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Zorluk: KolayEquivalent Algebraic Expressions

For all real numbers xx and yy, the expression (4x3y2)2(2x2y)(4x^3y^2)^2(2x^2y) is equivalent to which of the following?

  1. A
    8x8y58x^8y^5
  2. B
    32x12y432x^{12}y^4
  3. 32x8y532x^8y^5Cevap
  4. D
    32x7y532x^7y^5

Cevap

The correct equivalent expression is 32x8y532x^8y^5.
To find the equivalent expression, we first apply the power of a product rule to the first term: (4x3y2)2=42(x3)2(y2)2=16x6y4(4x^3y^2)^2 = 4^2(x^3)^2(y^2)^2 = 16x^6y^4. Next, we multiply this result by the second term: (16x6y4)(2x2y)(16x^6y^4)(2x^2y). Multiplying the coefficients gives 16×2=3216 \times 2 = 32. Adding the exponents of the same base variables gives x6+2=x8x^{6+2} = x^8 and y4+1=y5y^{4+1} = y^5. This results in 32x8y532x^8y^5.

Adım Adım Çözüm

1
Apply the power of a product rule to square the first expression: (4x3y2)2(4x^3y^2)^2.
16x6y416x^6y^4
When raising a product to a power, raise each factor to that power: 42=164^2 = 16, (x3)2=x3×2=x6(x^3)^2 = x^{3 \times 2} = x^6, and (y2)2=y2×2=y4(y^2)^2 = y^{2 \times 2} = y^4.
2
Multiply the simplified first expression by the second expression: (16x6y4)(2x2y)(16x^6y^4)(2x^2y).
32x8y532x^8y^5
Multiply the numerical coefficients (16×2=3216 \times 2 = 32) and add the exponents of variables with matching bases (x6+2=x8x^{6+2} = x^8 and y4+1=y5y^{4+1} = y^5).

Anahtar Kavram

Simplifying equivalent algebraic expressions using rules of exponents
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