Tüm alıştırma soruları

2789 soru

Soru 1921Soru

A quadratic function ff has its vertex at (4,3)(4, -3) in the coordinate plane. The point (2,5)(2, 5) is on the graph of y=f(x)y = f(x). The function gg is defined by g(x)=f(x3)+8g(x) = -f(x - 3) + 8. What is the value of g(8)g(8)?

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Cevap: 9

Cevap

The correct answer is 9.
The correct answer is 9. To find this, we first establish the vertex form of the quadratic function f(x)=a(x4)23f(x) = a(x - 4)^2 - 3. Substituting the point (2,5)(2, 5) gives 5=a(24)235 = a(2 - 4)^2 - 3, which simplifies to 8=4a8 = 4a, so a=2a = 2. Thus, f(x)=2(x4)23f(x) = 2(x - 4)^2 - 3. To find the value of g(8)g(8), we substitute 88 into the definition of g(x)g(x), yielding g(8)=f(83)+8=f(5)+8g(8) = -f(8 - 3) + 8 = -f(5) + 8. Evaluating f(5)f(5) gives 2(54)23=12(5 - 4)^2 - 3 = -1. Finally, substituting 1-1 back into the expression for g(8)g(8) gives (1)+8=9-(-1) + 8 = 9.

Adım Adım Çözüm

1
Write the quadratic function f(x)f(x) in vertex form using its vertex (4,3)(4, -3).
f(x)=a(x4)23f(x) = a(x - 4)^2 - 3
The vertex form of a quadratic function with vertex (h,k)(h, k) is f(x)=a(xh)2+kf(x) = a(x - h)^2 + k.
2
Substitute the coordinates of the point (2,5)(2, 5) into the vertex form to find the value of the constant aa.
a=2a = 2, so f(x)=2(x4)23f(x) = 2(x - 4)^2 - 3
Since the point (2,5)(2, 5) lies on the graph of ff, substituting x=2x = 2 and f(2)=5f(2) = 5 allows us to solve for the vertical stretch factor aa.
3
Use the definition of g(x)g(x) to express g(8)g(8) in terms of ff.
g(8)=f(5)+8g(8) = -f(5) + 8
Substituting x=8x = 8 into the equation g(x)=f(x3)+8g(x) = -f(x - 3) + 8 yields g(8)=f(83)+8=f(5)+8g(8) = -f(8 - 3) + 8 = -f(5) + 8.
4
Evaluate f(5)f(5) using the equation for f(x)f(x) found in Step 2.
f(5)=1f(5) = -1
Substituting x=5x = 5 into f(x)=2(x4)23f(x) = 2(x - 4)^2 - 3 gives 2(54)23=2(1)3=12(5 - 4)^2 - 3 = 2(1) - 3 = -1.
5
Substitute the value of f(5)f(5) into the expression for g(8)g(8) to find the final result.
g(8)=9g(8) = 9
Substituting f(5)=1f(5) = -1 into g(8)=f(5)+8g(8) = -f(5) + 8 yields (1)+8=1+8=9-(-1) + 8 = 1 + 8 = 9.

Anahtar Kavram

Finding the equation of a quadratic function from its vertex and a point, and evaluating transformed functions using function notation.
Soru 1922Soru

A municipal swimming pool is being filled with water at a constant rate. After 22 hours of filling, the pool contains 14,50014,500 gallons of water. After 55 hours of filling, the pool contains 20,20020,200 gallons of water. If the relationship between the time the pool has been filling, tt, in hours, and the volume of water in the pool, VV, in gallons, is linear, which of the following equations represents this relationship?

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Cevap: V=1,900t+10,700V = 1,900t + 10,700

Cevap

The equation representing the relationship is V=1,900t+10,700V = 1,900t + 10,700.
The correct equation is V=1,900t+10,700V = 1,900t + 10,700. The rate of change of the water volume is the change in volume divided by the change in time: 20,20014,50052=5,7003=1,900\frac{20,200 - 14,500}{5 - 2} = \frac{5,700}{3} = 1,900 gallons per hour. Using the point-slope form with the coordinate point (2,14,500)(2, 14,500) yields V14,500=1,900(t2)V - 14,500 = 1,900(t - 2). Simplifying this expression gives V14,500=1,900t3,800V - 14,500 = 1,900t - 3,800, which results in V=1,900t+10,700V = 1,900t + 10,700.

Adım Adım Çözüm

1
Identify two data points from the problem context.
The two coordinate pairs representing (t,V)(t, V) are (2,14,500)(2, 14,500) and (5,20,200)(5, 20,200).
These points will allow us to calculate the slope and the y-intercept of the linear equation.
2
Calculate the slope (mm) using the slope formula m=V2V1t2t1m = \frac{V_2 - V_1}{t_2 - t_1}.
m=20,20014,50052=5,7003=1,900m = \frac{20,200 - 14,500}{5 - 2} = \frac{5,700}{3} = 1,900.
The slope represents the constant rate, in gallons per hour, at which the pool is being filled.
3
Substitute the slope m=1,900m = 1,900 and the point (2,14,500)(2, 14,500) into the point-slope form equation VV1=m(tt1)V - V_1 = m(t - t_1) to solve for VV.
V14,500=1,900(t2)    V14,500=1,900t3,800    V=1,900t+10,700V - 14,500 = 1,900(t - 2) \implies V - 14,500 = 1,900t - 3,800 \implies V = 1,900t + 10,700.
This yields the equation representing the volume of water VV in the pool at any time tt.

Anahtar Kavram

Determining a linear equation in two variables given two points from a word problem context.

Alternatif Yöntem

Instead of solving the linear equation algebraically, you can test the coordinates of the two given points (2,14,500)(2, 14,500) and (5,20,200)(5, 20,200) in the answer choices. Substituting t=2t = 2 and t=5t = 5 into the correct equation V=1,900t+10,700V = 1,900t + 10,700 satisfies both conditions: 1,900(2)+10,700=14,5001,900(2) + 10,700 = 14,500 and 1,900(5)+10,700=20,2001,900(5) + 10,700 = 20,200. None of the other options satisfy both points.
Tahmini Süre:1m 30s
Soru 1923Soru

An agricultural researcher categorized a sample of 150150 tomato plants by their watering schedule (daily or weekly) and their fruit yield (high yield or average yield). The results are summarized in the table below.

Watering ScheduleHigh YieldAverage YieldTotal
Daily626218188080
Weekly282842427070
Total90906060150150

Given that a tomato plant selected at random from the sample produced a high yield of fruit, what is the probability that the plant had a weekly watering schedule?

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Cevap: 1445\frac{14}{45}

Cevap

The correct answer is fourteen-forty-fifths (14/45). Given that the plant has a high yield, the sample space is restricted to the 90 plants in the High Yield column. Out of these 90 plants, 28 were on a weekly watering schedule, resulting in a probability of 28/90, which simplifies to 14/45.
To find the conditional probability that a tomato plant had a weekly watering schedule given that it produced a high yield of fruit, restrict the denominator to the total number of high-yield plants, which is 90. The numerator is the number of plants that meet both conditions (weekly watering and high yield), which is 28. The probability is 28/90, which simplifies to 14/45.

Adım Adım Çözüm

1
Identify the condition specified in the question stem to determine the subset of data to consider.
The condition is 'given that a tomato plant ... produced a high yield of fruit'. Thus, we restrict our focus to the 'High Yield' column.
This establishes the denominator for the conditional probability calculation.
2
Find the total number of plants in the 'High Yield' column (denominator) and the number of those plants that had a weekly watering schedule (numerator).
Total high-yield plants = 90. High-yield plants with a weekly watering schedule = 28.
These represent the total possible outcomes and the favorable outcomes within the restricted sample space.
3
Calculate and simplify the fraction representing the conditional probability.
Probability=2890=1445.Probability = \frac{28}{90} = \frac{14}{45}.
Expressing the final ratio in its simplest fractional form to match the standard exam options.

Anahtar Kavram

Two-Way Tables and Conditional Probability
Tahmini Süre:1m 30s
Soru 1924Soru

A study of 180180 college students categorized them by their major field of study (STEM or Humanities) and whether they participate in undergraduate research. The table below shows the partial results of the study, where aa, bb, cc, and dd represent the number of students in each category.

MajorParticipates in ResearchDoes Not Participate in ResearchTotal
STEMaabb110110
Humanitiesccdd7070
Total8080100100180180

Given that a student selected at random is a Humanities major, the probability that the student participates in undergraduate research is 37\frac{3}{7}. If a student who participates in undergraduate research is selected at random, what is the probability that the student is a STEM major?

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Cevap: 58\frac{5}{8}

Cevap

The correct probability is 58\frac{5}{8}.
To find the probability that a student is a STEM major given they participate in undergraduate research, we first determine the missing values in the table. The total number of Humanities majors is 7070. Since the probability that a Humanities major participates in research is 37\frac{3}{7}, the number of Humanities majors in research is c=37×70=30c = \frac{3}{7} \times 70 = 30. Using the research column total, the number of STEM majors in research is a=80c=8030=50a = 80 - c = 80 - 30 = 50. The probability that a student is a STEM major given that they participate in research is the ratio of STEM research participants to total research participants: aa+c=5080=58\frac{a}{a+c} = \frac{50}{80} = \frac{5}{8}.

Adım Adım Çözüm

1
Find the number of Humanities majors who participate in research (cc).
c=30c = 30
The table shows there are 7070 Humanities majors in total. We are given that the probability of a Humanities major participating in research is 37\frac{3}{7}. Therefore, c70=37\frac{c}{70} = \frac{3}{7}, which simplifies to c=30c = 30.
2
Find the number of STEM majors who participate in research (aa).
a=50a = 50
The total number of students who participate in research is 8080. Since a+c=80a + c = 80 and c=30c = 30, we have a+30=80a + 30 = 80, which means a=50a = 50.
3
Calculate the conditional probability that a student who participates in research is a STEM major.
58\frac{5}{8}
We want to find the probability of selecting a STEM major given that the student participates in research. This is the ratio of STEM majors who participate in research (a=50a = 50) to the total number of students who participate in research (8080). The probability is 5080=58\frac{50}{80} = \frac{5}{8}.

Anahtar Kavram

Conditional Probability in Two-Way Tables
Soru 1925Soru

In the equation 25x5x3=1252\frac{25^x}{5^{x-3}} = 125^2, what is the value of xx?

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Cevap: 3

Cevap

The correct answer is 3.
By writing all terms with a base of 5, the equation 25x5x3=1252\frac{25^x}{5^{x-3}} = 125^2 becomes 52x5x3=56\frac{5^{2x}}{5^{x-3}} = 5^6. Applying the quotient rule of exponents, the left side simplifies to 52x(x3)=5x+35^{2x - (x-3)} = 5^{x+3}. Setting the exponents equal gives x+3=6x+3 = 6, which yields x=3x = 3.

Adım Adım Çözüm

1
Express all terms with a common base of 5.
25x=(52)x=52x25^x = (5^2)^x = 5^{2x} and 1252=(53)2=56125^2 = (5^3)^2 = 5^6.
Expressing all exponential terms with the same base allows the exponents to be equated directly once simplified.
2
Substitute these expressions back into the original equation and simplify the left side using the quotient rule of exponents.
52x5x3=52x(x3)=5x+3\frac{5^{2x}}{5^{x-3}} = 5^{2x - (x-3)} = 5^{x+3}. The equation becomes 5x+3=565^{x+3} = 5^6.
The quotient rule states that dividing exponential terms with the same base requires subtracting the exponent of the denominator from the exponent of the numerator: bmbn=bmn\frac{b^m}{b^n} = b^{m-n}.
3
Equate the exponents and solve for xx.
x+3=6    x=3x + 3 = 6 \implies x = 3.
Since the bases on both sides of the equation are equal, their exponents must also be equal: if by=bzb^y = b^z where b>0b > 0 and b1b \neq 1, then y=zy = z.

Anahtar Kavram

Solving exponential equations by expressing terms with a common base and applying exponent rules.
Tahmini Süre:1m 30s
Soru 1926Soru

A residential solar power system stores electricity in a battery. The total energy stored in the battery, EE, in kilowatt-hours (kWh), is modeled by a linear function of the time tt, in hours, since sunrise. After 44 hours of sunlight, the energy stored is 1818 kWh. After 77 hours of sunlight, the energy stored is 2727 kWh. Which of the following is the best interpretation of the slope of the graph of this function in the tEtE-plane?

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Cevap: The energy stored in the battery increases by 33 kilowatt-hours per hour of sunlight.

Cevap

The energy stored in the battery increases by 33 kilowatt-hours per hour of sunlight.
To find the slope of the linear relationship, we use the formula for the rate of change: slope=ΔEΔt\text{slope} = \frac{\Delta E}{\Delta t}. Using the two points (4,18)(4, 18) and (7,27)(7, 27), the slope is 271874=93=3\frac{27 - 18}{7 - 4} = \frac{9}{3} = 3 kilowatt-hours per hour. In the context of the problem, the slope represents the rate at which the stored energy increases per hour of sunlight. Therefore, the energy stored in the battery increases by 33 kilowatt-hours per hour of sunlight.

Adım Adım Çözüm

1
Identify the coordinates (t,E)(t, E) from the given values.
The two data points are (4,18)(4, 18) and (7,27)(7, 27).
These points represent the time in hours and the corresponding energy stored in the battery.
2
Calculate the slope of the linear relationship using the slope formula.
The slope is 271874=93=3\frac{27 - 18}{7 - 4} = \frac{9}{3} = 3.
The slope of a linear relationship represents the constant rate of change of the dependent variable (EE) per unit change of the independent variable (tt).
3
Interpret the meaning of the calculated slope in the context of the problem.
A slope of 33 means that the energy stored in the battery, EE, increases by 33 kilowatt-hours (kWh) for every 11 hour of sunlight, tt.
The units of the slope are units of EE divided by units of tt, which is kilowatt-hours per hour.

Anahtar Kavram

Interpreting the rate of change (slope) of a linear relationship in context.
Tahmini Süre:1m 30s
Soru 1927Soru

The value of a financial asset, V(t)V(t), in dollars, is modeled as a function of time tt, in years, for 0t40 \le t \le 4. The growth of the asset's value is described by two different models over this period:

- For 0t20 \le t \le 2, the value of the asset increases by a constant percentage of r%r\% per year.
- For 2t42 \le t \le 4, the value of the asset increases by a constant amount of dd dollars per year.

At t=0t = 0, the value of the asset is 100100 dollars, and at t=1t = 1, the value of the asset is 120120 dollars. If the average rate of change of the asset's value from t=0t = 0 to t=4t = 4 is 2525 dollars per year, what is the value of the asset, in dollars, at t=3t = 3?

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Cevap: 172

Cevap

172
To find the value of the asset at t=3t = 3, we first determine its value at t=2t = 2 using the exponential growth model. Since the value increases by a constant percentage from t=0t=0 to t=2t=2, the value is modeled by V(t)=V(0)×(1+r100)tV(t) = V(0) \times (1 + \frac{r}{100})^t. Given V(0)=100V(0) = 100 and V(1)=120V(1) = 120, the annual growth factor is 1.21.2. Thus, V(2)=100×(1.2)2=144V(2) = 100 \times (1.2)^2 = 144 dollars.

Next, the linear growth from t=2t = 2 to t=4t = 4 is modeled by V(t)=V(2)+d(t2)=144+d(t2)V(t) = V(2) + d(t - 2) = 144 + d(t - 2), which gives V(4)=144+2dV(4) = 144 + 2d dollars. The average rate of change of the asset's value from t=0t = 0 to t=4t = 4 is 2525 dollars per year, so we set up the equation: V(4)V(0)4=25    (144+2d)1004=25\frac{V(4) - V(0)}{4} = 25 \implies \frac{(144 + 2d) - 100}{4} = 25. Solving for dd gives d=28d = 28 dollars per year. Finally, we evaluate the value at t=3t = 3: V(3)=144+28(32)=172V(3) = 144 + 28(3 - 2) = 172 dollars.

Adım Adım Çözüm

1
Identify the growth model for 0t20 \le t \le 2 and write the corresponding equation using the initial values.
Since the value increases by a constant percentage each year, the growth is exponential: V(t)=V(0)×(1+r100)tV(t) = V(0) \times (1 + \frac{r}{100})^t. Given V(0)=100V(0) = 100 and V(1)=120V(1) = 120, we have 120=100(1+r100)1    1+r100=1.2120 = 100(1 + \frac{r}{100})^1 \implies 1 + \frac{r}{100} = 1.2.
Establishing the exponential model allows us to find the growth factor and calculate the value of the asset at the boundary of the two models (t=2t = 2).
2
Calculate the value of the asset at t=2t = 2 using the exponential growth model.
V(2)=100×(1.2)2=144V(2) = 100 \times (1.2)^2 = 144 dollars.
The value at t=2t = 2 serves as the initial value for the linear growth model in the second interval.
3
Write the growth model for the interval 2t42 \le t \le 4.
The growth is linear, so V(t)=V(2)+d(t2)=144+d(t2)V(t) = V(2) + d(t - 2) = 144 + d(t - 2) for t2t \ge 2. At t=4t = 4, the value is V(4)=144+2dV(4) = 144 + 2d dollars.
Expressing the value at t=4t = 4 in terms of the constant rate dd allows us to use the average rate of change information to solve for dd.
4
Set up the equation for the average rate of change over the entire interval from t=0t = 0 to t=4t = 4 and solve for dd.
The average rate of change is given by V(4)V(0)40=25\frac{V(4) - V(0)}{4 - 0} = 25. Substituting the values, we get (144+2d)1004=25    44+2d4=25    44+2d=100    2d=56    d=28\frac{(144 + 2d) - 100}{4} = 25 \implies \frac{44 + 2d}{4} = 25 \implies 44 + 2d = 100 \implies 2d = 56 \implies d = 28 dollars per year.
The average rate of change relates the final value at t=4t=4 to the initial value at t=0t=0, enabling us to determine the linear rate of change dd.
5
Calculate the value of the asset at t=3t = 3 using the linear model.
V(3)=V(2)+d(32)=144+28(1)=172V(3) = V(2) + d(3 - 2) = 144 + 28(1) = 172 dollars.
Substituting t=3t = 3 into the linear growth model yields the final requested value.

Anahtar Kavram

Linear and Exponential Growth

Alternatif Yöntem

Instead of setting up the linear equation from t=2t = 2 to t=4t = 4, we can write V(4)V(4) directly as V(0)+4×25=200V(0) + 4 \times 25 = 200 dollars using the definition of average rate of change. Since V(2)=144V(2) = 144 dollars, the total change over the linear interval [2,4][2, 4] is 200144=56200 - 144 = 56 dollars. Because the growth is linear during this interval, the change over one year (from t=2t = 2 to t=3t = 3) must be exactly half of the change over two years (from t=2t = 2 to t=4t = 4). Thus, the increase from t=2t = 2 to t=3t = 3 is 56/2=2856 / 2 = 28 dollars, yielding V(3)=144+28=172V(3) = 144 + 28 = 172 dollars.
Tahmini Süre:3m 0s
Soru 1928Soru
An equation is shown below.
x+1x2+1x=6x22x\frac{x+1}{x-2} + \frac{1}{x} = \frac{6}{x^2-2x}
If xx satisfies the equation above, what is the value of xx?
Cevabı ve açıklamayı göster

Cevap: -4

Cevap

-4
The correct answer is 4-4. To solve the rational equation, we first identify the least common denominator as x(x2)x(x-2). Multiplying both sides by this expression eliminates the denominators, yielding x(x+1)+(x2)=6x(x+1) + (x-2) = 6. Expanding and simplifying gives the quadratic equation x2+2x8=0x^2 + 2x - 8 = 0, which factors as (x+4)(x2)=0(x+4)(x-2) = 0. This yields potential solutions of x=4x = -4 and x=2x = 2. However, substituting x=2x = 2 back into the original equation results in division by zero, making x=2x = 2 extraneous. The only valid solution is 4-4.

Adım Adım Çözüm

1
Find the least common denominator (LCD) of the rational expressions in the equation.
The denominators are x2x-2, xx, and x22xx^2-2x. Since x22x=x(x2)x^2-2x = x(x-2), the LCD is x(x2)x(x-2), with the restriction that x0x \neq 0 and x2x \neq 2.
Finding a common denominator allows us to clear the fractions by multiplying both sides of the equation.
2
Multiply each term of the equation by the LCD to eliminate the denominators.
x(x+1)+1(x2)=6x(x+1) + 1(x-2) = 6
This clears the denominators and converts the rational equation into a polynomial equation.
3
Expand and simplify the resulting equation.
x2+x+x2=6x^2 + x + x - 2 = 6, which simplifies to x2+2x2=6x^2 + 2x - 2 = 6.
Combining like terms prepares the equation to be written in standard quadratic form.
4
Rearrange the terms into standard quadratic form: ax2+bx+c=0ax^2 + bx + c = 0.
x2+2x8=0x^2 + 2x - 8 = 0
Subtracting 66 from both sides sets the quadratic equation to zero so it can be solved by factoring.
5
Factor the quadratic equation.
(x+4)(x2)=0(x+4)(x-2) = 0
Finding two numbers that multiply to 8-8 and add to 22 (44 and 2-2) allows us to solve for xx.
6
Find the potential solutions by setting each factor to zero.
x=4x = -4 or x=2x = 2
Applying the zero product property gives the potential roots of the quadratic equation.
7
Check the potential solutions in the original equation to identify any extraneous solutions.
For x=4x = -4, the equation is defined and valid. For x=2x = 2, the denominators x2x-2 and x22xx^2-2x become zero, which is undefined.
Rational equations can produce extraneous solutions that make the original denominators zero, so they must be checked and discarded.

Anahtar Kavram

Solving rational equations by finding a common denominator and checking for extraneous solutions.
Soru 1929Soru

A quadratic function gg is defined by g(x)=2x212x+kg(x) = 2x^2 - 12x + k, where kk is a constant. In the xyxy-plane, the graph of gg has its vertex on the line y=5y = -5. What is the value of kk?

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Cevap: 13

Cevap

13
The xx-coordinate of the vertex for the quadratic function g(x)=ax2+bx+cg(x) = ax^2 + bx + c is found using the formula x=b2ax = -\frac{b}{2a}. Substituting a=2a = 2 and b=12b = -12 yields x=122(2)=3x = -\frac{-12}{2(2)} = 3. Evaluating g(3)g(3) gives the yy-coordinate of the vertex: g(3)=2(3)212(3)+k=18+kg(3) = 2(3)^2 - 12(3) + k = -18 + k. Since the vertex lies on the line y=5y = -5, setting 18+k=5-18 + k = -5 and solving for kk gives k=13k = 13.

Adım Adım Çözüm

1
Find the xx-coordinate of the vertex of the parabola.
The xx-coordinate is 33.
For a quadratic function g(x)=ax2+bx+cg(x) = ax^2 + bx + c, the xx-coordinate of the vertex is given by x=b2ax = -\frac{b}{2a}. Here, a=2a = 2 and b=12b = -12, so x=122(2)=3x = -\frac{-12}{2(2)} = 3.
2
Evaluate the function at x=3x = 3 to find the yy-coordinate of the vertex in terms of kk.
The yy-coordinate is 18+k-18 + k.
Substituting x=3x = 3 into the function gives g(3)=2(3)212(3)+k=1836+k=18+kg(3) = 2(3)^2 - 12(3) + k = 18 - 36 + k = -18 + k.
3
Set the yy-coordinate of the vertex equal to 5-5 and solve for kk.
k=13k = 13.
Since the vertex lies on the line y=5y = -5, the yy-coordinate of the vertex must be 5-5. Thus, 18+k=5    k=13-18 + k = -5 \implies k = 13.

Anahtar Kavram

Determining the vertex of a quadratic function and using its coordinates to solve for unknown parameters.
Soru 1930Soru

A biologist measures the heights, in centimeters, of five seedlings in a laboratory. The heights are 1212, 1515, 88, 2121, and 1414. What is the range, in centimeters, of these heights?

Cevabı ve açıklamayı göster

Cevap: 13

Cevap

13
To find the range of a dataset, subtract the minimum value from the maximum value. In the given dataset of seedling heights (1212, 1515, 88, 2121, and 1414), the maximum height is 2121 centimeters and the minimum height is 88 centimeters. Calculating the difference gives 218=1321 - 8 = 13 centimeters.

Adım Adım Çözüm

1
Identify the maximum and minimum values in the dataset.
The maximum value is 2121 and the minimum value is 88.
The range is defined as the difference between the largest (maximum) and smallest (minimum) values in a data distribution.
2
Subtract the minimum value from the maximum value to calculate the range.
218=1321 - 8 = 13
Subtracting the minimum value of 88 from the maximum value of 2121 yields the range of the dataset.

Anahtar Kavram

The range of a dataset measures the spread of the data and is calculated by subtracting the minimum value from the maximum value.
Soru 1931Soru

The list below shows the number of packages delivered to a local business on each of 88 business days:

1,2,2,3,5,6,7,101, 2, 2, 3, 5, 6, 7, 10

What is the median number of packages delivered on these days?

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Cevap: 4

Cevap

4
The correct answer is the median value of 44. The list contains 88 values already sorted in ascending order: 1,2,2,3,5,6,7,101, 2, 2, 3, 5, 6, 7, 10. Because the number of values is even, the median is the average of the two middle values (the 44 th and 55 th values, which are 33 and 55). The average is calculated as 3+52=4\frac{3 + 5}{2} = 4.

Adım Adım Çözüm

1
Identify the two middle terms of the ordered dataset.
The two middle values in the ordered list of 8 numbers are the 4th term, which is 33, and the 5th term, which is 55.
Since the dataset has an even number of values (88), the median is the average of the two middle terms.
2
Calculate the average of the two middle terms.
3+52=82=4\frac{3 + 5}{2} = \frac{8}{2} = 4
Finding the mean of these two middle values yields the median of the entire dataset.

Anahtar Kavram

Calculating the median of a dataset with an even number of values
Tahmini Süre:45s
Soru 1932Soru

An administrator installs a new security update on a computer server. The update is designed to identify and quarantine system errors such that the total number of errors on the server is reduced by 12%12\% each hour. Which of the following best describes the relationship between the time, in hours, since the update was installed and the number of system errors remaining on the server?

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Cevap: Decreasing exponential, because the number of errors decreases by a constant percentage each hour.

Cevap

Decreasing exponential, because the number of errors decreases by a constant percentage each hour.
The correct answer is the option stating that the relationship is decreasing exponential because the number of errors decreases by a constant percentage each hour. In mathematical modeling, when a quantity changes by a fixed percentage over equal intervals of time, it is modeled by an exponential function. Since the quantity is being reduced, it is a decreasing exponential relationship.

Adım Adım Çözüm

1
Analyze the rate of change described in the problem.
The number of system errors is reduced by 12%12\% each hour.
Identifying how the quantity changes per unit of time is key to determining the model type.
2
Distinguish between linear and exponential relationships based on the rate of change.
Since the change is a constant percent decrease (12%12\%) rather than a constant numerical amount, the relationship is exponential rather than linear.
Exponential models represent situations with constant percentage changes, while linear models represent constant absolute changes.
3
Determine the direction of the change (growth or decay).
Because the number of errors is reduced, the quantity is decreasing, representing exponential decay (decreasing exponential).
A reduction in quantity indicates decay (decreasing) rather than growth (increasing).

Anahtar Kavram

Linear and Exponential Growth
Soru 1933Soru

A solar power station consists of solar panels that generate electricity at a constant rate of 15 watts15\text{ watts} per square foot of panel surface area (where 1 watt=1 joule per second1\text{ watt} = 1\text{ joule per second}). The panels have a total surface area of 12,000 square yards12,000\text{ square yards}. How many megajoules (MJ) of energy do the panels generate in 2 hours2\text{ hours}? (Given that 1 yard=3 feet1\text{ yard} = 3\text{ feet} and 1 MJ=1,000,000 joules1\text{ MJ} = 1,000,000\text{ joules})

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Cevap: 11,66411,664

Cevap

The solar panels generate 11,66411,664 megajoules of energy in 2 hours2\text{ hours}.
To find the energy generated, first convert the area from square yards to square feet. Since 1 yard=3 feet1\text{ yard} = 3\text{ feet}, 1 square yard=(3 feet)2=9 square feet1\text{ square yard} = (3\text{ feet})^2 = 9\text{ square feet}. Multiplying 12,000 square yards12,000\text{ square yards} by 99 gives 108,000 square feet108,000\text{ square feet}. The power generated is 108,000 square feet×15 watts/square foot=1,620,000 watts108,000\text{ square feet} \times 15\text{ watts/square foot} = 1,620,000\text{ watts}, which is 1,620,000 joules per second1,620,000\text{ joules per second}. In 2 hours2\text{ hours}, which is 2×3,600=7,200 seconds2 \times 3,600 = 7,200\text{ seconds}, the total energy generated is 1,620,000 joules/second×7,200 seconds=11,664,000,000 joules1,620,000\text{ joules/second} \times 7,200\text{ seconds} = 11,664,000,000\text{ joules}. Since 1 MJ=1,000,000 joules1\text{ MJ} = 1,000,000\text{ joules}, this is equivalent to 11,664 MJ11,664\text{ MJ}.

Adım Adım Çözüm

1
Convert the surface area of the solar panels from square yards to square feet.
Since 1 yard=3 feet1\text{ yard} = 3\text{ feet}, 1 square yard=32=9 square feet1\text{ square yard} = 3^2 = 9\text{ square feet}. Therefore, the total area in square feet is 12,000×9=108,000 square feet12,000 \times 9 = 108,000\text{ square feet}.
To apply the generation rate given in watts per square foot, the area must be in square feet.
2
Determine the total rate of energy generation in joules per second.
The total power generated is 108,000 square feet×15 watts per square foot=1,620,000 watts108,000\text{ square feet} \times 15\text{ watts per square foot} = 1,620,000\text{ watts}. Since 1 watt=1 joule per second1\text{ watt} = 1\text{ joule per second}, this equals 1,620,000 joules per second1,620,000\text{ joules per second}.
This calculates the total energy produced by the entire solar farm every second.
3
Convert the total time from hours to seconds.
2 hours×60 minutes/hour×60 seconds/minute=7,200 seconds2\text{ hours} \times 60\text{ minutes/hour} \times 60\text{ seconds/minute} = 7,200\text{ seconds}.
To find the total energy generated, the rate (joules per second) must be multiplied by the duration in seconds.
4
Calculate the total energy generated in joules, then convert it to megajoules (MJ).
Total energy in joules is 1,620,000 joules/second×7,200 seconds=11,664,000,000 joules1,620,000\text{ joules/second} \times 7,200\text{ seconds} = 11,664,000,000\text{ joules}. Converting to megajoules: 11,664,000,000 joules÷1,000,000 joules/MJ=11,664 MJ11,664,000,000\text{ joules} \div 1,000,000\text{ joules/MJ} = 11,664\text{ MJ}.
This yields the final quantity of energy in the requested units.

Anahtar Kavram

Multi-step unit conversions involving area scaling, compound rates, and time conversions.
Tahmini Süre:2m 30s
Soru 1934Soru

An express delivery truck travels from Warehouse A to Warehouse B at a constant speed, and then returns from Warehouse B to Warehouse A along the same route at a different constant speed. On the first trip, the ratio of the outbound travel time to the inbound travel time is 33 to 55. On a second trip along the same route, the truck's outbound speed is 50%50\% greater than its outbound speed on the first trip, and its inbound speed is 25%25\% less than its inbound speed on the first trip. If the total round-trip travel time for the second trip is 1313 hours, what is the total round-trip travel time, in hours, for the first trip?

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Cevap: 12

Cevap

The total round-trip travel time for the first trip is 12 hours.
The correct answer is 1212. By setting the outbound and inbound travel times of the first trip as t1t_1 and t2t_2 with t1=0.6t2t_1 = 0.6t_2, we apply the inverse relationships of speed and time to express the second trip's times as t1=23t1t_1' = \frac{2}{3}t_1 and t2=43t2t_2' = \frac{4}{3}t_2. Substituting these into the second trip's total time equation 23t1+43t2=13\frac{2}{3}t_1 + \frac{4}{3}t_2 = 13 yields t2=7.5t_2 = 7.5 and t1=4.5t_1 = 4.5, summing to 1212 hours.

Adım Adım Çözüm

1
Set up the ratio of outbound to inbound travel times for the first trip.
t1=0.6t2t_1 = 0.6t_2 (or t1=35t2t_1 = \frac{3}{5}t_2)
The ratio of the outbound travel time (t1t_1) to the inbound travel time (t2t_2) is given as 33 to 55.
2
Express the new travel times for the second trip (t1t_1' and t2t_2') in terms of the original travel times.
t1=23t1t_1' = \frac{2}{3}t_1 and t2=43t2t_2' = \frac{4}{3}t_2
For a constant distance, travel time is inversely proportional to speed. A 50%50\% speed increase multiplies time by 11.5=23\frac{1}{1.5} = \frac{2}{3}, and a 25%25\% speed decrease multiplies time by 10.75=43\frac{1}{0.75} = \frac{4}{3}.
3
Create an equation for the total travel time of the second trip.
23t1+43t2=13\frac{2}{3}t_1 + \frac{4}{3}t_2 = 13
The sum of the outbound and inbound travel times on the second trip is given as 1313 hours.
4
Substitute the first trip's relationship into the equation and solve for t2t_2.
t2=7.5t_2 = 7.5
Substituting t1=35t2t_1 = \frac{3}{5}t_2 gives 23(35t2)+43t2=13    2615t2=13    t2=13×1526=7.5\frac{2}{3}\left(\frac{3}{5}t_2\right) + \frac{4}{3}t_2 = 13 \implies \frac{26}{15}t_2 = 13 \implies t_2 = 13 \times \frac{15}{26} = 7.5.
5
Determine t1t_1 and calculate the total travel time for the first trip.
t1+t2=12t_1 + t_2 = 12
Since t2=7.5t_2 = 7.5, then t1=0.6(7.5)=4.5t_1 = 0.6(7.5) = 4.5. The total round-trip time is 4.5+7.5=124.5 + 7.5 = 12.

Anahtar Kavram

Inverse proportionality of speed and time, and solving linear systems involving ratios.
Soru 1935Soru

A customer service representative recorded the call durations, in minutes, for 55 phone calls on a Tuesday morning. The call durations are 11, 22, 33, 55, and 99 minutes. What is the mean duration, in minutes, of these 55 phone calls?

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Cevap: 44

Cevap

The correct answer is 44 minutes, which represents the mean duration of the phone calls.
The mean duration of the calls is found by dividing the sum of the durations by the total number of calls. The sum of the durations is 1+2+3+5+9=201 + 2 + 3 + 5 + 9 = 20 minutes. Dividing this sum by the 55 calls yields 20÷5=420 \div 5 = 4 minutes.

Adım Adım Çözüm

1
Calculate the sum of all the call durations.
Sum = 1+2+3+5+9=201 + 2 + 3 + 5 + 9 = 20
To find the mean, the sum of all values in the dataset must first be calculated.
2
Divide the sum by the total number of call durations.
20÷5=420 \div 5 = 4
The mean is found by dividing the sum of the values by the number of values in the dataset, which is 55.

Anahtar Kavram

Calculating the mean (average) of a data set by dividing the sum of all values by the count of values.
Soru 1936Soru

An environmental study monitored the water volume of two reservoirs, Reservoir A and Reservoir B. In June, the water volume of Reservoir A was 20%20\% greater than the water volume of Reservoir B. By August, the water volume of Reservoir A had decreased by 15%15\%, while the water volume of Reservoir B had increased by 10%10\%. If the water volume of Reservoir A in August was 10.210.2 million gallons, what was the water volume of Reservoir B in June, in millions of gallons?

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Cevap: 10.0

Cevap

The water volume of Reservoir B in June was 10.0 million gallons.
The correct answer is the value that represents Reservoir B's volume in June. Let BB represent Reservoir B's water volume in June. Since Reservoir A's June volume was 20%20\% greater than Reservoir B's, it is represented as 1.20B1.20B. Between June and August, Reservoir A's volume decreased by 15%15\%, so its August volume is 85%85\% of its June volume, which is 0.85×1.20B=1.02B0.85 \times 1.20B = 1.02B. Setting this equal to the given August volume of 10.210.2 million gallons yields 1.02B=10.21.02B = 10.2. Solving for BB gives B=10.0B = 10.0 million gallons.

Adım Adım Çözüm

1
Define a variable for the unknown quantity and express Reservoir A's volume in June.
Let BB represent the water volume of Reservoir B in June. Since Reservoir A's June volume was 20%20\% greater than Reservoir B's, the volume of Reservoir A in June is 1.20B1.20B.
This establishes the relationship between the initial volumes of the two reservoirs.
2
Determine Reservoir A's volume in August in terms of the variable BB.
Since Reservoir A's volume decreased by 15%15\% by August, its new volume is 85%85\% of its June volume. Thus, the volume in August is 0.85×1.20B=1.02B0.85 \times 1.20B = 1.02B.
This represents the two-stage percentage change for Reservoir A.
3
Solve for the variable BB using the given August volume.
Set the expression for Reservoir A's August volume equal to 10.210.2 million gallons: 1.02B=10.21.02B = 10.2. Dividing both sides by 1.021.02 gives B=10.0B = 10.0 million gallons.
This finds the initial volume of Reservoir B.

Anahtar Kavram

Multi-step percentage change and setting up equations to solve for initial values.
Tahmini Süre:1m 30s
Soru 1937Soru

A manufacturing plant uses a machine lubricant at a constant rate of 0.080.08 fluid ounces per second of operation. The plant operates the machinery for 88 hours per day, 55 days a week. The lubricant is purchased in drums, where each drum contains 1515 gallons of lubricant. How many drums of lubricant does the plant use in a period of 55 weeks? (Note: 1 gallon=128 fluid ounces1\text{ gallon} = 128\text{ fluid ounces})

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Cevap: 30

Cevap

The plant uses 30 drums of lubricant in 5 weeks.
To find the number of drums, calculate the total seconds of operation: 5 weeks * 5 days/week * 8 hours/day * 3,600 seconds/hour = 720,000 seconds. Multiply this by the consumption rate of 0.08 fluid ounces/second to get 57,600 fluid ounces. Convert this to gallons by dividing by 128 fluid ounces/gallon to get 450 gallons. Finally, divide by 15 gallons/drum to find that 30 drums are used.

Adım Adım Çözüm

1
Calculate the total number of operational seconds in the 5-week period.
720000 seconds720{}000\text{ seconds}
Multiply 5 weeks by 5 days per week, 8 hours per day, and 3,600 seconds per hour: 5×5×8×3600=7200005 \times 5 \times 8 \times 3{}600 = 720{}000.
2
Calculate the total volume of lubricant used in fluid ounces.
57600 fluid ounces57{}600\text{ fluid ounces}
Multiply the rate of 0.08 fluid ounces per second0.08\text{ fluid ounces per second} by the total operational seconds: 720000×0.08=57600720{}000 \times 0.08 = 57{}600.
3
Convert the total fluid ounces to gallons.
450 gallons450\text{ gallons}
Divide the total fluid ounces by the conversion factor of 128 fluid ounces per gallon128\text{ fluid ounces per gallon}: 57600/128=45057{}600 / 128 = 450.
4
Calculate the total number of drums needed.
30 drums30\text{ drums}
Divide the total gallons by the capacity of a single drum (15 gallons15\text{ gallons}): 450/15=30450 / 15 = 30.

Anahtar Kavram

Multi-step dimensional analysis and unit conversion under compound rates
Soru 1938Soru

Two environmental cleanup projects, Project A and Project B, begin treating separate, identical bodies of water that each contain V0V_0 gallons of a certain chemical. The volume of the chemical remaining in the water treated by Project A is modeled by the exponential decay function A(t)=V0(k)tA(t) = V_0(k)^t, where tt is the number of days since treatment began and kk is a constant. The volume of the chemical remaining in the water treated by Project B is modeled by the linear decay function B(t)=V0ctB(t) = V_0 - c \cdot t, where cc is a positive constant. After 11 day of treatment, the volume of the chemical remaining in both bodies of water is the same. After 22 days of treatment, the volume of the chemical remaining in the water treated by Project A is exactly 1615\frac{16}{15} times the volume of the chemical remaining in the water treated by Project B. If the treatment for Project B continues at this constant rate, after how many days will the chemical in Project B's water be completely removed?

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Cevap: 5

Cevap

5
Equating both models at t=1t = 1 gives cV0=1k\frac{c}{V_0} = 1 - k. At t=2t = 2, Project A's remaining volume is V0k2V_0 k^2 and Project B's is V0(2k1)V_0(2k - 1). Setting k2=1615(2k1)k^2 = \frac{16}{15}(2k - 1) results in the quadratic equation 15k232k+16=015k^2 - 32k + 16 = 0. Factoring this yields k=0.8k = 0.8 (discarding 1.331.33 because the scenario represents decay). The chemical in Project B's water is completely removed when B(t)=0    t=V0c=11k=10.2=5B(t) = 0 \implies t = \frac{V_0}{c} = \frac{1}{1-k} = \frac{1}{0.2} = 5 days.

Adım Adım Çözüm

1
Relate parameters kk and cc using the condition A(1)=B(1)A(1) = B(1).
cV0=1k\frac{c}{V_0} = 1 - k
Establishing a link between the rates of linear decay and exponential decay.
2
Express the remaining volumes at t=2t = 2 in terms of kk.
A(2)=V0k2A(2) = V_0 k^2 and B(2)=V0(2k1)B(2) = V_0(2k - 1)
Preparing equations to apply the ratio condition at t=2t = 2 using a single variable.
3
Apply the condition A(2)=1615B(2)A(2) = \frac{16}{15}B(2) to solve for kk.
k=0.8k = 0.8
Setting up the quadratic equation 15k232k+16=015k^2 - 32k + 16 = 0, factoring it to find roots 0.80.8 and 1.331.33, and selecting 0.80.8 because k<1k < 1 for a decay process.
4
Calculate the time tt when B(t)=0B(t) = 0.
t=5t = 5
Solving V0ct=0V_0 - c \cdot t = 0 yields t=V0c=11k=10.2=5t = \frac{V_0}{c} = \frac{1}{1-k} = \frac{1}{0.2} = 5 days.

Anahtar Kavram

Linear and exponential decay modeling
Soru 1939Soru

A bicycle factory produces road bikes and mountain bikes at a constant ratio of 22 to 33. If the factory produces 120120 road bikes in one day, how many mountain bikes does the factory produce in the same day?

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Cevap: 180

Cevap

180
The ratio of road bikes to mountain bikes is 22 to 33. Since the factory produces 120120 road bikes, we can set up the proportion 23=120x\frac{2}{3} = \frac{120}{x}, where xx represents the number of mountain bikes. Solving for xx gives 2x=3602x = 360, which simplifies to x=180x = 180.

Adım Adım Çözüm

1
Identify the given ratio and set up a proportion comparing road bikes to mountain bikes.
The ratio of road bikes to mountain bikes is 23\frac{2}{3}, so the proportion is Road BikesMountain Bikes=23\frac{\text{Road Bikes}}{\text{Mountain Bikes}} = \frac{2}{3}.
To find the unknown number of mountain bikes using the constant ratio.
2
Substitute 120120 for the number of road bikes and solve for the number of mountain bikes, xx.
120x=23    2x=360    x=180\frac{120}{x} = \frac{2}{3} \implies 2x = 360 \implies x = 180.
To calculate the exact number of mountain bikes produced.

Anahtar Kavram

Using ratios and proportions to solve word problems
Soru 1940Soru

What is the complete set of solutions for the inequality 73(2x5)4x+87 - 3(2x - 5) \leq -4x + 8?

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Cevap: x7x \geq 7

Cevap

The complete set of solutions is represented by the inequality x7x \geq 7.
To solve the inequality 73(2x5)4x+87 - 3(2x - 5) \leq -4x + 8, we first distribute 3-3 to get 76x+154x+87 - 6x + 15 \leq -4x + 8. Combining constant terms on the left side gives 226x4x+822 - 6x \leq -4x + 8. Adding 4x4x and subtracting 2222 from both sides isolates the variable, resulting in 2x14-2x \leq -14. Dividing both sides by 2-2 and flipping the inequality symbol yields the solution x7x \geq 7.

Adım Adım Çözüm

1
Distribute the 3-3 to both terms inside the parentheses.
76x+154x+87 - 6x + 15 \leq -4x + 8
Applying the distributive property, 3(2x)=6x-3(2x) = -6x and 3(5)=15-3(-5) = 15.
2
Combine the constant terms on the left side of the inequality.
226x4x+822 - 6x \leq -4x + 8
Adding 77 and 1515 yields 2222.
3
Isolate the variable term on one side and the constant term on the other side.
2x14-2x \leq -14
Adding 4x4x to both sides yields 2x-2x, and subtracting 2222 from both sides yields 14-14.
4
Divide both sides by 2-2 and flip the inequality sign.
x7x \geq 7
Dividing both sides of an inequality by a negative number reverses the direction of the inequality symbol.

Anahtar Kavram

Solving multi-step linear inequalities in one variable including negative coefficient division and the distributive property.
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