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Zorluk: OrtaTwo-Way Tables and Probability

The table below shows the distribution of a group of 180180 commuters surveyed about their primary mode of transportation and their daily commuting distance.

Commuting DistancePublic TransitPersonal Vehicle
Under 10 miles4535
10 miles or more6040

Based on the table, if a commuter who primarily uses a personal vehicle is selected at random, what is the probability that this commuter has a daily commuting distance of under 10 miles?

  1. A
    736\frac{7}{36}
  2. B
    716\frac{7}{16}
  3. 715\frac{7}{15}Cevap
  4. D
    512\frac{5}{12}

Cevap

The probability that the selected commuter has a daily commuting distance of under 10 miles, given that they primarily use a personal vehicle, is 715\frac{7}{15}.
To find the probability that a commuter has a daily commuting distance of under 10 miles given that they primarily use a personal vehicle, we limit our sample space to only the commuters who use a personal vehicle. The total number of commuters who primarily use a personal vehicle is 35+40=7535 + 40 = 75. Within this group, the number of commuters with a daily commuting distance of under 10 miles is 35. Therefore, the probability is the fraction 3575\frac{35}{75}, which simplifies to 715\frac{7}{15}.

Adım Adım Çözüm

1
Identify the total number of commuters who satisfy the condition of primarily using a personal vehicle.
The total number of commuters who primarily use a personal vehicle is 35+40=7535 + 40 = 75.
This sum represents the total number of possible outcomes (the denominator) because the selection is restricted to this group.
2
Identify the number of commuters within that subset who have a daily commuting distance of under 10 miles.
The number of personal vehicle commuters with a daily commuting distance of under 10 miles is 35.
This represents the number of favorable outcomes (the numerator).
3
Divide the number of favorable outcomes by the total number of possible outcomes and simplify the resulting fraction.
The probability is 3575=715\frac{35}{75} = \frac{7}{15}.
Dividing the numerator and denominator by their greatest common divisor, 5, gives the simplified probability.

Anahtar Kavram

Calculating conditional probability from a two-way table by identifying the correct subset of the population to use as the denominator.
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