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Zorluk: OrtaQuadratic Functions and Graphs

In the xyxy-plane, the graph of the quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c, where aa, bb, and cc are constants, has a vertex at (2,3)(2, -3) and passes through the point (4,5)(4, 5). If the graph of a second quadratic function, gg, is obtained by translating the graph of ff horizontally by 33 units to the right and vertically by 55 units up, what is the value of g(5)g(5)?

  1. A
    -8
  2. 2Cevap
  3. C
    8
  4. D
    74

Cevap

The value of g(5)g(5) is 22.
The vertex of the graph of ff is at (2,3)(2, -3), which means f(2)=3f(2) = -3. The graph of gg is obtained by translating the graph of ff by 33 units to the right and 55 units up, so its equation is g(x)=f(x3)+5g(x) = f(x - 3) + 5. To find g(5)g(5), we substitute x=5x = 5 into this relation, which gives g(5)=f(53)+5=f(2)+5g(5) = f(5 - 3) + 5 = f(2) + 5. Since f(2)=3f(2) = -3, we have g(5)=3+5=2g(5) = -3 + 5 = 2. Alternatively, translating the vertex of ff at (2,3)(2, -3) by 33 units to the right and 55 units up gives the vertex of gg at (2+3,3+5)=(5,2)(2 + 3, -3 + 5) = (5, 2). Since the vertex of the parabola gg occurs at x=5x = 5, the value of g(5)g(5) is the yy-coordinate of the vertex, which is 22.

Adım Adım Çözüm

1
Identify the vertex of the function ff and write its vertex form equation.
The vertex of ff is (2,3)(2, -3), so the vertex form of the function is f(x)=a(x2)23f(x) = a(x - 2)^2 - 3.
This allows us to find the specific equation of f(x)f(x) if needed, and also tells us that the value of f(2)f(2) is 3-3.
2
Set up the equation for the translated function g(x)g(x).
A horizontal translation of 33 units to the right and a vertical translation of 55 units up is represented by g(x)=f(x3)+5g(x) = f(x - 3) + 5.
This defines the function gg in terms of the function ff using standard translation rules.
3
Evaluate g(5)g(5) using the relation from step 2.
g(5)=f(53)+5=f(2)+5g(5) = f(5 - 3) + 5 = f(2) + 5.
This simplifies the calculation by using the value of ff at the vertex.
4
Substitute the value of f(2)f(2) to find g(5)g(5).
g(5)=3+5=2g(5) = -3 + 5 = 2.
Since the vertex of ff is at (2,3)(2, -3), we know f(2)=3f(2) = -3, which yields the final result.

Anahtar Kavram

Quadratic functions can be analyzed and transformed using their vertex form and function translation rules.
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