Soru

Zorluk: KolayLinear and Exponential Growth

A community library starts a digital collection with 5,0005,000 e-books. The library's goal is to increase the number of e-books in the collection by 8%8\% each year. Which of the following functions best models the number of e-books, E(t)E(t), in the collection tt years after the collection was started?

  1. A
    E(t)=400t+5,000E(t) = 400t + 5,000
  2. B
    E(t)=5,000(0.08)tE(t) = 5,000(0.08)^t
  3. E(t)=5,000(1.08)tE(t) = 5,000(1.08)^tCevap
  4. D
    E(t)=1.08t+5,000E(t) = 1.08t + 5,000

Cevap

E(t)=5,000(1.08)tE(t) = 5,000(1.08)^t
The correct option is the function that represents exponential growth, where the quantity increases by a constant percentage each year. The general formula for exponential growth is E(t)=a(1+r)tE(t) = a(1 + r)^t, where aa is the initial value, rr is the growth rate as a decimal, and tt is the number of time periods. Here, the initial number of e-books is a=5,000a = 5,000 and the annual growth rate is r=8%=0.08r = 8\% = 0.08. Therefore, the growth factor is 1+r=1.081 + r = 1.08. Substituting these values into the formula yields the correct model: E(t)=5,000(1.08)tE(t) = 5,000(1.08)^t.

Adım Adım Çözüm

1
Determine if the growth is linear or exponential by analyzing the type of increase described.
The problem states that the collection increases by 8%8\% each year. Since the increase is a constant percentage rather than a constant quantity, this represents exponential growth.
Identifying the growth type determines whether to use a linear equation or an exponential equation.
2
State the general form of an exponential growth function.
The general formula is E(t)=a(1+r)tE(t) = a(1 + r)^t, where aa is the initial amount, rr is the percent growth rate expressed as a decimal, and 1+r1 + r is the growth factor.
This formula provides the template for constructing the model.
3
Identify the values of aa and rr from the given context and substitute them into the template.
The initial value a=5,000a = 5,000. The growth rate r=8%=0.08r = 8\% = 0.08, so the growth factor is 1+0.08=1.081 + 0.08 = 1.08. Substituting these gives E(t)=5,000(1.08)tE(t) = 5,000(1.08)^t.
This completes the model construction to find the correct expression.

Anahtar Kavram

Linear and Exponential Growth
Bu soruyu puanla