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Zorluk: KolayRadical and Rational Equations

If 20x3=4\frac{20}{x - 3} = 4, what is the value of x+2x + 2?

Cevap: 10

Cevap

10
To solve the equation 20x3=4\frac{20}{x - 3} = 4, multiply both sides by x3x - 3 to get 20=4(x3)20 = 4(x - 3). Distributing the 4 gives 20=4x1220 = 4x - 12. Adding 12 to both sides yields 32=4x32 = 4x, and dividing by 4 gives x=8x = 8. Substituting x=8x = 8 into the expression x+2x + 2 gives 8+2=108 + 2 = 10.

Adım Adım Çözüm

1
Multiply both sides of the equation by the denominator x3x - 3.
20=4(x3)20 = 4(x - 3)
To eliminate the fraction and rewrite the rational equation in linear form.
2
Distribute the constant on the right side of the equation.
20=4x1220 = 4x - 12
To remove the parentheses by multiplying 4 by both xx and 3-3.
3
Add 12 to both sides of the equation.
32=4x32 = 4x
To isolate the term with the variable xx on one side of the equation.
4
Divide both sides of the equation by 4.
x=8x = 8
To solve for the variable xx.
5
Substitute the value of xx into the expression x+2x + 2.
1010
The question asks for the value of the expression x+2x + 2 rather than just the variable xx.

Anahtar Kavram

Solving rational equations by clearing the denominator and isolating the variable to evaluate algebraic expressions.
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