zorluk: OrtaLinear Equations in One Variable

If 35(2x4)12(x3)=65\frac{3}{5}(2x - 4) - \frac{1}{2}(x - 3) = \frac{6}{5}, what is the value of 5x45x - 4?

Cevap: 11

Cevap

11
Evaluating the linear equation by clearing the fractions with a common denominator of 10 gives 6(2x4)5(x3)=126(2x - 4) - 5(x - 3) = 12. Distributing terms yields 12x245x+15=1212x - 24 - 5x + 15 = 12. Combining like terms results in 7x9=127x - 9 = 12. Solving for xx gives x=3x = 3. Finally, substituting x=3x = 3 into the target expression 5x45x - 4 yields 5(3)4=115(3) - 4 = 11.

Adım Adım Çözüm

1
Multiply both sides of the equation by 10 to clear the denominators.
6(2x4)5(x3)=126(2x - 4) - 5(x - 3) = 12
The least common denominator of 5 and 2 is 10. Multiplying both sides by 10 simplifies the equation by removing the fractions.
2
Distribute the constants 6 and -5 into the parentheses.
12x245x+15=1212x - 24 - 5x + 15 = 12
Applying the distributive property removes the parentheses. Be careful to distribute the negative sign for the second term: 5(x3)=5x+15-5 \cdot (x - 3) = -5x + 15.
3
Combine like terms on the left side of the equation.
7x9=127x - 9 = 12
Grouping the xx terms (12x5x=7x12x - 5x = 7x) and the constant terms (24+15=9-24 + 15 = -9) simplifies the equation.
4
Isolate the variable term 7x7x and solve for xx.
x=3x = 3
Adding 9 to both sides gives 7x=217x = 21. Dividing both sides by 7 yields x=3x = 3.
5
Substitute the value of xx into the expression 5x45x - 4.
11
The question asks for the value of 5x45x - 4, not just xx, so we evaluate 5(3)4=115(3) - 4 = 11.

Anahtar Kavram

Solving linear equations in one variable by clearing fractions, distributing terms, and isolating the variable.
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