Tüm alıştırma soruları

612 soru

Soru 81Soru

A linear equation models the total cost, in dollars, of purchasing xx pounds of almonds and yy pounds of walnuts. Under the original pricing, purchasing 88 pounds of almonds and 1515 pounds of walnuts costs cc dollars. If the price per pound of almonds is increased by 25%25\% and the price per pound of walnuts is decreased by 10%10\%, the cost of purchasing 88 pounds of almonds and 1515 pounds of walnuts is still cc dollars. Under the original pricing, a customer can purchase exactly 2222 pounds of almonds and no walnuts for cc dollars. How many pounds of walnuts and no almonds can the customer purchase for cc dollars under the original pricing?

Cevabı ve açıklamayı göster

Cevap: 16.5

Cevap

16.5
Under the original pricing, the cost of 88 pounds of almonds at aa dollars per pound and 1515 pounds of walnuts at bb dollars per pound is represented by the linear equation 8a+15b=c8a + 15b = c. Under promotional pricing, the cost of almonds increases by 25%25\% to 1.25a1.25a, and the cost of walnuts decreases by 10%10\% to 0.90b0.90b. The new cost for the same amounts of nuts is 8(1.25a)+15(0.90b)=10a+13.5b=c8(1.25a) + 15(0.90b) = 10a + 13.5b = c. Setting the two cost equations equal to each other gives 8a+15b=10a+13.5b8a + 15b = 10a + 13.5b, which simplifies to 1.5b=2a1.5b = 2a, or a=0.75ba = 0.75b. Since 2222 pounds of almonds can be purchased for cc dollars, we have 22a=c22a = c. Substituting a=0.75ba = 0.75b yields 22(0.75b)=c22(0.75b) = c, which simplifies to 16.5b=c16.5b = c. Thus, exactly 16.516.5 pounds of walnuts can be purchased for cc dollars.

Adım Adım Çözüm

1
Set up the equation representing the total cost of the initial purchase under the original pricing.
8a+15b=c8a + 15b = c, where aa is the original price per pound of almonds and bb is the original price per pound of walnuts.
To represent the cost relation using the original individual prices of almonds and walnuts.
2
Modify the individual prices for the promotional rates and write the new total cost equation.
8(1.25a)+15(0.90b)=c    10a+13.5b=c8(1.25a) + 15(0.90b) = c \implies 10a + 13.5b = c.
The price per pound of almonds increases by 25%25\% (multiplied by 1.251.25) and the price per pound of walnuts decreases by 10%10\% (multiplied by 0.900.90).
3
Equate the two expressions representing cc to find the ratio between the prices aa and bb.
8a+15b=10a+13.5b    2a=1.5b    a=0.75b8a + 15b = 10a + 13.5b \implies 2a = 1.5b \implies a = 0.75b.
Since both purchasing combinations yield the same total budget cc, their cost equations are equal.
4
Use the budget equation for purchasing only almonds to determine the equivalent purchase in walnuts.
22a=c    22(0.75b)=c    16.5b=c22a = c \implies 22(0.75b) = c \implies 16.5b = c. Therefore, 16.516.5 pounds of walnuts can be bought for cc dollars.
Substituting the price relationship a=0.75ba = 0.75b allows expressing the budget cc purely in terms of the price of walnuts bb.

Anahtar Kavram

Modeling linear relationships in two variables and analyzing changes in coefficients.
Soru 82Soru

If the equations x+2y=12x + 2y = 12 and x+y=7x + y = 7 are true for the same values of xx and yy, what is the value of yy?

Cevabı ve açıklamayı göster

Cevap: 5

Cevap

The value of yy is 5.
Subtracting the equation x+y=7x + y = 7 from x+2y=12x + 2y = 12 gives (xx)+(2yy)=127(x - x) + (2y - y) = 12 - 7, which simplifies directly to y=5y = 5.

Adım Adım Çözüm

1
Subtract the second equation from the first equation.
y=5y = 5
Subtracting x+y=7x + y = 7 from x+2y=12x + 2y = 12 eliminates the xx terms, leaving a single linear equation in terms of yy.

Anahtar Kavram

Solving systems of linear equations using elimination.
Soru 83Soru

In the xyxy-plane, the graph of the linear function ff passes through the point (6,4)(6, 4). Line gg is perpendicular to the graph of ff and has a yy-intercept of (0,12)(0, 12). The graph of ff and line gg intersect at the point P(h,k)P(h, k), where hh and kk are integers. If the slope of the graph of ff is a positive integer greater than 55, what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 11

Cevap

The value of kk is 1111.
By equating the linear equations representing ff and gg, we find that the intersection point's xx-coordinate hh is given by h=6+8m6m2+1h = 6 + \frac{8m - 6}{m^2 + 1}. Since hh is an integer and mm is a positive integer greater than 55, the inequality m2+18m6m^2 + 1 \le 8m - 6 limits mm to the range 1m71 \le m \le 7. Testing the integers greater than 55 (which are 66 and 77) reveals that only m=7m = 7 yields an integer value for hh, resulting in h=7h = 7. Substituting these values back into the equation of either line yields k=11k = 11.

Adım Adım Çözüm

1
Write the equation of the linear function ff in terms of its slope mm.
y4=m(x6)    y=mx+46my - 4 = m(x - 6) \implies y = mx + 4 - 6m
Since the graph of ff passes through the point (6,4)(6, 4) with slope mm, we can use the point-slope form of a linear equation.
2
Write the equation of line gg in slope-intercept form.
y=1mx+12y = -\frac{1}{m}x + 12
Line gg is perpendicular to the graph of ff, so its slope is the negative reciprocal of mm, which is 1m-\frac{1}{m}. Its yy-intercept is (0,12)(0, 12).
3
Equate the two equations to find the xx-coordinate hh of the intersection point P(h,k)P(h, k) in terms of mm.
h=6m2+8mm2+1h = \frac{6m^2 + 8m}{m^2 + 1}
At the intersection point, the yy-values of both equations are equal, so we solve mx+46m=1mx+12mx + 4 - 6m = -\frac{1}{m}x + 12 for xx.
4
Analyze the expression for hh to find the integer constraints on mm.
h=6+8m6m2+1    m28m+70    1m7h = 6 + \frac{8m - 6}{m^2 + 1} \implies m^2 - 8m + 7 \le 0 \implies 1 \le m \le 7
For hh to be an integer, 8m6m2+1\frac{8m - 6}{m^2 + 1} must be an integer. Since mm is a positive integer greater than 55, the numerator is positive, meaning the denominator m2+1m^2 + 1 must be less than or equal to the numerator 8m68m - 6.
5
Test the possible integer values of mm greater than 55 to find the one that yields integer coordinates.
m=7    h=7m = 7 \implies h = 7
The only integers greater than 55 in the range [1,7][1, 7] are 66 and 77. Testing m=6m=6 gives a non-integer, while m=7m=7 gives h=7h = 7, which is an integer.
6
Calculate the yy-coordinate kk of the intersection point PP.
k=11k = 11
Substitute h=7h = 7 into the equation of line gg: k=17(7)+12=11k = -\frac{1}{7}(7) + 12 = 11.

Anahtar Kavram

Linear Functions and Graphs
Soru 84Soru

In the xyxy-plane, the graph of the linear function ff has a slope of mm and a yy-intercept of (0,b)(0, b). The graph of the linear function gg has a slope of 3m-3m and a yy-intercept of (0,b+15)(0, b + 15). If the graphs of ff and gg intersect at the point (3,5)(3, 5), what is the value of f(5)f(5)?

Cevabı ve açıklamayı göster

Cevap: 7.5

Cevap

7.5 (or 15/2)
By writing the equations of the two lines as f(x)=mx+bf(x) = mx + b and g(x)=3mx+b+15g(x) = -3mx + b + 15, and substituting the intersection point (3,5)(3, 5), we get the system of equations 3m+b=53m + b = 5 and 9m+b=10-9m + b = -10. Subtracting these equations gives 12m=1512m = 15, which simplifies to m=1.25m = 1.25. Substituting mm back into 3m+b=53m + b = 5 yields b=1.25b = 1.25. The function is therefore f(x)=1.25x+1.25f(x) = 1.25x + 1.25. Evaluating this at x=5x = 5 gives f(5)=1.25(5)+1.25=7.5f(5) = 1.25(5) + 1.25 = 7.5.

Adım Adım Çözüm

1
Formulate equations for both linear functions using slope-intercept form.
f(x)=mx+bf(x) = mx + b and g(x)=3mx+b+15g(x) = -3mx + b + 15
The equation of a line with slope MM and yy-intercept (0,B)(0, B) is given by y=Mx+By = Mx + B.
2
Substitute the coordinates of the intersection point (3,5)(3, 5) into both equations.
3m+b=53m + b = 5 and 9m+b=10-9m + b = -10
Since the intersection point lies on both lines, its coordinates must satisfy both equations.
3
Solve the system of equations for mm and bb.
m=1.25m = 1.25 and b=1.25b = 1.25
Subtracting the equations eliminates bb, giving 12m=15    m=1.2512m = 15 \implies m = 1.25. Substituting this back into the first equation gives 3(1.25)+b=5    b=1.253(1.25) + b = 5 \implies b = 1.25.
4
Evaluate f(5)f(5) using the found values.
f(5)=1.25(5)+1.25=7.5f(5) = 1.25(5) + 1.25 = 7.5
Substitute x=5x = 5 into the equation f(x)=1.25x+1.25f(x) = 1.25x + 1.25.

Anahtar Kavram

Solving systems of linear equations and evaluating linear functions from graph intersections.
Tahmini Süre:2m 0s
Soru 85Soru

In the xyxy-plane, a line passes through the origin and has a slope of 35\frac{3}{5}. If the point (k,9)(k, 9) lies on the line, what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 15

Cevap

15
A line passing through the origin has a yy-intercept of 00. Thus, its equation in slope-intercept form is y=mxy = mx, where mm is the slope. Given the slope is 35\frac{3}{5}, the equation is y=35xy = \frac{3}{5}x. Since the point (k,9)(k, 9) lies on the line, substituting these coordinates yields 9=35k9 = \frac{3}{5}k. Multiplying both sides by 53\frac{5}{3} gives k=15k = 15.

Adım Adım Çözüm

1
Write the equation of the line in slope-intercept form.
y=35xy = \frac{3}{5}x
The line passes through the origin (0,0)(0,0), so the yy-intercept is 00, and the slope is 35\frac{3}{5}.
2
Substitute the coordinates of the point (k,9)(k, 9) into the line's equation.
9=35k9 = \frac{3}{5}k
A point lies on a line if its coordinates satisfy the equation of the line.
3
Solve the equation for kk.
k=15k = 15
Multiply both sides of the equation by 53\frac{5}{3} to isolate kk.

Anahtar Kavram

Using the slope and a point on a line to determine an unknown coordinate.
Soru 86Soru

For the linear function ff, the value of f(0)f(0) is 33 and the value of f(5)f(5) is 1818. What is the slope of the graph of y=f(x)y = f(x) in the xyxy-plane?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

The slope of the graph of y=f(x)y = f(x) is 33.
The slope of a linear function can be determined using any two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) on its graph with the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. The given function values f(0)=3f(0) = 3 and f(5)=18f(5) = 18 correspond to the coordinate points (0,3)(0, 3) and (5,18)(5, 18) respectively. Substituting these coordinates into the formula gives m=18350=155=3m = \frac{18 - 3}{5 - 0} = \frac{15}{5} = 3.

Adım Adım Çözüm

1
Identify the coordinates of two points on the line using the given function values.
The function values f(0)=3f(0) = 3 and f(5)=18f(5) = 18 correspond to the points (0,3)(0, 3) and (5,18)(5, 18) on the graph of the function.
In function notation, f(x)=yf(x) = y represents a point (x,y)(x, y) on the graph of the function.
2
Calculate the slope using the slope formula.
The slope mm is calculated as 18350=3\frac{18 - 3}{5 - 0} = 3.
The slope of a line is defined as the change in yy divided by the change in xx between any two points on the line.

Anahtar Kavram

Calculating the slope of a linear function from given function values.
Soru 87Soru

If 3(2.5x4)1.5(x2)=0.8(5x+10)3(2.5x - 4) - 1.5(x - 2) = 0.8(5x + 10), what is the value of xx?

Cevabı ve açıklamayı göster

Cevap: 8.5

Cevap

8.5
By distributing and simplifying terms, the linear equation simplifies to 2x=172x = 17, which yields x=8.5x = 8.5.

Adım Adım Çözüm

1
Distribute the constants on both sides of the equation.
7.5x121.5x+3=4x+87.5x - 12 - 1.5x + 3 = 4x + 8
To simplify the expressions.
2
Combine like terms on the left side.
6x9=4x+86x - 9 = 4x + 8
To simplify the left side of the equation.
3
Subtract 4x4x from both sides of the equation.
2x9=82x - 9 = 8
To group variable terms on one side.
4
Add 9 to both sides of the equation.
2x=172x = 17
To isolate the term with the variable.
5
Divide both sides by 2.
x=8.5x = 8.5
To find the final value of the variable.

Anahtar Kavram

Linear Equations in One Variable

Alternatif Yöntem

Multiply the entire equation by 10 to clear all decimal values: 30(2.5x4)15(x2)=8(5x+10)30(2.5x - 4) - 15(x - 2) = 8(5x + 10). Expanding this yields 75x12015x+30=40x+8075x - 120 - 15x + 30 = 40x + 80, which simplifies to 60x90=40x+8060x - 90 = 40x + 80. Subtracting 40x40x and adding 90 to both sides gives 20x=17020x = 170, resulting in x=8.5x = 8.5.
Tahmini Süre:1m 30s
Soru 88Soru

A linear function ff is defined by f(x)=mx+bf(x) = mx + b, where mm and bb are constants. The graph of ff in the xyxy-plane passes through the point (2,5)(2, 5). A second linear function gg is defined by g(x)=f(x3)+4g(x) = f(x - 3) + 4. The graph of gg has an xx-intercept of (k,0)(k, 0) and a yy-intercept of (0,k)(0, -k), where kk is a nonzero constant. What is the value of f(8)f(8)?

Cevabı ve açıklamayı göster

Cevap: 11

Cevap

11
The correct answer is 11. By using the given point on the graph of f(x)f(x), we express its y-intercept bb in terms of its slope mm as b=52mb = 5 - 2m. Substituting this expression into the translation equation g(x)=f(x3)+4g(x) = f(x - 3) + 4 yields g(x)=mx5m+9g(x) = mx - 5m + 9. Setting the y-intercept of g(x)g(x), which is 5m+9-5m + 9, equal to k-k gives k=5m9k = 5m - 9. Evaluating g(x)g(x) at its x-intercept x=kx = k gives mk5m+9=0mk - 5m + 9 = 0. Substituting the relation 5m+9=k-5m + 9 = -k into this equation yields mkk=0mk - k = 0, or k(m1)=0k(m - 1) = 0. Since kk is nonzero, we find m=1m = 1, which in turn gives b=3b = 3. Thus, the linear function is f(x)=x+3f(x) = x + 3, and f(8)=11f(8) = 11.

Adım Adım Çözüm

1
Express the y-intercept constant bb in terms of the slope mm.
b=52mb = 5 - 2m
Since the graph of f(x)=mx+bf(x) = mx + b passes through (2,5)(2, 5), substituting x=2x = 2 and f(x)=5f(x) = 5 gives 5=2m+b5 = 2m + b.
2
Write the expression for g(x)g(x) in terms of mm.
g(x)=mx5m+9g(x) = mx - 5m + 9
By definition, g(x)=f(x3)+4=m(x3)+b+4g(x) = f(x - 3) + 4 = m(x - 3) + b + 4. Substituting b=52mb = 5 - 2m simplifies the expression to g(x)=mx5m+9g(x) = mx - 5m + 9.
3
Relate the y-intercept of g(x)g(x) to the parameter kk.
k=5m9k = 5m - 9
The y-intercept of g(x)g(x) is g(0)=5m+9g(0) = -5m + 9. Since the y-intercept is given as (0,k)(0, -k), we set k=5m+9-k = -5m + 9, which gives k=5m9k = 5m - 9.
4
Set up an equation using the x-intercept of g(x)g(x).
g(k)=mk5m+9=0g(k) = mk - 5m + 9 = 0
Since the x-intercept of g(x)g(x) is (k,0)(k, 0), substituting x=kx = k into the expression for g(x)g(x) must yield 00.
5
Solve for the slope mm.
m=1m = 1
Substituting 5m+9=k-5m + 9 = -k into the equation mk5m+9=0mk - 5m + 9 = 0 gives mkk=0mk - k = 0, which factors as k(m1)=0k(m - 1) = 0. Since kk is a nonzero constant, we divide by kk to get m1=0m - 1 = 0, so m=1m = 1.
6
Find the constant bb and write the final formula for f(x)f(x).
f(x)=x+3f(x) = x + 3
Substituting m=1m = 1 back into b=52mb = 5 - 2m yields b=3b = 3. Therefore, f(x)=x+3f(x) = x + 3.
7
Evaluate f(8)f(8).
11
Substituting x=8x = 8 into the function f(x)=x+3f(x) = x + 3 gives f(8)=8+3=11f(8) = 8 + 3 = 11.

Anahtar Kavram

Linear function transformations and intercept properties
Soru 89Soru

The equation 3x+4y=363x + 4y = 36 represents the relationship between the number of small boxes, xx, and large boxes, yy, that can fit in a delivery van. If the van is loaded with exactly 6 large boxes, what is the number of small boxes that can also fit in the van?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

The number of small boxes that can also fit in the van is 4.
Substituting y=6y = 6 into the equation 3x+4y=363x + 4y = 36 gives 3x+24=363x + 24 = 36. Subtracting 24 from both sides results in 3x=123x = 12. Dividing both sides by 3 yields x=4x = 4. Thus, the number of small boxes that can fit is 4.

Adım Adım Çözüm

1
Substitute 6 for yy in the equation 3x+4y=363x + 4y = 36.
3x+4(6)=363x + 4(6) = 36
The variable yy represents the number of large boxes, which is given as 6.
2
Simplify the multiplication in the equation.
3x+24=363x + 24 = 36
To simplify the terms before solving for xx.
3
Subtract 24 from both sides of the equation.
3x=123x = 12
To isolate the variable term 3x3x on one side of the equation.
4
Divide both sides of the equation by 3.
x=4x = 4
To solve for xx, the number of small boxes.

Anahtar Kavram

Evaluating and solving a linear equation in two variables given the value of one variable.
Tahmini Süre:45s
Soru 90Soru

The graph of the linear function ff in the xyxy-plane is defined by f(x)=kx+4f(x) = kx + 4, where kk is a positive constant. The graph of the linear function gg is obtained by translating the graph of ff left by 33 units and down by 22 units. If the xx-intercept of the graph of gg is 55 times the xx-intercept of the graph of ff, what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

6
The correct answer is 6. The linear function g(x)g(x) represents the translated graph, which is expressed as g(x)=f(x+3)2g(x) = f(x+3) - 2. Substituting f(x)=kx+4f(x) = kx + 4 yields g(x)=k(x+3)+42=kx+3k+2g(x) = k(x+3) + 4 - 2 = kx + 3k + 2. The xx-intercept of a graph is the point where the function value is 00. Solving f(x)=0f(x) = 0 gives the xx-intercept of the graph of ff as x=4kx = -\frac{4}{k}. Solving g(x)=0g(x) = 0 gives the xx-intercept of the graph of gg as x=3k+2kx = -\frac{3k + 2}{k}. We are given that the xx-intercept of the graph of gg is 55 times the xx-intercept of the graph of ff, which translates to the equation 3k+2k=5(4k)-\frac{3k+2}{k} = 5 \left(-\frac{4}{k}\right). Multiplying both sides by k-k (since k>0k > 0, k0k \neq 0) yields 3k+2=203k + 2 = 20. Subtracting 22 from both sides gives 3k=183k = 18, and dividing by 33 results in k=6k = 6.

Adım Adım Çözüm

1
Determine the equation of the translated function g(x)g(x)
g(x)=kx+3k+2g(x) = kx + 3k + 2
Shifting the graph of f(x)f(x) left by 33 units and down by 22 units translates to g(x)=f(x+3)2g(x) = f(x+3) - 2.
2
Find the xx-intercept of the graph of ff
x=4kx = -\frac{4}{k}
The xx-intercept is the input value for which the output of the function is zero, so we solve f(x)=0f(x) = 0.
3
Find the xx-intercept of the graph of gg
x=3k+2kx = -\frac{3k + 2}{k}
We set the equation of g(x)g(x) to zero and solve for xx in terms of kk.
4
Set up and solve the equation relating the two xx-intercepts
k=6k = 6
Using the relation xg=5xfx_g = 5 \cdot x_f, we obtain 3k+2k=5(4k)-\frac{3k + 2}{k} = 5 \left(-\frac{4}{k}\right), which simplifies to 3k+2=203k + 2 = 20, leading to k=6k = 6.

Anahtar Kavram

Function translations and finding intercepts of linear equations
Soru 91Soru

In the xyxy-plane, a line with a positive slope mm and a yy-intercept of (0,b)(0, b) passes through the point (b,12)(b, 12), where b>0b > 0. If the area of the triangle bounded by the line, the xx-axis, and the yy-axis is 44, what is the value of mm?

Cevabı ve açıklamayı göster

Cevap: 2

Cevap

2
The line equation is y=mx+by = mx + b. Substituting the point (b,12)(b, 12) gives 12=b(m+1)12 = b(m + 1). The xx-intercept of the line is at (bm,0)(-\frac{b}{m}, 0), which gives a base length of bm\frac{b}{m} for the right triangle, while the height is bb. The area of the triangle is b22m=4    b2=8m\frac{b^2}{2m} = 4 \implies b^2 = 8m. Substituting b=12m+1b = \frac{12}{m + 1} into this equation yields 144(m+1)2=8m    m(m+1)2=18\frac{144}{(m + 1)^2} = 8m \implies m(m + 1)^2 = 18. Solving this for positive values of mm gives the unique solution m=2m = 2.

Adım Adım Çözüm

1
Express the line equation and substitute the given point (b,12)(b, 12).
b(m+1)=12b(m + 1) = 12
Since the line has a yy-intercept of (0,b)(0, b) and a slope of mm, its equation is y=mx+by = mx + b. Substituting the point (b,12)(b, 12) yields 12=m(b)+b=b(m+1)12 = m(b) + b = b(m + 1).
2
Determine the lengths of the base and height of the triangle formed by the line and the coordinate axes.
Base =bm= \frac{b}{m}, Height =b= b
The yy-intercept is at (0,b)(0, b) and the xx-intercept is at (bm,0)(-\frac{b}{m}, 0). Since b>0b > 0 and m>0m > 0, the height is bb and the base is the absolute value of the xx-intercept, which is bm\frac{b}{m}.
3
Write the area equation of the triangle and simplify it.
b2=8mb^2 = 8m
The area of the right triangle is 12×base×height=12(bm)b=b22m\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \left(\frac{b}{m}\right)b = \frac{b^2}{2m}. Setting this equal to the given area of 44 gives b22m=4    b2=8m\frac{b^2}{2m} = 4 \implies b^2 = 8m.
4
Solve the system of equations for mm.
m=2m = 2
Substituting b=12m+1b = \frac{12}{m + 1} into b2=8mb^2 = 8m yields (12m+1)2=8m    144(m+1)2=8m    m(m+1)2=18\left(\frac{12}{m + 1}\right)^2 = 8m \implies \frac{144}{(m + 1)^2} = 8m \implies m(m + 1)^2 = 18. Since m(m+1)2m(m + 1)^2 is strictly increasing for positive mm, testing small integers shows 2(3)2=182(3)^2 = 18, so m=2m = 2 is the unique positive real solution.

Anahtar Kavram

Formulating linear equations in slope-intercept form and solving non-linear systems of equations derived from geometric constraints.

Alternatif Yöntem

Instead of algebraically expanding the cubic equation, one can test small positive integers for mm in the equation m(m+1)2=18m(m + 1)^2 = 18. Testing m=1m = 1 yields 1(2)2=41(2)^2 = 4 (too small), and testing m=2m = 2 yields 2(3)2=182(3)^2 = 18 (correct). Because m(m+1)2m(m + 1)^2 is strictly increasing for m>0m > 0, m=2m = 2 is the only positive real root.
Tahmini Süre:3m 0s
Soru 92Soru

If 2(x5)4-2(x - 5) \geq 4, what is the maximum possible value of xx?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

3
Distributing the 2-2 on the left side of the inequality 2(x5)4-2(x - 5) \geq 4 yields 2x+104-2x + 10 \geq 4. Subtracting 1010 from both sides gives 2x6-2x \geq -6. Dividing both sides by 2-2 and reversing the inequality sign results in x3x \leq 3. The maximum possible value is therefore 3.

Adım Adım Çözüm

1
Distribute 2-2 to the terms inside the parentheses.
2x+104-2x + 10 \geq 4
Applying the distributive property simplifies the inequality.
2
Subtract 1010 from both sides of the inequality.
2x6-2x \geq -6
This isolates the variable term on the left side.
3
Divide both sides of the inequality by 2-2 and reverse the inequality sign.
x3x \leq 3
Dividing both sides of an inequality by a negative number reverses the direction of the inequality.

Anahtar Kavram

Solving linear inequalities in one variable using the distributive property and division by negative numbers.
Soru 93Soru

A company manufactures custom travel mugs. The daily cost CC, in dollars, to manufacture nn mugs is given by the formula C=1.25n+250C = 1.25n + 250. The company sells each mug for 4.50.Tomakeaprofitofexactly4.50. To make a profit of exactly 400$ in a day, how many mugs must the company manufacture?

Cevabı ve açıklamayı göster

Cevap: 200

Cevap

The company must manufacture 200 mugs to make a profit of exactly $400 in a day.
Subtracting the cost expression from the revenue expression gives the profit equation: 4.50n(1.25n+250)=4004.50n - (1.25n + 250) = 400. Distributing the negative sign results in 4.50n1.25n250=4004.50n - 1.25n - 250 = 400, which simplifies to 3.25n250=4003.25n - 250 = 400. Adding 250 to both sides gives 3.25n=6503.25n = 650. Dividing both sides by 3.25 yields n=200n = 200.

Adım Adım Çözüm

1
Set up the profit equation
4.50n(1.25n+250)=4004.50n - (1.25n + 250) = 400
Profit is calculated as total revenue (4.50n4.50n) minus total cost (1.25n+2501.25n + 250).
2
Distribute the negative sign and simplify the equation
3.25n250=4003.25n - 250 = 400
Subtracting the entire cost expression requires distributing the subtraction to both 1.25n1.25n and 250250, yielding 4.50n1.25n2504.50n - 1.25n - 250.
3
Isolate the variable term by adding 250 to both sides
3.25n=6503.25n = 650
Adding 250 to both sides of the equation isolates the term containing nn.
4
Solve for nn by dividing both sides by 3.25
n=200n = 200
Dividing 650 by 3.25 gives the number of mugs needed to achieve the target profit.

Anahtar Kavram

Solving linear equations in one variable derived from a real-world context.
Soru 94Soru

In the xyxy-plane, the graph of the linear function hh has a slope of 33 and passes through the point (5,8)(5, 8). What is the value of h(11)h(11)?

Cevabı ve açıklamayı göster

Cevap: 26

Cevap

The value of h(11)h(11) is 26.
The correct answer is 26. Since the function hh is linear, its rate of change (slope) is constant. A slope of 3 means that for every 1-unit increase in xx, the value of h(x)h(x) increases by 3. The change in xx from 5 to 11 is 115=611 - 5 = 6. Therefore, the corresponding increase in h(x)h(x) is 3×6=183 \times 6 = 18. Adding this increase to the known value of h(5)=8h(5) = 8 gives h(11)=8+18=26h(11) = 8 + 18 = 26.

Adım Adım Çözüm

1
Determine the change in the input variable xx from the known point to the target point.
The change in xx is 115=611 - 5 = 6.
This identifies how many units the input increases from x=5x = 5 to x=11x = 11.
2
Multiply the change in xx by the slope to find the corresponding change in the function value.
The change in the function value is 3×6=183 \times 6 = 18.
The slope represents the constant rate of change (change in yy divided by change in xx). Therefore, multiplying the slope by the change in xx gives the total change in the output.
3
Add the calculated change in the function value to the initial function value.
h(11)=8+18=26h(11) = 8 + 18 = 26.
Adding the total increase in output to the starting output value at x=5x = 5 yields the value of the function at x=11x = 11.

Anahtar Kavram

Linear functions have a constant rate of change, which is represented by the slope. The change in the output value is equal to the slope multiplied by the change in the input value.

Alternatif Yöntem

Alternatively, find the equation of the line using the point-slope form: yy1=m(xx1)y - y_1 = m(x - x_1). Substituting the slope m=3m = 3 and the point (5,8)(5, 8) gives y8=3(x5)y - 8 = 3(x - 5), which simplifies to y=3x7y = 3x - 7. Thus, the function is defined by h(x)=3x7h(x) = 3x - 7. Evaluating this function at x=11x = 11 yields h(11)=3(11)7=337=26h(11) = 3(11) - 7 = 33 - 7 = 26.
Tahmini Süre:1m 0s
Soru 95Soru

A gym membership costs $35\$35 per month plus an additional $5\$5 per fitness class attended. If a member wants to spend at most $65\$65 in a single month, what is the maximum number of fitness classes the member can attend?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

The maximum number of fitness classes the member can attend is 66.
Let cc represent the number of classes. The inequality representing the budget constraint is 35+5c6535 + 5c \le 65. Subtracting 3535 from both sides of the inequality yields 5c305c \le 30. Dividing both sides by 55 yields c6c \le 6. Since the number of classes must be a whole number, the maximum number of classes the member can attend is 66.

Adım Adım Çözüm

1
Set up the inequality representing the situation.
35+5c6535 + 5c \le 65
The cost of the membership is a fixed $35\$35 plus $5\$5 per class cc, and this total must not exceed $65\$65.
2
Subtract 3535 from both sides of the inequality to isolate the variable term.
5c305c \le 30
Isolating the term with the variable allows us to solve for cc.
3
Divide both sides by 55 to find the solution range for the number of classes.
c6c \le 6
Dividing by the coefficient of the variable gives the upper limit for the number of classes.

Anahtar Kavram

Solving one-variable linear inequalities in a real-world context.
Soru 96Soru

In the xyxy-plane, the graph of the linear function ff passes through the points (k,12)(k, 12) and (8,k)(8, k), where kk is a constant. If the slope of the graph of ff is 13-\frac{1}{3}, what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 14

Cevap

14
The slope of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. Substituting the given points (k,12)(k, 12) and (8,k)(8, k) and the slope 13-\frac{1}{3} into the formula gives 13=k128k-\frac{1}{3} = \frac{k - 12}{8 - k}. Cross-multiplying yields 3(k12)=1(8k)3(k - 12) = -1(8 - k), which simplifies to 3k36=8+k3k - 36 = -8 + k. Isolating the variable kk gives 2k=282k = 28, so k=14k = 14.

Adım Adım Çözüm

1
Apply the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} using the points (k,12)(k, 12) and (8,k)(8, k) with slope 13-\frac{1}{3}.
13=k128k-\frac{1}{3} = \frac{k - 12}{8 - k}
The slope of a linear function is constant and defined by the ratio of the change in yy-values to the change in xx-values.
2
Cross-multiply to solve the equation for kk.
3(k12)=1(8k)3(k - 12) = -1(8 - k)
To eliminate the fractions and solve the rational equation.
3
Distribute and simplify both sides of the equation.
3k36=8+k3k - 36 = -8 + k
Distributing the constants on both sides prepares the equation for isolating the variable kk.
4
Isolate the variable kk by subtracting kk from both sides and adding 3636 to both sides.
2k=282k = 28
Grouping like terms on opposite sides of the equation.
5
Divide by 22 to find the value of kk.
k=14k = 14
To find the final numerical value of the constant kk.

Anahtar Kavram

Linear function slope formula
Tahmini Süre:1m 30s
Soru 97Soru

An artist sells customized prints online. The total price, yy, in dollars, for an order of xx prints is given by the equation y=8.50x+4.00y = 8.50x + 4.00, where 4.004.00 represents a flat shipping fee. If a customer's total order price is 38.0038.00, how many prints did the customer order?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

4
Substituting 38.0038.00 for yy in the given linear equation y=8.50x+4.00y = 8.50x + 4.00 yields 38.00=8.50x+4.0038.00 = 8.50x + 4.00. Subtracting 4.004.00 from both sides of the equation results in 34.00=8.50x34.00 = 8.50x. Dividing both sides of the equation by 8.508.50 yields x=4x = 4. Therefore, the customer ordered 4 prints.

Adım Adım Çözüm

1
Substitute the given total price of 38.0038.00 for yy in the equation.
38.00=8.50x+4.0038.00 = 8.50x + 4.00
The variable yy represents the total price of the order in dollars, which is given as 38.0038.00.
2
Subtract the shipping fee of 4.004.00 from both sides of the equation.
34.00=8.50x34.00 = 8.50x
Subtracting 4.004.00 from both sides isolates the variable term 8.50x8.50x.
3
Divide both sides of the equation by 8.508.50.
x=4x = 4
Dividing the remaining cost of 34.0034.00 by the unit price per print of 8.508.50 yields the total number of prints ordered.

Anahtar Kavram

Solving a linear equation in two variables for one variable when the value of the other variable is given.
Tahmini Süre:45s
Soru 98Soru

In the system of equations below, aa and bb are constants.

3x4y=7ax12y=b\begin{aligned} 3x - 4y &= 7 \\ ax - 12y &= b \end{aligned}

If the system has infinitely many solutions, what is the value of a+ba + b?

Cevabı ve açıklamayı göster

Cevap: 30

Cevap

30
For a system of two linear equations in two variables to have infinitely many solutions, the two equations must represent the same line. Comparing the yy-coefficients shows that 12-12 is 33 times 4-4. Multiplying the first equation by 33 gives the equivalent equation 9x12y=219x - 12y = 21. For this to be identical to the second equation, ax12y=bax - 12y = b, the corresponding coefficients must be equal, meaning a=9a = 9 and b=21b = 21. Therefore, the value of a+ba + b is 9+21=309 + 21 = 30.

Adım Adım Çözüm

1
Identify the condition for a system of linear equations to have infinitely many solutions.
The two equations must represent the same line, making them equivalent equations.
Infinitely many solutions occur when the two equations in a system are scalar multiples of each other.
2
Align the coefficients of the yy-terms in both equations.
Multiplying the first equation by 33 gives 9x12y=219x - 12y = 21.
The coefficient of yy in the second equation is 12-12, which is 33 times the coefficient of yy in the first equation (4-4).
3
Equate the coefficients of the remaining terms to find the values of aa and bb.
a=9a = 9 and b=21b = 21.
For 9x12y=219x - 12y = 21 and ax12y=bax - 12y = b to be equivalent, their corresponding coefficients and constants must be equal.
4
Calculate the value of a+ba + b.
a+b=9+21=30a + b = 9 + 21 = 30.
The problem asks for the value of the sum a+ba + b.

Anahtar Kavram

Determining constants in a system of linear equations with infinitely many solutions
Tahmini Süre:1m 30s
Soru 99Soru

In the xyxy-plane, the graphs of two linear functions, ff and gg, are perpendicular lines that intersect at the point (12,k)(12, k), where kk is a positive constant. If the yy-intercept of the graph of ff is (0,24)(0, 24) and the yy-intercept of the graph of gg is (0,6)(0, -6), what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 18

Cevap

18
To find the value of kk, we determine the slopes of the two lines. The line representing ff passes through (0,24)(0, 24) and (12,k)(12, k), so its slope is mf=k2412m_f = \frac{k - 24}{12}. The line representing gg passes through (0,6)(0, -6) and (12,k)(12, k), so its slope is mg=k+612m_g = \frac{k + 6}{12}. Since the two lines are perpendicular, the product of their slopes is 1-1. This gives the equation (k2412)(k+612)=1\left(\frac{k - 24}{12}\right)\left(\frac{k + 6}{12}\right) = -1. Multiplying both sides by 144144 yields (k24)(k+6)=144(k - 24)(k + 6) = -144. Expanding the left side gives k218k144=144k^2 - 18k - 144 = -144. Adding 144144 to both sides results in k218k=0k^2 - 18k = 0, which factors as k(k18)=0k(k - 18) = 0. Since kk is a positive constant, kk must be 1818.

Adım Adım Çözüm

1
Determine the slopes of the lines ff and gg in terms of kk.
The slope of ff is mf=k24120=k2412m_f = \frac{k - 24}{12 - 0} = \frac{k - 24}{12}. The slope of gg is mg=k(6)120=k+612m_g = \frac{k - (-6)}{12 - 0} = \frac{k + 6}{12}.
We use the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} for each line passing through their respective yy-intercepts and their intersection point (12,k)(12, k).
2
Set up an equation using the perpendicular condition.
mfmg=1    (k2412)(k+612)=1    (k24)(k+6)144=1m_f \cdot m_g = -1 \implies \left(\frac{k - 24}{12}\right)\left(\frac{k + 6}{12}\right) = -1 \implies \frac{(k - 24)(k + 6)}{144} = -1
Since the graphs of ff and gg are perpendicular, the product of their slopes must equal 1-1.
3
Solve the quadratic equation for kk.
(k24)(k+6)=144    k218k144=144    k218k=0    k(k18)=0(k - 24)(k + 6) = -144 \implies k^2 - 18k - 144 = -144 \implies k^2 - 18k = 0 \implies k(k - 18) = 0. Since kk must be positive, k=18k = 18.
Multiplying by 144144, expanding, and factoring the quadratic equation gives the possible values k=0k = 0 and k=18k = 18. The problem states kk is positive, so k=18k = 18.

Anahtar Kavram

Perpendicular lines have slopes that are negative reciprocals of each other, meaning their product is 1-1.
Soru 100Soru

In the xyxy-plane, a line with a negative slope passes through the point (4,3)(4, 3) and intersects the positive xx-axis at (a,0)(a, 0) and the positive yy-axis at (0,b)(0, b). If the area of the triangle formed by this line and the coordinate axes is 2424, what is the value of bb?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

The value of bb is 6.
The correct value is 6. By representing the linear equation in intercept form as xa+yb=1\frac{x}{a} + \frac{y}{b} = 1 and substituting the given point (4,3)(4, 3), we obtain 4a+3b=1\frac{4}{a} + \frac{3}{b} = 1. Using the area of the triangle, 12ab=24\frac{1}{2}ab = 24, we can write a=48ba = \frac{48}{b}. Substituting this into the intercept equation yields b12+3b=1\frac{b}{12} + \frac{3}{b} = 1. Multiplying by 12b12b leads to the quadratic equation b212b+36=0b^2 - 12b + 36 = 0, which factors as (b6)2=0(b-6)^2 = 0, giving the unique solution b=6b = 6.

Adım Adım Çözüm

1
Express the line in intercept form
xa+yb=1\frac{x}{a} + \frac{y}{b} = 1
Since the intercepts are (a,0)(a, 0) and (0,b)(0, b) with a>0a > 0 and b>0b > 0, the intercept form of a linear equation is the most direct representation.
2
Substitute the given point (4,3)(4, 3) into the intercept form
4a+3b=1\frac{4}{a} + \frac{3}{b} = 1
The line passes through (4,3)(4, 3), so these coordinates must satisfy the equation of the line.
3
Express aa in terms of bb using the area of the triangle
a=48ba = \frac{48}{b}
The area of the right triangle with base aa and height bb is 12ab=24\frac{1}{2}ab = 24, which gives ab=48ab = 48.
4
Substitute a=48ba = \frac{48}{b} into the equation from Step 2
b12+3b=1\frac{b}{12} + \frac{3}{b} = 1
This reduces the equation to a single variable bb.
5
Clear denominators and write the equation in standard quadratic form
b212b+36=0b^2 - 12b + 36 = 0
Multiplying both sides by 12b12b allows us to form a quadratic equation.
6
Factor the quadratic equation to solve for bb
b=6b = 6
The quadratic expression is a perfect square trinomial, (b6)2=0(b-6)^2 = 0, which yields b=6b = 6.

Anahtar Kavram

Using the intercept form of a linear equation and geometric properties of linear graphs to solve for unknown parameters.
ÖncekiSayfa 5 / 31Sonraki
Tüm alıştırma soruları — SAT | Examkin