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Zorluk: ZorSystems of Linear Inequalities in Two Variables

A digital marketing firm allocates its monthly advertising budget between search engine campaigns and social media campaigns. Let xx represent the amount, in thousands of dollars, spent on search engine campaigns, and let yy represent the amount, in thousands of dollars, spent on social media campaigns. The system of inequalities below represents the firm's monthly constraints:

x2yx+y253x+4y80y3\begin{aligned} x &\ge 2y \\ x + y &\le 25 \\ 3x + 4y &\le 80 \\ y &\ge 3 \end{aligned}

Based on these constraints, what is the maximum possible amount, in thousands of dollars, the firm can spend on social media campaigns?

Cevap: 8

Cevap

8
To find the maximum possible value of yy, we analyze the boundaries of the feasible region. The boundary lines of the system are x=2yx = 2y, x+y=25x + y = 25, 3x+4y=803x + 4y = 80, and y=3y = 3. We can find the upper limit of yy by combining the inequalities x2yx \ge 2y and 3x+4y803x + 4y \le 80. Multiplying the first inequality by 33 gives 3x6y3x \ge 6y. Adding 4y4y to both sides yields 3x+4y10y3x + 4y \ge 10y. Because 3x+4y803x + 4y \le 80, it follows that 10y8010y \le 80, which simplifies to y8y \le 8. We verify that the point (16,8)(16, 8) satisfies the remaining inequalities: 16+8=242516 + 8 = 24 \le 25 and 838 \ge 3, which are both true. Thus, the maximum possible value of yy is 88.

Adım Adım Çözüm

1
Relate the variables using the constraints to establish an upper bound for yy.
Since x2yx \ge 2y, multiplying both sides by 33 gives 3x6y3x \ge 6y.
This allows us to express the 3x3x term in the cost inequality in terms of yy to determine the maximum boundary.
2
Substitute 3x6y3x \ge 6y into the inequality 3x+4y803x + 4y \le 80.
We get 6y+4y3x+4y806y + 4y \le 3x + 4y \le 80, which simplifies to 10y8010y \le 80.
This establishes a direct upper limit for yy based on the intersection of the two active boundary lines.
3
Solve the inequality 10y8010y \le 80 for yy.
y8y \le 8.
This determines that the maximum possible value for yy under these constraints is 88.
4
Verify that the point corresponding to y=8y = 8 satisfies all other constraints in the system.
When y=8y = 8, the boundary x=2yx = 2y gives x=16x = 16. Checking (16,8)(16, 8) against all inequalities:
- 162(8)    161616 \ge 2(8) \implies 16 \ge 16 (True)
- 16+825    242516 + 8 \le 25 \implies 24 \le 25 (True)
- 3(16)+4(8)80    80803(16) + 4(8) \le 80 \implies 80 \le 80 (True)
- 838 \ge 3 (True)
We must verify that the optimal vertex lies within the feasible region defined by all four inequalities.

Anahtar Kavram

Maximizing a coordinate value within a bounded feasible region defined by a system of linear inequalities.
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