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Zorluk: OrtaLinear Equations in One Variable

If 56(y2)13(2y5)=32\frac{5}{6}(y - 2) - \frac{1}{3}(2y - 5) = \frac{3}{2}, what is the value of 4y4y?

Cevap: 36

Cevap

The correct answer is 36.
To solve the equation 56(y2)13(2y5)=32\frac{5}{6}(y - 2) - \frac{1}{3}(2y - 5) = \frac{3}{2}, we first clear the fractions by multiplying the entire equation by the least common denominator, 6, which yields 5(y2)2(2y5)=95(y - 2) - 2(2y - 5) = 9. Distributing the terms on the left side gives 5y104y+10=95y - 10 - 4y + 10 = 9. Combining like terms simplifies this to y=9y = 9. The question asks for the value of 4y4y, so we multiply 99 by 44 to get the final answer of 3636.

Adım Adım Çözüm

1
Multiply both sides of the equation by the least common denominator, which is 6.
5(y2)2(2y5)=95(y - 2) - 2(2y - 5) = 9
Multiplying by 6 eliminates the fractions, simplifying the equation.
2
Distribute the coefficients across the parentheses.
5y104y+10=95y - 10 - 4y + 10 = 9
Expanding the terms allows like terms to be combined in the next step.
3
Combine the variable terms and constant terms on the left side of the equation.
y=9y = 9
Combining 5y4y5y - 4y yields yy, and combining 10+10-10 + 10 yields 00, isolating the variable.
4
Multiply the value of yy by 4.
4y=364y = 36
The question asks for the value of 4y4y rather than just yy.

Anahtar Kavram

Solving a linear equation in one variable by clearing fractions and combining like terms.
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