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Zorluk: OrtaLinear Inequalities in One Variable

A rideshare driver has a daily goal of earning at least 150.Sofartoday,thedriverhasearned150. So far today, the driver has earned 45. The driver earns 12perrideplusanaveragetipof12 per ride plus an average tip of 3 per ride. If the driver must pay a daily vehicle fee of $15, what is the minimum number of additional rides the driver must complete today to meet or exceed the daily earnings goal?

Cevap: 8 rides

Cevap

The minimum number of additional rides the driver must complete today is 8.
The driver earns 12plusa12 plus a 3 tip per ride, which is 15perride.Startingwith15 per ride. Starting with 45 and subtracting the 15feeleavesthedriverwith15 fee leaves the driver with 30 before completing any new rides. To reach at least 150,thedriverneedstoearnatleast150, the driver needs to earn at least 120 more. Dividing 120bythe120 by the 15 rate per ride gives a minimum of 8 rides.

Adım Adım Çözüm

1
Define the variable xx for the number of additional rides and write an inequality representing the total net earnings.
45+12x+3x1515045 + 12x + 3x - 15 \geq 150
To represent the condition that the driver's total earnings, including initial earnings and new rides, minus the fee, must be at least $150.
2
Simplify the left side of the inequality by combining the constants and the xx terms.
30+15x15030 + 15x \geq 150
To group like terms and simplify the expression before solving.
3
Subtract 30 from both sides of the inequality to isolate the variable term.
15x12015x \geq 120
To isolate the term with the variable on one side of the inequality.
4
Divide both sides of the inequality by 15 to solve for xx.
x8x \geq 8
To find the minimum value of xx that satisfies the inequality.

Anahtar Kavram

Solving linear inequalities in one variable to find a minimum threshold value in a real-world scenario.
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