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Zorluk: OrtaPolynomial Factors and Graphs

For a cubic polynomial function pp, the graph of y=p(x)y = p(x) in the xyxy-plane has xx-intercepts at (1,0)(1, 0) and (4,0)(4, 0), and x+3x + 3 is a factor of p(x)p(x). If p(0)=−24p(0) = -24, what is the value of p(2)p(2)?

  1. A
    -10
  2. B
    4
  3. 20Cevap
  4. D
    -20

Cevap

20
The correct answer is 20. By translating the factor x+3x + 3 and the intercepts (1,0)(1, 0) and (4,0)(4, 0) into roots, the polynomial can be modeled as p(x)=a(x+3)(x−1)(x−4)p(x) = a(x + 3)(x - 1)(x - 4). Solving for the leading coefficient using p(0)=−24p(0) = -24 yields a=−2a = -2. Substituting x=2x = 2 into the resulting equation p(x)=−2(x+3)(x−1)(x−4)p(x) = -2(x + 3)(x - 1)(x - 4) gives p(2)=−2(5)(1)(−2)=20p(2) = -2(5)(1)(-2) = 20.

Adım Adım Çözüm

1
Identify the roots of the polynomial from the factors and intercepts.
The roots of p(x)p(x) are x=−3x = -3, x=1x = 1, and x=4x = 4.
A factor of x+3x + 3 corresponds to a root of −3-3. The xx-intercepts at (1,0)(1, 0) and (4,0)(4, 0) correspond to roots at 11 and 44.
2
Write the general factored form of the cubic polynomial.
p(x)=a(x+3)(x−1)(x−4)p(x) = a(x + 3)(x - 1)(x - 4)
A cubic polynomial with known roots r1,r2,r3r_1, r_2, r_3 can be expressed as p(x)=a(x−r1)(x−r2)(x−r3)p(x) = a(x-r_1)(x-r_2)(x-r_3).
3
Use the value p(0)=−24p(0) = -24 to find the constant coefficient aa.
a=−2a = -2
Substituting x=0x = 0 gives p(0)=a(0+3)(0−1)(0−4)=12ap(0) = a(0 + 3)(0 - 1)(0 - 4) = 12a. Since 12a=−2412a = -24, we solve to find a=−2a = -2.
4
Evaluate p(2)p(2) using the fully defined polynomial.
p(2)=20p(2) = 20
Substituting x=2x = 2 into p(x)=−2(x+3)(x−1)(x−4)p(x) = -2(x + 3)(x - 1)(x - 4) yields p(2)=−2(2+3)(2−1)(2−4)=−2(5)(1)(−2)=20p(2) = -2(2 + 3)(2 - 1)(2 - 4) = -2(5)(1)(-2) = 20.

Anahtar Kavram

Using polynomial roots, factors, and given coordinates to define and evaluate polynomial functions.
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