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Zorluk: ZorExponential Functions and Equations

If 272x19y+2=31327^{2x - 1} \cdot 9^{y + 2} = 3^{13} and 8xy=2y98^{x - y} = 2^{y - 9}, what is the value of x+yx + y?

  1. A
    2
  2. 4Cevap
  3. C
    6
  4. D
    9

Cevap

4
To solve the system, we convert all exponential terms to their prime bases. The first equation becomes 36x332y+4=3133^{6x - 3} \cdot 3^{2y + 4} = 3^{13}, which simplifies to 36x+2y+1=3133^{6x + 2y + 1} = 3^{13}. Equating the exponents yields 6x+2y+1=136x + 2y + 1 = 13, which simplifies to 3x+y=63x + y = 6. The second equation becomes 23x3y=2y92^{3x - 3y} = 2^{y - 9}. Equating these exponents yields 3x4y=93x - 4y = -9. Solving this system of equations gives x=1x = 1 and y=3y = 3. The sum of these values is 1+3=41 + 3 = 4.

Adım Adım Çözüm

1
Convert the bases of the first equation to a common base of 3.
Since 27=3327 = 3^3 and 9=329 = 3^2, we can rewrite the equation 272x19y+2=31327^{2x - 1} \cdot 9^{y + 2} = 3^{13} as (33)2x1(32)y+2=313(3^3)^{2x - 1} \cdot (3^2)^{y + 2} = 3^{13}. Applying the power of a power rule, this simplifies to 36x332y+4=3133^{6x - 3} \cdot 3^{2y + 4} = 3^{13}. Using the product rule of exponents, we add the exponents to get 36x+2y+1=3133^{6x + 2y + 1} = 3^{13}.
This allows us to equate the exponents and form a linear equation.
2
Set the exponents equal to each other to obtain the first linear equation.
6x+2y+1=13    6x+2y=12    3x+y=66x + 2y + 1 = 13 \implies 6x + 2y = 12 \implies 3x + y = 6.
Since the bases are identical on both sides, their exponents must be equal.
3
Convert the bases of the second equation to a common base of 2 and equate their exponents.
Since 8=238 = 2^3, rewrite 8xy=2y98^{x - y} = 2^{y - 9} as (23)xy=2y9    23x3y=2y9(2^3)^{x - y} = 2^{y - 9} \implies 2^{3x - 3y} = 2^{y - 9}. Equating the exponents gives 3x3y=y9    3x4y=93x - 3y = y - 9 \implies 3x - 4y = -9.
This gives us a second linear equation to form a system of equations.
4
Solve the system of equations for the variables.
From the first equation, we have 3x=6y3x = 6 - y. Substituting this into the second equation gives (6y)4y=9    65y=9    5y=15    y=3(6 - y) - 4y = -9 \implies 6 - 5y = -9 \implies -5y = -15 \implies y = 3. Substituting y=3y = 3 back into the first equation yields 3x+3=6    3x=3    x=13x + 3 = 6 \implies 3x = 3 \implies x = 1.
Solving the system of linear equations provides the individual values of the variables.
5
Calculate the sum of the variables.
x+y=1+3=4x + y = 1 + 3 = 4.
This answers the question asking for the sum of the variables.

Anahtar Kavram

Expressing exponential terms with a common base to form and solve a system of linear equations.
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