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Zorluk: KolayRadical and Rational Equations

If 4x+9=5\sqrt{4x + 9} = 5, what is the value of xx?

Cevap: 4

Cevap

4
Squaring both sides of the equation 4x+9=5\sqrt{4x + 9} = 5 yields 4x+9=254x + 9 = 25. Subtracting 9 from both sides gives 4x=164x = 16, and dividing by 4 yields x=4x = 4. Checking this solution in the original equation yields 4(4)+9=25=5\sqrt{4(4) + 9} = \sqrt{25} = 5, which confirms it is correct.

Adım Adım Çözüm

1
Square both sides of the equation
4x+9=254x + 9 = 25
To eliminate the square root on the left side of the equation.
2
Subtract 9 from both sides of the equation
4x=164x = 16
To isolate the variable term on the left side of the equation.
3
Divide both sides of the equation by 4
x=4x = 4
To solve for xx.
4
Substitute the solved value back into the original equation
4(4)+9=5    5=5\sqrt{4(4) + 9} = 5 \implies 5 = 5
To ensure the solution is valid and not extraneous.

Anahtar Kavram

Solving radical equations of the form ax+b=c\sqrt{ax + b} = c by squaring both sides.
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