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Zorluk: OrtaInterpreting Linear Relationships in Context

A coffee roasting company uses a commercial roasting machine. The temperature of the roasting drum, TT, in degrees Fahrenheit (F^\circ\text{F}), is modeled as a linear function of the roasting time, tt, in minutes, where 0t100 \leq t \leq 10. After 22 minutes of roasting, the temperature of the drum is 280F280^\circ\text{F}. After 55 minutes of roasting, the temperature of the drum is 385F385^\circ\text{F}. What is the rate of temperature increase, in degrees Fahrenheit per minute, of the roasting drum?

Cevap: 35 degrees Fahrenheit per minute

Cevap

The rate of temperature increase of the roasting drum is 3535 degrees Fahrenheit per minute.
The temperature, TT, is modeled as a linear function of time, tt. The constant rate of temperature increase corresponds to the slope of this linear function. Given two points, (2,280)(2, 280) and (5,385)(5, 385), the slope is calculated as the change in temperature divided by the change in time: 38528052=1053=35\frac{385 - 280}{5 - 2} = \frac{105}{3} = 35 degrees Fahrenheit per minute.

Adım Adım Çözüm

1
Identify the coordinates representing the relationship between time and temperature.
The two points are (2,280)(2, 280) and (5,385)(5, 385), where the first coordinate is the time, tt, in minutes, and the second coordinate is the temperature, TT, in degrees Fahrenheit.
To find the rate of change of a linear relationship, we first need to determine two points (t1,T1)(t_1, T_1) and (t2,T2)(t_2, T_2) from the given context.
2
Calculate the rate of temperature increase as the slope of the line passing through these two points.
The slope mm is given by m=38528052=1053=35m = \frac{385 - 280}{5 - 2} = \frac{105}{3} = 35.
The rate of temperature increase per minute is the constant slope of the linear relationship.

Anahtar Kavram

Slope of a linear relationship in context
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