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Zorluk: OrtaLinear Functions and Graphs

In the xyxy-plane, the graph of a line ll passes through the points (0,1)(0, 1) and (3,5)(3, 5). If another point on line ll has coordinates (t,9)(t, 9), what is the value of tt?

Cevap: 6

Cevap

The value of tt is 66.
The slope of line ll is m=5130=43m = \frac{5 - 1}{3 - 0} = \frac{4}{3}. Using the y-intercept (0,1)(0, 1), the equation of the line is y=43x+1y = \frac{4}{3}x + 1. Setting y=9y = 9 gives 9=43t+19 = \frac{4}{3}t + 1. Subtracting 1 from both sides gives 8=43t8 = \frac{4}{3}t. Multiplying both sides by 34\frac{3}{4} yields t=6t = 6.

Adım Adım Çözüm

1
Calculate the slope of line ll using the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} with the points (0,1)(0, 1) and (3,5)(3, 5).
m=5130=43m = \frac{5 - 1}{3 - 0} = \frac{4}{3}
The slope of a line represents its constant rate of change and is needed to determine the line's equation.
2
Write the equation of the line in slope-intercept form, y=mx+by = mx + b, using the slope m=43m = \frac{4}{3} and the y-intercept b=1b = 1 (from the point (0,1)(0, 1)).
y=43x+1y = \frac{4}{3}x + 1
The slope-intercept equation defines the relationship between the xx- and yy-coordinates of any point on the line.
3
Substitute the point (t,9)(t, 9) into the line's equation and solve for tt.
9=43t+1    8=43t    t=69 = \frac{4}{3}t + 1 \implies 8 = \frac{4}{3}t \implies t = 6
Since the point lies on the line, its coordinates must satisfy the line's equation.

Anahtar Kavram

Determining the equation of a linear function from a graph or points and evaluating it for a given value.
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