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Zorluk: OrtaExponential Functions and Equations

If 4x=54^x = 5, what is the value of 24x12^{4x - 1}?

Cevap: 12.5

Cevap

12.5
By writing 4x4^x as (22)x=22x(2^2)^x = 2^{2x}, we find that 22x=52^{2x} = 5. The expression 24x12^{4x-1} can be rewritten using exponent properties as 24x21=(22x)22\frac{2^{4x}}{2^1} = \frac{(2^{2x})^2}{2}. Substituting 22x=52^{2x} = 5 into this expression yields 522=252=12.5\frac{5^2}{2} = \frac{25}{2} = 12.5. Thus, the correct numerical response is 12.5.

Adım Adım Çözüm

1
Express the given equation in terms of base 2.
22x=52^{2x} = 5
Since 4=224 = 2^2, we can rewrite 4x4^x as (22)x(2^2)^x. Applying the power of a power rule, (am)n=amn(a^m)^n = a^{mn}, gives (22)x=22x(2^2)^x = 2^{2x}.
2
Rewrite the expression to be evaluated using exponent properties.
24x1=(22x)222^{4x - 1} = \frac{(2^{2x})^2}{2}
Using the division property of exponents, amn=amana^{m-n} = \frac{a^m}{a^n}, we can write 24x12^{4x - 1} as 24x2\frac{2^{4x}}{2}. Then, using the power of a power rule in reverse, 24x=(22x)22^{4x} = (2^{2x})^2.
3
Substitute the known value of 22x2^{2x} and simplify the numerical expression.
12.512.5
Substitute 22x=52^{2x} = 5 into the expression (22x)22\frac{(2^{2x})^2}{2} to obtain 522=252\frac{5^2}{2} = \frac{25}{2}, which simplifies to 12.512.5.

Anahtar Kavram

Manipulating exponential equations by expressing bases in terms of common prime factors and applying properties of exponents.
Tahmini Süre:1m 30s
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