Tüm alıştırma soruları

2789 soru

Soru 1621Soru

In the xyxy-plane, the graph of the quadratic function f(x)=a(x3)(x11)f(x) = a(x-3)(x-11), where aa is a constant, has a vertex at (h,k)(h, k). The graph of the quadratic function g(x)=(xh)2+qg(x) = -(x-h)^2 + q has its vertex at (h,k+8)(h, k+8). If the graphs of ff and gg intersect at a point with an xx-coordinate of 55, what is the value of aa?

Cevabı ve açıklamayı göster

Cevap: 1

Cevap

1
The value of aa is 1. By finding the vertex of f(x)f(x) at (7,16a)(7, -16a) and using the vertex of g(x)g(x) at (7,16a+8)(7, -16a+8), we evaluate both functions at x=5x=5. Setting f(5)=g(5)f(5) = g(5) yields the linear equation 12a=16a+4-12a = -16a + 4, which simplifies to a=1a = 1.

Adım Adım Çözüm

1
Find the x-coordinate of the vertex of f(x)f(x)
h=7h = 7
The x-coordinate of the vertex of a quadratic function of the form f(x)=a(xr1)(xr2)f(x) = a(x-r_1)(x-r_2) is the midpoint of its x-intercepts, r1=3r_1 = 3 and r2=11r_2 = 11.
2
Find the y-coordinate of the vertex of f(x)f(x) in terms of aa
k=16ak = -16a
Evaluate the function at the vertex x-coordinate: f(7)=a(73)(711)=16af(7) = a(7-3)(7-11) = -16a.
3
Write the equation of g(x)g(x) using the given vertex information
g(x)=(x7)2+k+8g(x) = -(x-7)^2 + k+8
The vertex of g(x)g(x) is given as (h,k+8)(h, k+8). Since h=7h = 7, the vertex form of g(x)g(x) is g(x)=(x7)2+k+8g(x) = -(x-7)^2 + k+8.
4
Set up the equation for the intersection point at x=5x = 5
f(5)=g(5)f(5) = g(5)
Since the graphs of ff and gg intersect at x=5x=5, their y-values must be equal at this point.
5
Substitute expressions and solve for aa
a=1a = 1
Evaluate both sides: f(5)=a(53)(511)=12af(5) = a(5-3)(5-11) = -12a, and g(5)=(57)2+k+8=4+k+8=k+4g(5) = -(5-7)^2 + k+8 = -4 + k+8 = k+4. Substituting k=16ak = -16a gives 12a=16a+4    4a=4    a=1-12a = -16a + 4 \implies 4a = 4 \implies a = 1.

Anahtar Kavram

Quadratic Functions and Graphs
Soru 1622Soru

Consider the system of linear equations below:

3x+4y=8ax+8y=15\begin{aligned} 3x + 4y &= 8 \\ ax + 8y &= 15 \end{aligned}

If the system of equations has no solution, and aa is a constant, what is the value of aa?

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Cevap: 6

Cevap

The correct answer is 6.
For a system of linear equations to have no solution, the lines representing the equations must be parallel, which requires them to have the same slope but different y-intercepts. Writing 3x+4y=83x + 4y = 8 in slope-intercept form gives y=34x+2y = -\frac{3}{4}x + 2, so its slope is 34-\frac{3}{4}. Writing ax+8y=15ax + 8y = 15 in slope-intercept form gives y=a8x+158y = -\frac{a}{8}x + \frac{15}{8}, so its slope is a8-\frac{a}{8}. Equating the slopes gives 34=a8-\frac{3}{4} = -\frac{a}{8}. Solving for aa gives a=6a = 6. Since the y-intercepts (22 and 158\frac{15}{8}) are different, the lines are parallel and have no intersection points.

Adım Adım Çözüm

1
Convert the first equation 3x+4y=83x + 4y = 8 to slope-intercept form.
y=34x+2y = -\frac{3}{4}x + 2
To find the slope of the first line, which is 34-\frac{3}{4}.
2
Convert the second equation ax+8y=15ax + 8y = 15 to slope-intercept form.
y=a8x+158y = -\frac{a}{8}x + \frac{15}{8}
To find the slope of the second line in terms of aa, which is a8-\frac{a}{8}.
3
Equate the slopes of the two lines.
34=a8-\frac{3}{4} = -\frac{a}{8}
Parallel lines have the same slope, and a system with parallel lines has no solution.
4
Solve the equation for aa.
a=6a = 6
Isolating the variable aa yields the value of the constant.

Anahtar Kavram

A system of linear equations has no solution if the lines represented by the equations are parallel, meaning they have the same slope but different y-intercepts.
Soru 1623Soru

The table below shows some values for the linear function ff.

xxf(x)f(x)
2255
551414
882323

If the function gg is defined by g(x)=f(x)+kg(x) = f(x) + k, where kk is a constant, and the xx-intercept of the graph of y=g(x)y = g(x) in the xyxy-plane is 2-2, what is the value of kk?

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Cevap: 7

Cevap

The value of kk is 77.
To find the value of kk, we first determine the linear function f(x)f(x) using the values in the table. The slope of ff is calculated as 14552=3\frac{14 - 5}{5 - 2} = 3. Substituting the point (2,5)(2, 5) into the slope-intercept form f(x)=3x+bf(x) = 3x + b gives 5=3(2)+b5 = 3(2) + b, which simplifies to b=1b = -1. Therefore, f(x)=3x1f(x) = 3x - 1. The function gg is defined as g(x)=f(x)+k=3x1+kg(x) = f(x) + k = 3x - 1 + k. Since the xx-intercept of the graph of y=g(x)y = g(x) is 2-2, we must have g(2)=0g(-2) = 0. Substituting x=2x = -2 into the equation for g(x)g(x) gives 3(2)1+k=03(-2) - 1 + k = 0, which simplifies to 7+k=0-7 + k = 0. Solving for kk yields k=7k = 7.

Adım Adım Çözüm

1
Determine the slope of the linear function ff.
The slope of ff is 33.
Using the points (2,5)(2, 5) and (5,14)(5, 14) from the table, the slope is calculated as m=14552=93=3m = \frac{14 - 5}{5 - 2} = \frac{9}{3} = 3.
2
Find the equation for f(x)f(x).
f(x)=3x1f(x) = 3x - 1
Using the slope-intercept form f(x)=3x+bf(x) = 3x + b and the point (2,5)(2, 5), we solve for bb: 5=3(2)+b5 = 3(2) + b, which gives b=1b = -1.
3
Set up the equation for g(x)g(x) and use the xx-intercept to find the value of kk.
k=7k = 7
Since g(x)=f(x)+kg(x) = f(x) + k, we have g(x)=3x1+kg(x) = 3x - 1 + k. The xx-intercept of g(x)g(x) is 2-2, so g(2)=0g(-2) = 0. This gives 3(2)1+k=03(-2) - 1 + k = 0, which simplifies to 7+k=0-7 + k = 0, meaning k=7k = 7.

Anahtar Kavram

Finding the equation of a linear function from tabular data and applying translations and intercepts.
Soru 1624Soru

The population of a certain species of wildflower in a national park increases by 300%300\% every 88 years. The population can be modeled by the function P(t)=P0(1+r)tP(t) = P_0(1 + r)^t, where P0P_0 is the initial population, rr is the constant annual growth rate, and tt is the time in years. Which of the following is closest to the value of rr?

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Cevap: 0.19

Cevap

The correct value of the annual growth rate is 0.190.19.
An increase of 300%300\% means the population becomes 100%+300%=400%100\% + 300\% = 400\% of its initial value, which corresponds to a growth factor of 44 over an 88-year period. The annual growth rate rr satisfies the equation (1+r)8=4(1 + r)^8 = 4. Solving for 1+r1 + r gives 1+r=41/8=(22)1/8=21/41.18921 + r = 4^{1/8} = (2^2)^{1/8} = 2^{1/4} \approx 1.1892. Subtracting 11 from both sides yields the annual growth rate r0.1892r \approx 0.1892, which is closest to 0.190.19.

Adım Adım Çözüm

1
Determine the total growth factor over the 8-year period from the percentage increase.
The population increases by 300%300\%, meaning the new population is 100%+300%=400%100\% + 300\% = 400\% of the initial population. This corresponds to a growth factor of 44 every 88 years.
An increase of 300%300\% adds 33 times the original value to the original value, resulting in a total of 44 times the original value.
2
Set up the equation relating the annual growth rate rr to the 8-year growth factor.
(1+r)8=4(1+r)^8 = 4
Since the population is multiplied by 1+r1+r each year, after 88 years it is multiplied by (1+r)8(1+r)^8, which must equal the total growth factor of 44.
3
Solve the equation for rr and round to the nearest hundredth.
1+r=41/81.1892    r0.18920.191+r = 4^{1/8} \approx 1.1892 \implies r \approx 0.1892 \approx 0.19
Taking the eighth root of both sides gives the annual growth factor 1+r1.191+r \approx 1.19. Subtracting 11 isolates the annual growth rate rr.

Anahtar Kavram

Relating exponential growth rates and growth factors across different time periods

Alternatif Yöntem

Instead of solving (1+r)8=4(1+r)^8 = 4, we can write the function directly using the 8-year growth factor as P(t)=P04t/8P(t) = P_0 \cdot 4^{t/8}. Rewriting this in the form P(t)=P0(41/8)tP(t) = P_0(4^{1/8})^t shows that the annual growth factor is 41/84^{1/8}. We can approximate 41/81.18924^{1/8} \approx 1.1892, which corresponds to an annual growth rate r=1.18921=0.1892r = 1.1892 - 1 = 0.1892, or approximately 0.190.19.
Tahmini Süre:1m 30s
Soru 1625Soru

If 42x+1=8x14^{2x + 1} = 8^{x - 1}, what is the value of xx?

Cevabı ve açıklamayı göster

Cevap: -5

Cevap

-5
The correct answer is 5-5. By converting the bases of both sides to 22, the equation becomes 22(2x+1)=23(x1)2^{2(2x+1)} = 2^{3(x-1)}. Equating the exponents gives 2(2x+1)=3(x1)2(2x+1) = 3(x-1), which expands to 4x+2=3x34x+2 = 3x-3. Solving for xx yields x=5x = -5.

Adım Adım Çözüm

1
Express both bases as powers of 2
4=224 = 2^2 and 8=238 = 2^3
To solve an exponential equation, we need to rewrite the terms with a common base.
2
Substitute the bases back into the equation and apply exponent power rules
(22)2x+1=(23)x122(2x+1)=23(x1)(2^2)^{2x + 1} = (2^3)^{x - 1} \Rightarrow 2^{2(2x + 1)} = 2^{3(x - 1)}
Applying the power of a power property, (bm)n=bmn(b^m)^n = b^{mn}, allows us to simplify the exponents.
3
Set the exponents equal to each other
2(2x+1)=3(x1)2(2x + 1) = 3(x - 1)
Since the bases are identical and positive, their exponents must be equal.
4
Distribute and solve the linear equation for xx
4x+2=3x3x=54x + 2 = 3x - 3 \Rightarrow x = -5
Distributing the constants gives 4x+2=3x34x + 2 = 3x - 3. Subtracting 3x3x from both sides gives x+2=3x + 2 = -3, and subtracting 22 from both sides isolates the variable to find x=5x = -5.

Anahtar Kavram

Solving exponential equations by expressing both sides with a common base
Soru 1626Soru

First developed in the classical world, the astrolabe was a sophisticated analog calculator used by astronomers and navigators to solve problems relating to time and the position of celestial bodies. In the medieval Islamic world, scholars made significant advancements to the instrument's design ______ they added specialized plates that allowed users to determine the precise times of daily prayers and align themselves toward Mecca.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: design: they

Cevap

design: they
The correct option correctly uses a colon to connect two independent clauses. The clause preceding the colon is independent, and the clause following it is also independent and directly explains the advancements made to the design. This meets the grammatical criteria for colon usage.

Adım Adım Çözüm

1
Analyze the clause before the blank.
The clause 'In the medieval Islamic world, scholars made significant advancements to the instrument's design' is independent because it contains a subject ('scholars') and a verb ('made') and can stand alone as a complete sentence.
Identifying the grammatical nature of the first clause helps determine what punctuation can follow it.
2
Analyze the clause after the blank.
The clause 'they added specialized plates that allowed users to determine the precise times of daily prayers and align themselves toward Mecca' is also independent because it contains a subject ('they') and a verb ('added') and can stand alone.
Knowing that both clauses are independent narrows down the correct punctuation options to those that can join independent clauses.
3
Determine the logical relationship between the two clauses.
The second clause explains and elaborates on the specific 'significant advancements' mentioned in the first clause.
A colon is appropriate here because it introduces an explanation or elaboration of the preceding independent clause.

Anahtar Kavram

Colons are used to join two independent clauses when the second clause explains, illustrates, or details the first.
Soru 1627Soru

The quadratic equation x2(k+3)x+(2k+3)=0x^2 - (k + 3)x + (2k + 3) = 0 has exactly one real solution, where kk is a constant. If k>1k > 1, what is the value of kk?

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Cevap: 3

Cevap

The value of kk is 33.
For the quadratic equation to have exactly one real solution, its discriminant must be equal to 00. Setting the discriminant of x2(k+3)x+(2k+3)=0x^2 - (k + 3)x + (2k + 3) = 0 to 00 yields [(k+3)]24(1)(2k+3)=0[-(k + 3)]^2 - 4(1)(2k + 3) = 0. Simplifying this yields k22k3=0k^2 - 2k - 3 = 0, which factors as (k3)(k+1)=0(k - 3)(k + 1) = 0. This gives two potential values for kk: 33 and 1-1. Because the problem specifies that k>1k > 1, the value of kk must be 33.

Adım Adım Çözüm

1
Identify the coefficients of the quadratic equation and state the condition for having exactly one real solution.
The coefficients of the quadratic equation x2(k+3)x+(2k+3)=0x^2 - (k + 3)x + (2k + 3) = 0 are a=1a = 1, b=(k+3)b = -(k + 3), and c=2k+3c = 2k + 3. For a quadratic equation to have exactly one real solution, its discriminant b24acb^2 - 4ac must equal 00.
A discriminant of zero indicates that the quadratic equation has two equal real roots, which is equivalent to exactly one distinct real solution.
2
Set up the discriminant equation in terms of kk and simplify it.
[(k+3)]24(1)(2k+3)=0[-(k + 3)]^2 - 4(1)(2k + 3) = 0
(k2+6k+9)(8k+12)=0(k^2 + 6k + 9) - (8k + 12) = 0
k22k3=0k^2 - 2k - 3 = 0
This algebraic expansion and simplification transforms the discriminant condition into a solvable quadratic equation for kk.
3
Solve the quadratic equation k22k3=0k^2 - 2k - 3 = 0 by factoring.
(k3)(k+1)=0(k - 3)(k + 1) = 0, which gives k=3k = 3 or k=1k = -1.
Factoring is the most direct method to find the roots of this quadratic equation.
4
Apply the constraint k>1k > 1 to select the correct value of kk.
Since kk must be greater than 11, the value k=1k = -1 is discarded, leaving k=3k = 3.
The solution must satisfy all given constraints in the problem statement.

Anahtar Kavram

Discriminant of a Quadratic Equation

Alternatif Yöntem

Instead of solving the quadratic equation algebraically, you can test the given choices for kk. For the correct option of 33, substituting k=3k = 3 into the original equation yields x26x+9=0x^2 - 6x + 9 = 0. Factoring this expression gives (x3)2=0(x - 3)^2 = 0, which clearly has exactly one real solution (x=3x = 3). Testing the other options would not produce a perfect square trinomial.
Tahmini Süre:2m 0s
Soru 1628Soru

For the 1900 Paris Exposition, sociologist W.E.B. Du Bois and his research team created dozens of vibrant, hand-drawn charts to document the progress of Black Americans after the Civil War. The ________ meticulous handiwork, which was presented in a dedicated exhibition, challenged prevailing racist theories of the era by showcasing empirical evidence of economic, social, and educational advancement.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: researchers'

Cevap

researchers'
The context established by the mention of a research team indicates that multiple people collaborated on the charts, meaning a plural noun is needed. Furthermore, because these individuals own the 'meticulous handiwork,' a possessive noun is required. The plural possessive form is 'researchers'.

Adım Adım Çözüm

1
Determine if the noun should be singular or plural.
Plural
The context mentions W.E.B. Du Bois and his research team, indicating multiple members contributed to the work.
2
Determine if the noun should be possessive or non-possessive.
Possessive
The noun modifies the noun phrase 'meticulous handiwork,' showing ownership of the handiwork by the team members.
3
Select the correct plural possessive spelling.
researchers'
The plural possessive of 'researcher' is formed by adding an apostrophe after the final 's' of the plural noun.

Anahtar Kavram

Plural and Possessive Nouns and Pronouns
Soru 1629Soru

Consider the system of equations below:

y=2x2+kx+9y=2x+1\begin{aligned} y &= 2x^2 + kx + 9 \\ y &= -2x + 1 \end{aligned}

In the system of equations above, kk is a positive constant. If the system has exactly one real solution, what is the value of kk?

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Cevap: 6

Cevap

The value of the positive constant kk is 6.
By substituting the linear equation into the quadratic equation, we obtain the equation 2x2+(k+2)x+8=02x^2 + (k+2)x + 8 = 0. For the system to have exactly one real solution, the discriminant of this quadratic equation, Δ=b24ac\Delta = b^2 - 4ac, must be equal to zero. Substituting a=2a = 2, b=k+2b = k+2, and c=8c = 8 into the discriminant formula gives (k+2)24(2)(8)=0(k+2)^2 - 4(2)(8) = 0, which simplifies to (k+2)2=64(k+2)^2 = 64. Solving for kk gives k+2=8k+2 = 8 or k+2=8k+2 = -8, resulting in k=6k = 6 or k=10k = -10. Since kk is specified to be a positive constant, the value of kk must be 6.

Adım Adım Çözüm

1
Substitute the expression for yy from the linear equation into the quadratic equation.
2x2+kx+9=2x+12x^2 + kx + 9 = -2x + 1
Setting the two expressions for yy equal to each other allows us to solve for the xx-coordinates of the intersection points.
2
Rearrange the equation into the standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.
2x2+(k+2)x+8=02x^2 + (k+2)x + 8 = 0
Grouping the terms by power of xx lets us identify the coefficients a=2a = 2, b=k+2b = k+2, and c=8c = 8.
3
Set the discriminant of the quadratic equation to zero.
(k+2)24(2)(8)=0(k+2)^2 - 4(2)(8) = 0, which simplifies to (k+2)264=0(k+2)^2 - 64 = 0
A quadratic equation has exactly one real solution if and only if its discriminant, b24acb^2 - 4ac, is equal to zero.
4
Solve for the positive constant kk.
k=6k = 6
Solving (k+2)2=64(k+2)^2 = 64 yields k+2=8k+2 = 8 or k+2=8k+2 = -8, which means k=6k = 6 or k=10k = -10. Since kk must be a positive constant, we select 6.

Anahtar Kavram

Determining the number of solutions of a quadratic-linear system using the discriminant.

Alternatif Yöntem

Alternatively, the quadratic equation 2x2+(k+2)x+8=02x^2 + (k+2)x + 8 = 0 has exactly one real solution when it is a perfect square trinomial. Factoring out the leading coefficient gives 2(x2+k+22x+4)=02(x^2 + \frac{k+2}{2}x + 4) = 0. For the term inside the parentheses to be a perfect square trinomial of the form x2+2dx+d2x^2 + 2dx + d^2, we must have d2=4d^2 = 4, which means d=±2d = \pm 2. Thus, the middle coefficient k+22\frac{k+2}{2} must equal 2d=±42d = \pm 4. Since kk is positive, we set k+22=4\frac{k+2}{2} = 4, which solves to k=6k = 6.
Tahmini Süre:1m 30s
Soru 1630Soru

What is the solution to the equation 3x+13=x+3\sqrt{3x + 13} = x + 3?

Cevabı ve açıklamayı göster

Cevap: 1

Cevap

1
The value 11 is the correct answer because substituting it back into the original equation results in a true mathematical statement: 3(1)+13=1+3\sqrt{3(1) + 13} = 1 + 3, which simplifies to 4=44 = 4.

Adım Adım Çözüm

1
Square both sides of the equation to eliminate the radical.
3x+13=(x+3)23x + 13 = (x + 3)^2
Squaring both sides is the standard method to solve equations containing square roots.
2
Expand the right side of the equation.
3x+13=x2+6x+93x + 13 = x^2 + 6x + 9
Expanding the squared binomial gives a quadratic expression.
3
Move all terms to one side to set the quadratic equation to zero.
x2+3x4=0x^2 + 3x - 4 = 0
Setting the quadratic equation to zero allows us to solve for xx by factoring.
4
Factor the quadratic equation.
(x+4)(x1)=0(x + 4)(x - 1) = 0
Finding two numbers that multiply to 4-4 and add to 33 gives the binomial factors.
5
Solve for the potential values of xx.
x=4x = -4 or x=1x = 1
Setting each factor equal to zero yields the potential solutions.
6
Substitute each potential solution back into the original equation to check for extraneous solutions.
For x=1x = 1: 3(1)+13=1+34=4\sqrt{3(1) + 13} = 1 + 3 \Rightarrow 4 = 4 (valid). For x=4x = -4: 3(4)+13=4+31=1\sqrt{3(-4) + 13} = -4 + 3 \Rightarrow 1 = -1 (invalid). Thus, the only solution is 11.
Squaring both sides can introduce extraneous solutions, so checking all potential solutions in the original equation is necessary to verify their validity.

Anahtar Kavram

Solving radical equations by squaring both sides and checking for extraneous solutions.
Soru 1631Soru

In the mid-twentieth century, archaeologists restoring the frescoes of Pompeii faced a significant dilemma: the paraffin wax coating applied by early conservators to preserve the paintings had instead darkened over time. This obscured the vibrant pigments underneath _______ conservators had to develop novel chemical solvents that could selectively dissolve the wax without damaging the ancient plaster.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: ; consequently,

Cevap

; consequently,
The correct choice uses a semicolon to separate two independent clauses, followed by the conjunctive adverb 'consequently' and a comma to logically connect the cause (obscured pigments) and the effect (the need for new solvents).

Adım Adım Çözüm

1
Identify the clause boundary in the sentence.
The sentence contains two independent clauses: 'This obscured the vibrant pigments underneath' and 'conservators had to develop novel chemical solvents...'.
Locating the boundary helps determine the type of punctuation or conjunction needed to connect them grammatically.
2
Evaluate the relationship between the two clauses.
The second clause describes the result or consequence of the first clause (the obscured pigments led to the development of new solvents).
This determines the appropriate transitional word to use.
3
Select the option that conforms to standard English conventions for linking two independent clauses.
The option containing a semicolon followed by 'consequently' and a comma is the correct choice, as it avoids run-on or comma splice errors while conveying the correct cause-and-effect relationship.
A semicolon is required to link two independent clauses when not using a coordinating conjunction (like 'and' or 'so').

Anahtar Kavram

Linking independent clauses using appropriate punctuation and conjunctive adverbs.
Tahmini Süre:1m 0s
Soru 1632Soru

The function ff is defined by f(x)=(x5)2+4f(x) = -(x - 5)^2 + 4. What is the maximum value of the function ff?

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Cevap: 44

Cevap

The maximum value of the function is 4.
The quadratic function f(x)=(x5)2+4f(x) = -(x - 5)^2 + 4 is in vertex form f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where the vertex of the parabola is (h,k)=(5,4)(h, k) = (5, 4). Because the leading coefficient a=1a = -1 is negative, the parabola opens downward, which means the vertex is the highest point on the graph. The maximum value of the function is the y-coordinate of this vertex, which is 4.

Adım Adım Çözüm

1
Identify the form of the quadratic function.
The function f(x)=(x5)2+4f(x) = -(x - 5)^2 + 4 is written in vertex form, f(x)=a(xh)2+kf(x) = a(x - h)^2 + k.
Recognizing the vertex form allows us to directly identify the vertex coordinates of the parabola.
2
Identify the vertex (h,k)(h, k) and the direction the parabola opens.
The vertex is (5,4)(5, 4) and the leading coefficient is a=1a = -1.
Since the leading coefficient aa is negative, the parabola opens downward, meaning the vertex is the highest point on the graph.
3
Determine the maximum value of the function.
The maximum value of the function is the y-coordinate of the vertex, which is 4.
The maximum value of a function refers to its largest output (y-value), which corresponds to the y-coordinate of its highest point.

Anahtar Kavram

Quadratic Functions and Graphs
Soru 1633Soru

The temperature, TT, in degrees Fahrenheit (F^\circ\text{F}), of a laboratory incubator mm minutes after a cooling cycle begins is modeled by the equation T=950.8(2m5)T = 95 - 0.8(2m - 5). For a specific experiment, the incubator temperature must be at most 75F75^\circ\text{F}. Which of the following inequalities represents all possible values of mm for which the incubator temperature meets this requirement?

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Cevap: m15m \geq 15

Cevap

The correct inequality is m15m \geq 15.
The correct inequality is m15m \geq 15. To find this, set the temperature model 950.8(2m5)95 - 0.8(2m - 5) to be less than or equal to 7575. Subtracting 9595 from both sides gives 0.8(2m5)20-0.8(2m - 5) \leq -20. Dividing both sides by 0.8-0.8 requires flipping the inequality sign, which yields 2m5252m - 5 \geq 25. Adding 55 to both sides gives 2m302m \geq 30, and dividing by 22 yields m15m \geq 15.

Adım Adım Çözüm

1
Set up the inequality based on the requirement that the temperature must be at most 75F75^\circ\text{F}.
950.8(2m5)7595 - 0.8(2m - 5) \leq 75
The phrase 'at most' corresponds to a less-than-or-equal-to sign.
2
Subtract 9595 from both sides of the inequality.
0.8(2m5)20-0.8(2m - 5) \leq -20
This begins the process of isolating the term containing the variable mm.
3
Divide both sides by 0.8-0.8 and flip the inequality sign.
2m5252m - 5 \geq 25
Dividing both sides of an inequality by a negative number requires reversing the direction of the inequality sign.
4
Add 55 to both sides of the inequality.
2m302m \geq 30
This isolates the variable term 2m2m.
5
Divide both sides by 22 to solve for mm.
m15m \geq 15
This yields the solution set for the variable mm.

Anahtar Kavram

Solving multi-step linear inequalities in one variable, specifically expanding using the distributive property and reversing the inequality sign when multiplying or dividing by a negative number.
Soru 1634Soru

A researcher monitors the temperature of a chemical compound during an experiment. The temperature, TT, in degrees Celsius, of the compound mm minutes after heating begins can be modeled by a linear relationship. The temperature increases by 4.54.5 degrees Celsius every 22 minutes. If the temperature of the compound was 12-12 degrees Celsius when heating began, after how many minutes will the temperature of the compound reach 1515 degrees Celsius?

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Cevap: 12

Cevap

The temperature of the compound will reach 1515 degrees Celsius after 1212 minutes.
The correct answer is 1212 because the temperature increases at a constant rate of 2.252.25 degrees Celsius per minute. Starting from an initial temperature of 12-12 degrees Celsius, the equation is T=2.25m12T = 2.25m - 12. Setting T=15T = 15 gives 15=2.25m1215 = 2.25m - 12, which simplifies to 27=2.25m27 = 2.25m, resulting in m=12m = 12.

Adım Adım Çözüm

1
Calculate the constant rate of temperature increase per minute.
2.252.25 degrees Celsius per minute
This rate represents the slope of the linear relationship between time and temperature.
2
Formulate the linear equation representing the temperature TT as a function of the elapsed minutes mm.
T=2.25m12T = 2.25m - 12
The slope is 2.252.25 and the vertical intercept is the initial temperature of 12-12 degrees Celsius.
3
Set T=15T = 15 and solve the linear equation for mm.
m=12m = 12
This determines the exact number of minutes needed for the temperature to reach 1515 degrees Celsius.

Anahtar Kavram

Interpreting and solving linear equations modeled from context
Soru 1635Soru

To restore a depleted wetland, conservationists pump water into a basin. The volume of water in the basin, WW, in thousands of gallons, tt hours after the pumping begins is modeled by the equation W=12.5t+85W = 12.5t + 85. According to the model, how many hours of pumping are required for the volume of water in the basin to increase by 150150 thousand gallons?

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Cevap: 12

Cevap

12
The linear equation is given in slope-intercept form, W=mt+bW = mt + b, where m=12.5m = 12.5 is the slope and b=85b = 85 is the y-intercept. In this context, the slope m=12.5m = 12.5 represents the rate at which water is pumped into the basin, which is 12.512.5 thousand gallons per hour. To find the number of hours required for the volume of water to increase by 150150 thousand gallons, divide the total increase by the rate: 15012.5=12\frac{150}{12.5} = 12 hours.

Adım Adım Çözüm

1
Identify the rate of water volume increase per hour from the equation.
The rate is 12.512.5 thousand gallons per hour.
In the linear equation W=12.5t+85W = 12.5t + 85, the coefficient of tt (the slope) represents the rate of change of the water volume with respect to time.
2
Set up a relation to find the time tt for a volume increase of 150150 thousand gallons.
12.5t=15012.5t = 150
The change in volume is equal to the rate of change multiplied by the time elapsed.
3
Solve the equation for tt.
t=12t = 12
Dividing both sides of the equation 12.5t=15012.5t = 150 by 12.512.5 isolates tt.

Anahtar Kavram

Interpreting the slope of a linear equation in context as a rate of change.
Tahmini Süre:1m 30s
Soru 1636Soru

In the xyxy-plane, a system of equations consists of the circle with equation (x7)2+(y4)2=1(x - 7)^2 + (y - 4)^2 = 1 and the line y=kxy = kx, where kk is a positive constant. If the system has exactly one real solution and k>0.5k > 0.5, what is the value of kk?

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Cevap: 0.75

Cevap

The correct answer is 3/4 (or 0.75).
The correct answer is 3/43/4 (or 0.750.75). Substituting the line y=kxy = kx into the circle equation and setting the discriminant of the resulting quadratic equation to zero yields a quadratic in kk: 48k256k+15=048k^2 - 56k + 15 = 0. Solving this equation gives two positive tangent slopes: k=5/12k = 5/12 and k=3/4k = 3/4. Since the problem specifies that k>0.5k > 0.5, we choose k=3/4k = 3/4, which equals 0.750.75. Alternatively, using geometry, the distance from the center (7,4)(7,4) to the line kxy=0kx - y = 0 must equal the radius 11. This gives 7k4k2+1=1\frac{|7k-4|}{\sqrt{k^2+1}} = 1. Squaring both sides yields (7k4)2=k2+1(7k-4)^2 = k^2+1, which simplifies to 48k256k+15=048k^2 - 56k + 15 = 0, giving the same values of kk.

Adım Adım Çözüm

1
Substitute the linear equation y=kxy = kx into the circle's quadratic equation (x7)2+(y4)2=1(x - 7)^2 + (y - 4)^2 = 1.
(x7)2+(kx4)2=1(x - 7)^2 + (kx - 4)^2 = 1
To find the points of intersection between the line and the circle, substitute the expression for yy from the linear equation into the circle's equation.
2
Expand the terms and write the equation in the standard quadratic form Ax2+Bx+C=0Ax^2 + Bx + C = 0.
(1+k2)x2(14+8k)x+64=0(1 + k^2)x^2 - (14 + 8k)x + 64 = 0
Expanding (x7)2(x - 7)^2 yields x214x+49x^2 - 14x + 49 and expanding (kx4)2(kx - 4)^2 yields k2x28kx+16k^2x^2 - 8kx + 16. Grouping the terms by powers of xx and subtracting 11 from both sides gives the standard form.
3
Set the discriminant of the quadratic equation to 00 to satisfy the condition of exactly one real solution.
Δ=[(14+8k)]24(1+k2)(64)=0\Delta = [-(14 + 8k)]^2 - 4(1 + k^2)(64) = 0
A quadratic equation has exactly one real solution if and only if its discriminant, B24ACB^2 - 4AC, is equal to zero. Geometrically, this means the line is tangent to the circle.
4
Simplify the discriminant equation and solve for kk.
48k256k+15=048k^2 - 56k + 15 = 0, which factors as (12k5)(4k3)=0(12k - 5)(4k - 3) = 0. Thus, k=512k = \frac{5}{12} or k=34k = \frac{3}{4}.
Simplifying (14+8k)2256(1+k2)=0(14 + 8k)^2 - 256(1 + k^2) = 0 gives 196+224k+64k2256256k2=0196 + 224k + 64k^2 - 256 - 256k^2 = 0, which simplifies to 192k2+224k60=0-192k^2 + 224k - 60 = 0. Dividing the entire equation by 4-4 yields the quadratic equation in kk.
5
Select the value of kk that satisfies the given condition k>0.5k > 0.5.
k=34k = \frac{3}{4} (or 0.750.75)
Since 5120.417\frac{5}{12} \approx 0.417 is less than 0.50.5 and 34=0.75\frac{3}{4} = 0.75 is greater than 0.50.5, the correct value is 3/43/4.

Anahtar Kavram

Solving a nonlinear system of equations involving a circle and a line by setting the discriminant of the substituted quadratic equation to zero to find the slope of the tangent lines.
Tahmini Süre:2m 30s
Soru 1637Soru

A circle and a line intersect at two points in the xyxy-plane. The equations of the circle and the line are:

(x3)2+y2=25(x - 3)^2 + y^2 = 25
y=x2y = x - 2

If (x1,y1)(x_1, y_1) is the intersection point in Quadrant I and (x2,y2)(x_2, y_2) is the intersection point in Quadrant III, what is the value of x1+y2x_1 + y_2?

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Cevap: 3

Cevap

The value of x1+y2x_1 + y_2 is 3.
To solve the system, we substitute the linear equation y=x2y = x - 2 into the circle equation, obtaining (x3)2+(x2)2=25(x - 3)^2 + (x - 2)^2 = 25. Expanding this gives x26x+9+x24x+4=25x^2 - 6x + 9 + x^2 - 4x + 4 = 25, which simplifies to 2x210x12=02x^2 - 10x - 12 = 0. Dividing by 2, we get x25x6=0x^2 - 5x - 6 = 0, which factors as (x6)(x+1)=0(x - 6)(x + 1) = 0. The solutions are x=6x = 6 and x=1x = -1. Substituting these back into the linear equation gives the points of intersection: (6,4)(6, 4) in Quadrant I (since both coordinates are positive) and (1,3)(-1, -3) in Quadrant III (since both coordinates are negative). Therefore, x1=6x_1 = 6 and y2=3y_2 = -3, and their sum is 6+(3)=36 + (-3) = 3. This matches the correct option.

Adım Adım Çözüm

1
Substitute the linear equation into the circle equation to obtain an equation in terms of xx only.
(x3)2+(x2)2=25(x - 3)^2 + (x - 2)^2 = 25
This reduces the system to a single quadratic equation in one variable, allowing us to find the x-coordinates of the intersection points.
2
Expand and simplify the quadratic equation into standard form.
x26x+9+x24x+4=25    2x210x12=0    x25x6=0x^2 - 6x + 9 + x^2 - 4x + 4 = 25 \implies 2x^2 - 10x - 12 = 0 \implies x^2 - 5x - 6 = 0
Simplifying the equation makes it solvable by standard quadratic factoring methods.
3
Solve the simplified quadratic equation for xx by factoring.
(x6)(x+1)=0    x=6(x - 6)(x + 1) = 0 \implies x = 6 or x=1x = -1
The roots of this quadratic equation are the x-coordinates of the two intersection points.
4
Find the corresponding yy-coordinates by substituting the xx-values back into the linear equation y=x2y = x - 2.
For x=6x = 6, y=62=4y = 6 - 2 = 4, giving the point (6,4)(6, 4) in Quadrant I. For x=1x = -1, y=12=3y = -1 - 2 = -3, giving the point (1,3)(-1, -3) in Quadrant III.
This yields the coordinates of the two points of intersection and identifies which point lies in which quadrant.
5
Identify x1x_1 and y2y_2 and calculate the sum x1+y2x_1 + y_2.
x1=6x_1 = 6 and y2=3y_2 = -3, so x1+y2=6+(3)=3x_1 + y_2 = 6 + (-3) = 3.
This answers the specific question using the coordinate components of the two points.

Anahtar Kavram

Nonlinear Systems of Equations
Soru 1638Soru

In medieval Europe, the master builders of Gothic cathedrals sought to achieve unprecedented heights and incorporate expansive stained-glass windows. To prevent the massive stone vaults from collapsing outward, they developed flying _______ these external arched supports redistributed the lateral thrust of the roof down to heavy masonry piers on the exterior of the building.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: buttresses;

Cevap

buttresses;
The correct answer is the option containing only a semicolon. The passage contains two independent clauses: the first ends with the development of the buttresses, and the second begins with the explanation of how these supports redistributed the lateral thrust of the roof. A semicolon is the standard punctuation mark used to link two independent clauses without a coordinating conjunction.

Adım Adım Çözüm

1
Identify the clause boundaries in the sentence.
The sentence contains two independent clauses: 'they developed flying buttresses' and 'these external arched supports redistributed the lateral thrust of the roof down to heavy masonry piers on the exterior of the building.' Each of these clauses has a subject and a verb and can stand alone as a complete sentence.
Before deciding on punctuation, it is necessary to determine if the clauses being linked are independent or dependent.
2
Evaluate the grammar rules for linking two independent clauses.
Two independent clauses can be joined by a period, a semicolon, a colon (if the second explains the first), or a comma followed by a coordinating conjunction (FANBOYS). They cannot be joined by a comma alone or with no punctuation at all.
This narrows down the correct grammatical structures.
3
Evaluate the choices against the grammatical and logical requirements.
The option containing only a semicolon correctly links the two clauses. The option with a comma creates an ungrammatical comma splice. The option with no punctuation creates a run-on sentence. The option with 'but' is grammatically structured but logically incorrect, as there is no relationship of contrast between the clauses.
This identifies the correct choice and eliminates the distractors.

Anahtar Kavram

Clause Boundaries and Linking
Soru 1639Soru

If 9y132y=27y+29^{y - 1} \cdot 3^{2y} = 27^{y + 2}, what is the value of yy?

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Cevap: 8

Cevap

8
To solve the equation, we rewrite each term using the common base of 33. Since 9=329 = 3^2 and 27=3327 = 3^3, the equation 9y132y=27y+29^{y - 1} \cdot 3^{2y} = 27^{y + 2} can be written as (32)y132y=(33)y+2(3^2)^{y-1} \cdot 3^{2y} = (3^3)^{y+2}. Applying the power of a power rule, we get 32(y1)32y=33(y+2)3^{2(y-1)} \cdot 3^{2y} = 3^{3(y+2)}, which simplifies to 32y232y=33y+63^{2y-2} \cdot 3^{2y} = 3^{3y+6}. Using the product rule of exponents to combine the left side gives 32y2+2y=34y2=33y+63^{2y-2+2y} = 3^{4y-2} = 3^{3y+6}. Setting the exponents equal to each other gives the linear equation 4y2=3y+64y - 2 = 3y + 6. Solving for yy yields y=8y = 8.

Adım Adım Çözüm

1
Express all bases in the equation as powers of 3.
9y1=(32)y1=32y29^{y-1} = (3^2)^{y-1} = 3^{2y-2} and 27y+2=(33)y+2=33y+627^{y+2} = (3^3)^{y+2} = 3^{3y+6}. The original equation becomes 32y232y=33y+63^{2y-2} \cdot 3^{2y} = 3^{3y+6}.
Having a common base allows us to combine exponents using the properties of exponents.
2
Simplify the left side of the equation by adding the exponents.
3(2y2)+2y=34y23^{(2y-2) + 2y} = 3^{4y-2}, so the equation is 34y2=33y+63^{4y-2} = 3^{3y+6}.
When multiplying exponential expressions with the same base, we add their exponents.
3
Set the exponents equal to each other and solve for yy.
4y2=3y+6    y2=6    y=84y - 2 = 3y + 6 \implies y - 2 = 6 \implies y = 8.
Since the bases are equal and positive (and not equal to 1), their exponents must be equal.

Anahtar Kavram

Solving exponential equations by expressing terms with a common base and applying exponent laws.
Tahmini Süre:1m 30s
Soru 1640Soru

If (18)2x3=16x2\left(\frac{1}{8}\right)^{2x - 3} = 16^{x - 2}, what is the value of xx?

Cevabı ve açıklamayı göster

Cevap: 1.7

Cevap

1.7 (or 17/10)
The correct answer is 1.7 (or 17/10). By writing 18\frac{1}{8} as 232^{-3} and 1616 as 242^4, the equation becomes (23)2x3=(24)x2(2^{-3})^{2x - 3} = (2^4)^{x - 2}. Applying exponent rules yields 26x+9=24x82^{-6x + 9} = 2^{4x - 8}. Equating the exponents gives 6x+9=4x8-6x + 9 = 4x - 8, which simplifies to 10x=1710x = 17, resulting in x=1.7x = 1.7.

Adım Adım Çözüm

1
Express both bases as powers of 22.
(23)2x3=(24)x2(2^{-3})^{2x - 3} = (2^4)^{x - 2}
To solve the exponential equation, both sides must have a common base. Both 18\frac{1}{8} and 1616 can be rewritten as powers of 22.
2
Apply the power-of-a-power exponent rule (am)n=amn(a^m)^n = a^{mn} to simplify the exponents.
23(2x3)=24(x2)2^{-3(2x - 3)} = 2^{4(x - 2)}, which simplifies to 26x+9=24x82^{-6x + 9} = 2^{4x - 8}
This allows us to write each side as a single exponential term with a base of 22.
3
Set the exponents equal to each other.
6x+9=4x8-6x + 9 = 4x - 8
Since the bases are equal, their exponents must be equal for the equation to hold.
4
Solve the linear equation for xx.
10x=1710x = 17, which gives x=1.7x = 1.7
Isolate the variable xx by algebraic manipulation.

Anahtar Kavram

Solving exponential equations by expressing terms with a common base and applying exponent rules.

Alternatif Yöntem

Alternatively, you can apply the definition of logarithms to both sides of the equation. Taking the logarithm base 2 of both sides gives log2((18)2x3)=log2(16x2)\log_2\left(\left(\frac{1}{8}\right)^{2x-3}\right) = \log_2\left(16^{x-2}\right). Using the power property of logarithms, this simplifies to (2x3)log2(23)=(x2)log2(24)(2x - 3)\log_2\left(2^{-3}\right) = (x - 2)\log_2\left(2^4\right), which simplifies directly to 3(2x3)=4(x2)-3(2x - 3) = 4(x - 2). Solving this linear equation yields the same result, x=1.7x = 1.7.
Tahmini Süre:1m 30s
ÖncekiSayfa 82 / 140Sonraki
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