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Zorluk: ZorQuadratic Equations

In the quadratic equation 3x2kx+24=03x^2 - kx + 24 = 0, kk is a positive constant. If one of the roots of the equation is twice the other root, what is the value of kk?

  1. A
    6
  2. B
    12
  3. 18Cevap
  4. D
    36

Cevap

18
The correct answer is 18. Let the roots of the equation be rr and 2r2r. The product of the roots is given by ca=243=8\frac{c}{a} = \frac{24}{3} = 8. Therefore, 2r2=82r^2 = 8, which means r2=4r^2 = 4. Since k>0k > 0, the roots must be positive, so r=2r = 2 and the two roots are 2 and 4. The sum of the roots is 2+4=62 + 4 = 6. According to Vieta's formulas, the sum of the roots is also equal to ba=k3-\frac{b}{a} = \frac{k}{3}. Setting the two expressions for the sum of the roots equal to each other gives k3=6\frac{k}{3} = 6, which simplifies to k=18k = 18.

Adım Adım Çözüm

1
Define the roots and set up the product of the roots using Vieta's formulas.
Let the roots be rr and 2r2r. The product of the roots is r×2r=2r2r \times 2r = 2r^2. From the equation 3x2kx+24=03x^2 - kx + 24 = 0, the product of the roots is also ca=243=8\frac{c}{a} = \frac{24}{3} = 8.
This establishes a relationship between the given ratio of the roots and the coefficients of the equation.
2
Solve for the root variable rr.
Setting 2r2=82r^2 = 8 gives r2=4r^2 = 4. Since kk is a positive constant, the sum of the roots must be positive, which means the roots themselves must be positive. Thus, r=2r = 2, and the roots are 22 and 44.
Finding the actual values of the roots is necessary to calculate their sum.
3
Use Vieta's formula for the sum of the roots to find kk.
The sum of the roots is 2+4=62 + 4 = 6. According to Vieta's formulas, the sum of the roots is ba=k3-\frac{b}{a} = \frac{k}{3}. Setting them equal gives k3=6\frac{k}{3} = 6, which simplifies to k=18k = 18.
This directly isolates and solves for the unknown constant kk.

Anahtar Kavram

Using Vieta's formulas to relate the roots of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 to its coefficients: the sum of the roots is ba-\frac{b}{a} and the product of the roots is ca\frac{c}{a}.
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