Algebra

432 soru

Soru 301Soru

For a constant aa, the inequality 5xa(32x)45x - a(3 - 2x) \ge 4 has a solution set of the form xdx \le d, where dd is a constant. Which of the following must be true about the value of aa?

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Cevap: a<52a < -\frac{5}{2}

Cevap

The value of aa must satisfy a<52a < -\frac{5}{2}.
To find the correct range for aa, we first expand the inequality 5xa(32x)45x - a(3 - 2x) \ge 4 using the distributive property, which yields 5x3a+2ax45x - 3a + 2ax \ge 4. Grouping the xx terms gives (5+2a)x3a+4(5 + 2a)x \ge 3a + 4. The problem states that the solution set is of the form xdx \le d. Because the inequality sign flipped from greater-than-or-equal-to (\ge) to less-than-or-equal-to (\le), the coefficient of xx must be negative. Setting the coefficient 5+2a<05 + 2a < 0 and solving for aa gives a<52a < -\frac{5}{2}.

Adım Adım Çözüm

1
Expand the inequality to separate the terms.
5x3a+2ax45x - 3a + 2ax \ge 4
Apply the distributive property to the term a(32x)-a(3 - 2x), paying close attention to the signs: a×3=3a-a \times 3 = -3a and a×(2x)=2ax-a \times (-2x) = 2ax.
2
Group and factor the terms containing xx on the left side, and move the constant terms to the right side.
(5+2a)x3a+4(5 + 2a)x \ge 3a + 4
Factor out xx from the terms 5x5x and 2ax2ax to isolate the variable, and add 3a3a to both sides of the inequality.
3
Analyze the relationship between the coefficient of xx and the inequality sign of the solution set.
5+2a<05 + 2a < 0
The original inequality has a greater-than-or-equal-to sign (\ge), but the given solution set is of the form xdx \le d (less-than-or-equal-to). For the inequality sign to reverse when dividing both sides by the coefficient of xx, the coefficient (5+2a)(5 + 2a) must be negative.
4
Solve the inequality for aa.
a<52a < -\frac{5}{2}
Subtract 5 from both sides to get 2a<52a < -5, then divide both sides by 2.

Anahtar Kavram

Solving linear inequalities in one variable with symbolic coefficients and applying the inequality sign reversal rule when multiplying or dividing by a negative value.
Soru 302Soru

An athlete participates in a charity event where they earn money by swimming laps in a pool and running laps on a track. The athlete earns ss dollars for each lap swum and rr dollars for each lap run. Completing 10 laps in the pool and 15 laps on the track raises a total of 135.Completing12lapsinthepooland20lapsonthetrackraisesatotalof135. Completing 12 laps in the pool and 20 laps on the track raises a total of 176. What is the value of rr?

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Cevap: 7

Cevap

The value of rr is 7.
The correct answer is 7. To find this, we translate the word problem into a system of two linear equations: 10s+15r=13510s + 15r = 135 and 12s+20r=17612s + 20r = 176. Simplifying these equations by dividing by their common factors yields 2s+3r=272s + 3r = 27 and 3s+5r=443s + 5r = 44. Multiplying the first equation by 3 gives 6s+9r=816s + 9r = 81, and multiplying the second equation by 2 gives 6s+10r=886s + 10r = 88. Subtracting the two equations eliminates ss and gives r=7r = 7.

Adım Adım Çözüm

1
Write the system of linear equations representing the athlete's earnings.
The system is:
10s+15r=13510s + 15r = 135
12s+20r=17612s + 20r = 176
To represent the relationships between the number of laps completed and the total amount raised.
2
Simplify both equations to work with smaller coefficients.
Divide the first equation by 5:
2s+3r=272s + 3r = 27
Divide the second equation by 4:
3s+5r=443s + 5r = 44
Simplifying equations reduces the likelihood of arithmetic errors.
3
Eliminate the variable ss to solve for rr.
Multiply the first simplified equation by 3 and the second by 2:
3(2s+3r)=3(27)    6s+9r=813(2s + 3r) = 3(27) \implies 6s + 9r = 81
2(3s+5r)=2(44)    6s+10r=882(3s + 5r) = 2(44) \implies 6s + 10r = 88
Subtract the first equation from the second:
(6s+10r)(6s+9r)=8881    r=7(6s + 10r) - (6s + 9r) = 88 - 81 \implies r = 7
Using the elimination method allows us to solve directly for the target variable, rr.

Anahtar Kavram

Solving a system of linear equations in two variables using elimination or substitution.
Soru 303Soru

In the xyxy-plane, the graph of the linear equation y4=m(x6)y - 4 = m(x - 6), where mm is a constant, has a yy-intercept of (0,7)(0, 7). What is the xx-coordinate of the xx-intercept of the line?

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Cevap: 14

Cevap

The correct answer is 14. This is the x-coordinate of the point where the line crosses the x-axis, which is (14, 0).
To find the value of mm, substitute the y-intercept (0,7)(0, 7) into the equation: 74=m(06)7 - 4 = m(0 - 6), which simplifies to 3=6m3 = -6m, so m=12m = -\frac{1}{2}. The equation of the line is y4=12(x6)y - 4 = -\frac{1}{2}(x - 6). The x-intercept occurs when y=0y = 0. Substituting y=0y = 0 gives 4=12(x6)-4 = -\frac{1}{2}(x - 6), which simplifies to 8=x68 = x - 6, so x=14x = 14.

Adım Adım Çözüm

1
Substitute the y-intercept (0,7)(0, 7) into the given equation to solve for the constant mm.
74=m(06)    3=6m    m=127 - 4 = m(0 - 6) \implies 3 = -6m \implies m = -\frac{1}{2}
The y-intercept point (0,7)(0, 7) must satisfy the equation of the line, allowing us to find the slope mm.
2
Write the linear equation using the calculated value of mm.
y4=12(x6)y - 4 = -\frac{1}{2}(x - 6)
Knowing the slope allows us to write the complete linear equation in point-slope form.
3
Find the x-intercept of the line by setting y=0y = 0 and solving for xx.
04=12(x6)    4=12(x6)    8=x6    x=140 - 4 = -\frac{1}{2}(x - 6) \implies -4 = -\frac{1}{2}(x - 6) \implies 8 = x - 6 \implies x = 14
The x-intercept is the point on the line where the y-coordinate is equal to 0.

Anahtar Kavram

Finding the intercepts and slope of a linear equation in two variables.

Alternatif Yöntem

Alternatively, write the equation in slope-intercept form y=mx+by = mx + b. Since the y-intercept is (0,7)(0, 7), we have b=7b = 7, so the equation is y=mx+7y = mx + 7. Since the line passes through the point (6,4)(6, 4) (determined by the point-slope form y4=m(x6)y - 4 = m(x - 6)), substitute this point into the equation: 4=m(6)+7    3=6m    m=124 = m(6) + 7 \implies -3 = 6m \implies m = -\frac{1}{2}. Thus, the equation is y=12x+7y = -\frac{1}{2}x + 7. Setting y=0y = 0 for the x-intercept gives 0=12x+7    12x=7    x=140 = -\frac{1}{2}x + 7 \implies \frac{1}{2}x = 7 \implies x = 14.
Tahmini Süre:1m 30s
Soru 304Soru

A manufacturer plans to produce two models of smartphones: Model X and Model Y. The assembly of each Model X smartphone requires 2.52.5 hours, and the assembly of each Model Y smartphone requires 44 hours. A total of 800800 hours of assembly time is allocated for producing these two models. If the manufacturer produces 120120 Model X smartphones, what is the maximum number of Model Y smartphones that can be produced using the remaining allocated assembly time?

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Cevap: 125

Cevap

The maximum number of Model Y smartphones that can be produced is 125.
The correct answer is the value that satisfies the linear relation under the given constraints. Setting up the equation 2.5x+4y=8002.5x + 4y = 800 and substituting 120120 for xx results in 300+4y=800300 + 4y = 800. Subtracting 300300 from both sides yields 4y=5004y = 500, and dividing by 44 gives 125125 Model Y smartphones.

Adım Adım Çözüm

1
Set up a linear equation representing the total assembly time.
2.5x+4y=8002.5x + 4y = 800, where xx is the number of Model X smartphones and yy is the number of Model Y smartphones.
The total assembly time is the sum of the time spent on Model X (2.52.5 hours per phone) and Model Y (44 hours per phone), which must equal the allocated 800800 hours.
2
Substitute the given number of Model X smartphones into the equation.
2.5(120)+4y=8002.5(120) + 4y = 800, which simplifies to 300+4y=800300 + 4y = 800.
The problem states that the manufacturer produces 120120 Model X smartphones.
3
Isolate the variable representing Model Y smartphones to find its value.
4y=5004y = 500, which simplifies to y=125y = 125.
Subtracting 300300 from both sides of the equation and then dividing by 44 isolates the variable yy.

Anahtar Kavram

Linear Equations in Two Variables
Tahmini Süre:1m 30s
Soru 305Soru

An online retailer uses a linear relationship to determine the shipping cost of an order based on the total weight of the items in the order. The table below shows the shipping cost, yy, in dollars, for an order with a total weight of xx pounds.

Weight (xx pounds)Shipping Cost (yy dollars)
229.509.50
6617.5017.50

What is the shipping cost, in dollars, for an order with a total weight of 1111 pounds?

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Cevap: 27.5

Cevap

The correct shipping cost for an order weighing 11 pounds is 27.5 dollars.
The linear relationship has a constant rate of change (slope). Using the coordinates from the table, (2,9.50)(2, 9.50) and (6,17.50)(6, 17.50), the slope mm is calculated as 17.509.5062=84=2\frac{17.50 - 9.50}{6 - 2} = \frac{8}{4} = 2. Using the point-slope form, the equation of the line is y9.50=2(x2)y - 9.50 = 2(x - 2), which simplifies to y=2x+5.50y = 2x + 5.50. Substituting x=11x = 11 gives y=2(11)+5.50=27.5y = 2(11) + 5.50 = 27.5.

Adım Adım Çözüm

1
Calculate the slope (rate of change) of the linear relationship.
m=2m = 2
Determines the rate at which the shipping cost increases per additional pound of weight.
2
Formulate the linear equation representing the relationship.
y=2x+5.50y = 2x + 5.50
Establishes a functional relationship to calculate costs for any given weight.
3
Evaluate the function at the target weight of 11 pounds.
y=27.5y = 27.5
Determines the final cost of shipping for the specified weight of 11 pounds.

Anahtar Kavram

Determining and evaluating linear functions represented in tabular form
Tahmini Süre:1m 30s
Soru 306Soru

Company A and Company B both rent moving trucks. The total cost A(d)A(d), in dollars, for renting a truck from Company A for dd days is given by A(d)=35d+75A(d) = 35d + 75. The table below shows some values of the total cost B(d)B(d), in dollars, for renting a truck from Company B for dd days.

Days (dd)Total Cost (B(d)B(d))
2150
5300

If the relationship between dd and B(d)B(d) is linear, for how many days of rental will the total cost at Company B be exactly 9595 dollars more than the total cost at Company A?

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Cevap: 8

Cevap

The total cost at Company B will be exactly 95 dollars more than the total cost at Company A for a rental of 8 days.
To find the number of days for which Company B's cost is exactly 95 dollars more than Company A's cost, we first find the linear function for Company B. The rate of change is 30015052=50\frac{300 - 150}{5 - 2} = 50 dollars per day. The initial cost is 15050(2)=50150 - 50(2) = 50 dollars, giving B(d)=50d+50B(d) = 50d + 50. We then set up the equation B(d)A(d)=95B(d) - A(d) = 95, which is (50d+50)(35d+75)=95(50d + 50) - (35d + 75) = 95. Simplifying this equation gives 15d25=9515d - 25 = 95. Adding 25 to both sides gives 15d=12015d = 120, and dividing by 15 gives d=8d = 8.

Adım Adım Çözüm

1
Determine the linear cost function for Company B, B(d)=md+bB(d) = md + b, using the points (2,150)(2, 150) and (5,300)(5, 300) from the table.
The slope is m=30015052=50m = \frac{300 - 150}{5 - 2} = 50. Using (2,150)(2, 150) to find the y-intercept: 150=50(2)+bb=50150 = 50(2) + b \Rightarrow b = 50. Thus, B(d)=50d+50B(d) = 50d + 50.
We need to find the equation representing the total cost of Company B to set up the comparison.
2
Set up an equation where the total cost at Company B is equal to the total cost at Company A plus 95 dollars.
B(d)=A(d)+9550d+50=(35d+75)+95B(d) = A(d) + 95 \Rightarrow 50d + 50 = (35d + 75) + 95.
This represents the condition that Company B's cost is 95 dollars more than Company A's cost.
3
Simplify the equation and solve for the number of days, dd.
50d+50=35d+17015d=120d=850d + 50 = 35d + 170 \Rightarrow 15d = 120 \Rightarrow d = 8.
Isolating the variable dd gives the exact number of days required.

Anahtar Kavram

Comparing linear functions and solving linear equations representing real-world contexts.
Soru 307Soru

A deep-sea research submersible's internal cabin pressure, PP, in atmospheres (atm\text{atm}), is modeled by a linear function of its depth below the ocean surface, dd, in meters. At the surface (d=0d = 0), the internal pressure is 1.0 atm1.0\text{ atm}. For every increase in depth of 100 meters100\text{ meters}, the internal pressure increases by 0.05 atm0.05\text{ atm}. The submersible descends from the surface at a constant rate of 2.5 meters per second2.5\text{ meters per second}. What is the rate of increase of the internal cabin pressure, in atm\text{atm} per hour, as the submersible descends?

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Cevap: 4.5

Cevap

The rate of increase of the internal cabin pressure is 4.54.5 atmospheres per hour.
The rate of change of internal pressure with depth is 0.05 atm100 m=0.0005 atm/m\frac{0.05\text{ atm}}{100\text{ m}} = 0.0005\text{ atm/m}. Since the submersible descends at a rate of 2.5 m/s2.5\text{ m/s}, we convert this rate of depth change to hours: 2.5 m/s×3600 s/hr=9000 m/hr2.5\text{ m/s} \times 3600\text{ s/hr} = 9000\text{ m/hr}. Multiplying the pressure change per meter by the depth change per hour gives the rate of change of the internal pressure per hour: 0.0005 atm/m×9000 m/hr=4.5 atm/hr0.0005\text{ atm/m} \times 9000\text{ m/hr} = 4.5\text{ atm/hr}.

Adım Adım Çözüm

1
Calculate the rate of pressure increase per meter of depth.
0.0005 atm/m0.0005\text{ atm/m}
The pressure increases by 0.05 atm0.05\text{ atm} for every 100 meters100\text{ meters} of depth, giving a rate of change of 0.05 atm100 m=0.0005 atm/m\frac{0.05\text{ atm}}{100\text{ m}} = 0.0005\text{ atm/m}.
2
Determine the distance descended by the submersible in one hour.
9000 meters9000\text{ meters}
With 3600 seconds3600\text{ seconds} in one hour and a descent speed of 2.5 m/s2.5\text{ m/s}, the submersible descends a total of 2.5 m/s×3600 s=9000 meters2.5\text{ m/s} \times 3600\text{ s} = 9000\text{ meters} in one hour.
3
Calculate the rate of internal pressure increase per hour.
4.5 atm/hr4.5\text{ atm/hr}
Multiply the rate of change of pressure per meter (0.0005 atm/m0.0005\text{ atm/m}) by the hourly descent distance (9000 m9000\text{ m}) to obtain 0.0005×9000=4.5 atm/hr0.0005 \times 9000 = 4.5\text{ atm/hr}.

Anahtar Kavram

Interpreting Linear Relationships in Context

Alternatif Yöntem

Write the cabin pressure as a function of time tt, in seconds: P(t)=1.0+0.0005(2.5t)=1.0+0.00125tP(t) = 1.0 + 0.0005(2.5t) = 1.0 + 0.00125t. The slope of this line, 0.00125 atm/s0.00125\text{ atm/s}, represents the rate of increase per second. To convert this rate to hours, multiply by 3600 seconds/hour3600\text{ seconds/hour}: 0.00125×3600=4.5 atm/hr0.00125 \times 3600 = 4.5\text{ atm/hr}.
Tahmini Süre:2m 0s
Soru 308Soru

During a chemistry experiment, the temperature of a liquid increases at a constant rate. The temperature of the liquid is 24C24^\circ\text{C} at 55 minutes after the experiment starts, and 48C48^\circ\text{C} at 1515 minutes after the experiment starts. The temperature TT, in degrees Celsius, of the liquid tt minutes after the experiment starts can be modeled by the equation T=mt+bT = mt + b, where mm and bb are constants. What is the value of bb?

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Cevap: 12

Cevap

12
The correct answer is 12. By translating the given information into two points on the line, (5,24)(5, 24) and (15,48)(15, 48), we can find the slope m=4824155=2.4m = \frac{48 - 24}{15 - 5} = 2.4. Substituting this slope and the point (5,24)(5, 24) into T=mt+bT = mt + b yields 24=2.4(5)+b24 = 2.4(5) + b, which simplifies to 24=12+b24 = 12 + b. Solving for bb gives b=12b = 12.

Adım Adım Çözüm

1
Identify the data points representing the relationship between time and temperature.
The two data points are (t1,T1)=(5,24)(t_1, T_1) = (5, 24) and (t2,T2)=(15,48)(t_2, T_2) = (15, 48).
These points represent coordinates (t,T)(t, T) on the line representing the temperature over time.
2
Calculate the slope mm of the linear equation.
m=4824155=2410=2.4m = \frac{48 - 24}{15 - 5} = \frac{24}{10} = 2.4
The slope represents the constant rate of temperature increase per minute.
3
Substitute the slope mm and the coordinates of one point into the equation T=mt+bT = mt + b to solve for the y-intercept bb.
24=2.4(5)+b    24=12+b    b=1224 = 2.4(5) + b \implies 24 = 12 + b \implies b = 12
This determines the value of the constant bb, which corresponds to the initial temperature of the liquid.

Anahtar Kavram

Determining the y-intercept of a linear model in two variables given two points.
Soru 309Soru

An online store sells two types of monthly subscription plans: a basic plan for 12permonthandapremiumplanfor12 per month and a premium plan for 20 per month. In April, the store had a total of 150 active subscribers for these two plans and collected a total of $2,280 in subscription fees. How many of the active subscribers in April were on the premium plan?

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Cevap: 60

Cevap

60
By representing the number of basic subscribers as xx and premium subscribers as yy, we set up the system of equations x+y=150x + y = 150 and 12x+20y=228012x + 20y = 2280. Solving for xx in the first equation gives x=150yx = 150 - y. Substituting this into the second equation yields 12(150y)+20y=228012(150 - y) + 20y = 2280. Distributing the 12 and combining like terms gives 1800+8y=22801800 + 8y = 2280. Subtracting 1800 from both sides gives 8y=4808y = 480, and dividing by 8 results in y=60y = 60. Therefore, there were 60 premium subscribers.

Adım Adım Çözüm

1
Define variables for the unknown quantities: let xx represent the number of basic subscribers and let yy represent the number of premium subscribers.
The system of equations is: x+y=150x + y = 150 and 12x+20y=228012x + 20y = 2280.
Translate the given information about total subscribers and total revenue into algebraic equations.
2
Express xx in terms of yy using the first equation (x=150yx = 150 - y) and substitute it into the second equation.
The substituted equation is: 12(150y)+20y=228012(150 - y) + 20y = 2280, which expands to 180012y+20y=22801800 - 12y + 20y = 2280.
Eliminate one variable to create a single equation with only one variable, yy.
3
Simplify the equation and isolate yy.
1800+8y=2280    8y=480    y=601800 + 8y = 2280 \implies 8y = 480 \implies y = 60.
Combine like terms and use basic operations to solve for the number of premium subscribers.

Anahtar Kavram

Solving a system of two linear equations using substitution or elimination.
Tahmini Süre:1m 30s
Soru 310Soru

A point (x,y)(x, y) in the coordinate plane satisfies the system of inequalities below.

y2x4y \geq 2x - 4
yx+5y \leq -x + 5
x0x \geq 0
y0y \geq 0

What is the maximum possible value of xx for this point?

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Cevap: 3

Cevap

The maximum possible value of xx that satisfies the system of inequalities is 3.
To find the maximum possible value of xx for a point satisfying the system of inequalities, we identify the vertices of the region. The upper-right boundary of the region is formed by the intersection of the lines y=2x4y = 2x - 4 and y=x+5y = -x + 5. Solving 2x4=x+52x - 4 = -x + 5 gives 3x=9    x=33x = 9 \implies x = 3. At this point, y=3+5=2y = -3 + 5 = 2, which satisfies the constraints x0x \geq 0 and y0y \geq 0. The other boundary vertices of the region are (0,0)(0, 0), (2,0)(2, 0), and (0,5)(0, 5). Comparing the x-coordinates of these vertices (00, 22, and 33), we see that the maximum possible value of xx is 33.

Adım Adım Çözüm

1
Find the intersection point of the boundary lines y=2x4y = 2x - 4 and y=x+5y = -x + 5.
x=3x = 3
Setting the two boundary line equations equal to each other (2x4=x+52x - 4 = -x + 5) allows us to find the x-coordinate where the boundaries cross.
2
Substitute x=3x = 3 back into one of the boundary equations to find the y-coordinate.
y=2y = 2
This yields the intersection point (3,2)(3, 2) which lies on both boundary lines.
3
Verify that the intersection point (3,2)(3, 2) satisfies the other constraints: x0x \geq 0 and y0y \geq 0.
303 \geq 0 and 202 \geq 0 (both true)
The point must lie within the first quadrant to be a valid solution.
4
Determine the remaining boundary vertices of the solution region in the first quadrant.
Vertices are (0,0)(0, 0), (0,5)(0, 5), (2,0)(2, 0), and (3,2)(3, 2).
Comparing all vertices will confirm if (3,2)(3, 2) indeed provides the maximum value of xx.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Soru 311Soru

A logistics company uses a delivery drone to transport two types of packages. Let xx represent the number of Type A packages and yy represent the number of Type B packages in a single flight. The drone can carry at most 12 packages in total. Additionally, to balance the drone, the total weight of the cargo must be at least 15 pounds. Each Type A package weighs 2 pounds, and each Type B package weighs 1 pound. Which of the following combinations of Type A and Type B packages is a viable shipment for the drone?

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Cevap: 5 Type A packages and 6 Type B packages

Cevap

5 Type A packages and 6 Type B packages
The correct combination of 5 Type A packages and 6 Type B packages satisfies all system requirements. The total package count of 11 is less than or equal to the drone's limit of 12 packages (5+6125 + 6 \leq 12). Furthermore, the total weight of 16 pounds meets the minimum balance requirement of 15 pounds (2(5)+6152(5) + 6 \geq 15).

Adım Adım Çözüm

1
Write the system of linear inequalities that represents the given constraints.
The capacity constraint is x+y12x + y \leq 12, and the weight constraint is 2x+y152x + y \geq 15, where xx and yy are non-negative integers.
To define the mathematical boundaries for a valid shipment.
2
Substitute the package counts from the correct combination into both inequalities to verify they are satisfied.
For 5 Type A packages (x=5x = 5) and 6 Type B packages (y=6y = 6):
- Package count: 5+6=11125 + 6 = 11 \leq 12 (True)
- Cargo weight: 2(5)+6=16152(5) + 6 = 16 \geq 15 (True)
To confirm that the chosen combination satisfies all system requirements.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Tahmini Süre:1m 30s
Soru 312Soru

A coffee shop sells two sizes of bagged coffee: a standard bag and a deluxe bag. On Monday, the shop sold 88 standard bags and 55 deluxe bags for a total of $108\$108. On Tuesday, the shop sold 66 standard bags and 1010 deluxe bags for a total of $156\$156. What is the price, in dollars, of one deluxe bag of coffee?

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Cevap: 12

Cevap

The price of one deluxe bag of coffee is 1212 dollars.
By setting up a system of equations, we represent the total cost on Monday as 8s+5d=1088s + 5d = 108 and on Tuesday as 6s+10d=1566s + 10d = 156. Multiplying the first equation by 22 gives 16s+10d=21616s + 10d = 216. Subtracting the second equation yields 10s=6010s = 60, so s=6s = 6. Substituting s=6s = 6 into the first equation yields 8(6)+5d=1088(6) + 5d = 108, which simplifies to 48+5d=10848 + 5d = 108, then 5d=605d = 60, and finally d=12d = 12.

Adım Adım Çözüm

1
Define the variables and write the system of equations.
Let ss be the price of a standard bag and dd be the price of a deluxe bag. The system is:
8s+5d=1088s + 5d = 108
6s+10d=1566s + 10d = 156
To translate the word problem into mathematical equations.
2
Multiply the first equation by 22 to align the coefficients of dd.
16s+10d=21616s + 10d = 216
To prepare for elimination of the variable dd.
3
Subtract the second equation from the new equation to solve for ss.
10s=6010s = 60, which simplifies to s=6s = 6.
To eliminate dd and find the price of a standard bag.
4
Substitute the value of ss back into one of the original equations to solve for dd.
8(6)+5d=108    48+5d=108    5d=60    d=128(6) + 5d = 108 \implies 48 + 5d = 108 \implies 5d = 60 \implies d = 12.
To find the price of a deluxe bag.

Anahtar Kavram

Solving systems of linear equations using the elimination method.
Tahmini Süre:1m 30s
Soru 313Soru

A geophysicist models the temperature, TT, in degrees Celsius (C^\circ\text{C}), of a rock layer during a deep-crust drilling project using a linear function of the depth, dd, in kilometers (km\text{km}), below the surface. According to the model, for every increase in depth of 0.8 km0.8\text{ km}, the temperature of the rock increases by 22C22^\circ\text{C}. At a depth of 2.4 km2.4\text{ km}, the temperature of the rock is 81C81^\circ\text{C}. According to the model, at what depth, in kilometers, will the temperature of the rock be 114C114^\circ\text{C}?

Cevabı ve açıklamayı göster

Cevap: 3.6

Cevap

The temperature of the rock will reach 114C114^\circ\text{C} at a depth of 3.63.6 kilometers.
The correct answer is 3.63.6. The rate of change of temperature with depth is 22C0.8 km=27.5C/km\frac{22^\circ\text{C}}{0.8\text{ km}} = 27.5^\circ\text{C/km}. The linear relationship between temperature TT and depth dd can be modeled by T=27.5d+T0T = 27.5d + T_0, where T0T_0 is the temperature at the surface. Substituting the known values d=2.4d = 2.4 and T=81T = 81 into the model gives 81=27.5(2.4)+T081 = 27.5(2.4) + T_0, which simplifies to 81=66+T081 = 66 + T_0. Solving for T0T_0 yields T0=15T_0 = 15. Thus, the model is T=27.5d+15T = 27.5d + 15. To find the depth when the temperature is 114C114^\circ\text{C}, substitute T=114T = 114 into the model: 114=27.5d+15114 = 27.5d + 15. Subtracting 1515 from both sides gives 99=27.5d99 = 27.5d, and dividing by 27.527.5 yields d=3.6d = 3.6.

Adım Adım Çözüm

1
Find the rate of change (slope) of the temperature with respect to depth.
The slope is 27.5C/km27.5^\circ\text{C/km}.
The temperature increases by 22C22^\circ\text{C} for every 0.8 km0.8\text{ km} of depth, so the rate of change is 22C0.8 km=27.5C/km\frac{22^\circ\text{C}}{0.8\text{ km}} = 27.5^\circ\text{C/km}.
2
Set up a linear model and find the surface temperature (y-intercept).
The linear model is T=27.5d+15T = 27.5d + 15.
Using the slope-intercept form T=md+T0T = md + T_0 and substituting the given values d=2.4d = 2.4 and T=81T = 81 gives 81=27.5(2.4)+T081 = 27.5(2.4) + T_0, which simplifies to 81=66+T081 = 66 + T_0, so T0=15T_0 = 15.
3
Substitute the target temperature into the linear model and solve for the target depth.
d=3.6d = 3.6
Substitute T=114T = 114 into the equation T=27.5d+15T = 27.5d + 15 to get 114=27.5d+15114 = 27.5d + 15. Subtracting 1515 from both sides gives 99=27.5d99 = 27.5d. Dividing both sides by 27.527.5 yields d=3.6d = 3.6.

Anahtar Kavram

Interpreting slope and solving for values in a linear relationship context.

Alternatif Yöntem

Find the required temperature increase: 114C81C=33C114^\circ\text{C} - 81^\circ\text{C} = 33^\circ\text{C}. Set up a proportion using the rate of 22C22^\circ\text{C} increase per 0.8 km0.8\text{ km} to find the change in depth Δd\Delta d: 33CΔd=22C0.8 km    Δd=33×0.822=1.2 km\frac{33^\circ\text{C}}{\Delta d} = \frac{22^\circ\text{C}}{0.8\text{ km}} \implies \Delta d = \frac{33 \times 0.8}{22} = 1.2\text{ km}. Add this change in depth to the initial depth to find the final depth: 2.4+1.2=3.6 km2.4 + 1.2 = 3.6\text{ km}.
Tahmini Süre:2m 0s
Soru 314Soru

In the inequality 3(42x)5(xc)73(4 - 2x) - 5(x - c) \geq -7, where cc is a constant, the solution set consists of all values of xx such that x3x \leq 3. What is the value of cc?

Cevabı ve açıklamayı göster

Cevap: 2.8

Cevap

2.8
To find the value of cc, first simplify the inequality 3(42x)5(xc)73(4 - 2x) - 5(x - c) \geq -7 by expanding the terms using the distributive property, which yields 126x5x+5c712 - 6x - 5x + 5c \geq -7. Combining like terms gives 11x+12+5c7-11x + 12 + 5c \geq -7. Next, isolate the variable term by subtracting 1212 and 5c5c from both sides to obtain 11x195c-11x \geq -19 - 5c. Dividing both sides of the inequality by 11-11 and reversing the inequality sign results in x19+5c11x \leq \frac{19 + 5c}{11}. Given that the solution set consists of all values of xx such that x3x \leq 3, the boundary value 19+5c11\frac{19 + 5c}{11} must equal 33. Solving the equation 19+5c11=3\frac{19 + 5c}{11} = 3 gives 19+5c=3319 + 5c = 33, which simplifies to 5c=145c = 14 and results in c=2.8c = 2.8.

Adım Adım Çözüm

1
Distribute the constants on the left side of the inequality.
126x5x+5c712 - 6x - 5x + 5c \geq -7
Applying the distributive property simplifies the parentheses.
2
Combine the variable terms.
11x+12+5c7-11x + 12 + 5c \geq -7
Grouping like terms simplifies the inequality.
3
Subtract 1212 and 5c5c from both sides of the inequality.
11x195c-11x \geq -19 - 5c
This isolates the term containing xx.
4
Divide both sides by 11-11 and reverse the direction of the inequality.
x19+5c11x \leq \frac{19 + 5c}{11}
Dividing by a negative number requires flipping the inequality sign to maintain equivalence.
5
Set the algebraic boundary 19+5c11\frac{19 + 5c}{11} equal to the given boundary value of 33 and solve for cc.
c=2.8c = 2.8
Since the solution set is x3x \leq 3, the boundary values must be equivalent.

Anahtar Kavram

Solving multi-step linear inequalities in one variable containing parameters.
Soru 315Soru

The graph of the equation ax+by=24ax + by = 24, where aa and bb are constants, is a line in the xyxy-plane. If this line passes through the points (2,9)(2, 9) and (6,3)(6, 3), what is the value of a+ba + b?

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Cevap: 5

Cevap

The value of a+ba + b is 55.
Substituting the coordinates of the two points (2,9)(2, 9) and (6,3)(6, 3) into the given linear equation ax+by=24ax + by = 24 yields a system of two equations: 2a+9b=242a + 9b = 24 and 6a+3b=246a + 3b = 24. Simplifying the second equation gives 2a+b=82a + b = 8, which means b=82ab = 8 - 2a. Substituting this expression for bb into the first equation yields 2a+9(82a)=242a + 9(8 - 2a) = 24, which simplifies to 16a=48-16a = -48, or a=3a = 3. Plugging a=3a = 3 back into b=82ab = 8 - 2a gives b=2b = 2. Thus, the value of a+ba + b is 3+2=53 + 2 = 5.

Adım Adım Çözüm

1
Substitute the point (2,9)(2, 9) into the equation ax+by=24ax + by = 24.
2a+9b=242a + 9b = 24
Since the line passes through the point (2,9)(2, 9), the coordinates must satisfy the equation of the line.
2
Substitute the point (6,3)(6, 3) into the equation ax+by=24ax + by = 24.
6a+3b=246a + 3b = 24
Since the line passes through the point (6,3)(6, 3), the coordinates must satisfy the equation of the line.
3
Solve the system of equations for aa and bb.
a=3a = 3 and b=2b = 2
To find the values of the constants aa and bb, we solve the linear system: (1) 2a+9b=242a + 9b = 24 and (2) 6a+3b=246a + 3b = 24. Dividing the second equation by 3 gives 2a+b=82a + b = 8, or b=82ab = 8 - 2a. Substituting this into the first equation gives 2a+9(82a)=24    2a+7218a=24    16a=48    a=32a + 9(8 - 2a) = 24 \implies 2a + 72 - 18a = 24 \implies -16a = -48 \implies a = 3. Then, b=82(3)=2b = 8 - 2(3) = 2.
4
Add the values of aa and bb.
a+b=5a + b = 5
The question asks for the value of a+ba + b.

Anahtar Kavram

Solving systems of linear equations derived from coordinate substitution in a two-variable linear equation.
Tahmini Süre:1m 30s
Soru 316Soru

For a constant kk, the inequality 2(3x)k(x+5)>42(3 - x) - k(x + 5) > 4 has the solution set x<3x < -3. What is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 44

Cevap

4
The correct answer is 44. Expanding the inequality 2(3x)k(x+5)>42(3 - x) - k(x + 5) > 4 gives 62xkx5k>46 - 2x - kx - 5k > 4. Grouping the xx terms yields (2k)x>5k2(-2 - k)x > 5k - 2. Because the given solution set is x<3x < -3, the inequality sign must flip, indicating that the coefficient 2k-2 - k is negative. Dividing by this negative coefficient yields x<5k22kx < \frac{5k - 2}{-2 - k}. Setting the boundary expression equal to the boundary of the solution set gives 5k22k=3\frac{5k - 2}{-2 - k} = -3. Multiplying both sides by 2k-2 - k results in 5k2=6+3k5k - 2 = 6 + 3k. Subtracting 3k3k and adding 22 to both sides gives 2k=82k = 8, which simplifies to k=4k = 4.

Adım Adım Çözüm

1
Distribute the constants in the inequality
62xkx5k>46 - 2x - kx - 5k > 4
To clear parentheses and prepare to group terms.
2
Group the xx terms and constant terms
(2k)x>5k2(-2 - k)x > 5k - 2
To isolate the variable xx on one side of the inequality.
3
Divide by the coefficient of xx and flip the inequality direction
x<5k22kx < \frac{5k - 2}{-2 - k}
Since the solution set is x<3x < -3, the direction of the inequality must flip from >> to <<, meaning the coefficient 2k-2 - k must be negative.
4
Set the boundary value equal to 3-3 and solve for kk
k=4k = 4
The boundary of the solution set must be equal to 3-3. Solving 5k22k=3\frac{5k - 2}{-2 - k} = -3 yields 5k2=6+3k5k - 2 = 6 + 3k, which simplifies to 2k=82k = 8, so k=4k = 4.

Anahtar Kavram

Solving linear inequalities in one variable with symbolic coefficients, accounting for direction flips when dividing by negative quantities.
Soru 317Soru

An IT administrator uses the equation T=0.06r+40T = 0.06r + 40 to model the total time TT, in milliseconds, required to retrieve rr records from a cloud database. The constant term in the model represents the total setup time, which consists of network latency and database connection overhead. If the database connection overhead is 20% of the total setup time, which of the following is the best interpretation of the value 8 in this model?

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Cevap: The database connection overhead, in milliseconds, for retrieving any number of records.

Cevap

The database connection overhead, in milliseconds, for retrieving any number of records.
In the linear model T=0.06r+40T = 0.06r + 40, the constant term of 4040 represents the total setup time in milliseconds, which is independent of the number of records rr retrieved. The database connection overhead is 20%20\% of this total setup time, which equals 0.20×40=80.20 \times 40 = 8 milliseconds. Since it is part of the constant term, it represents a fixed overhead of 88 milliseconds for retrieving any number of records.

Adım Adım Çözüm

1
Identify the constant term in the linear model T=0.06r+40T = 0.06r + 40.
The constant term (y-intercept) is 4040, which represents the total setup time of 4040 milliseconds when r=0r = 0 records are retrieved.
In a linear relationship of the form y=mx+by = mx + b, the constant term bb represents the initial value or y-intercept.
2
Calculate the database connection overhead.
The database connection overhead is 20%20\% of the 4040 milliseconds total setup time, which is 0.20×40=80.20 \times 40 = 8 milliseconds.
The problem states that the database connection overhead is 20% of the total setup time.
3
Interpret the calculated value of 8 in the context of the model.
Since the 4040 milliseconds is a constant term that does not depend on the number of records rr, the 88 milliseconds represents a fixed database connection overhead for any number of records retrieved.
The constant term in a linear model represents a fixed value that does not scale with the independent variable.

Anahtar Kavram

Interpreting the constant term (y-intercept) and its components in a linear relationship context.
Soru 318Soru

A community theater sold adult tickets and student tickets for its opening weekend performances. On Friday, the theater sold 2020 adult tickets and 4040 student tickets for a total of $760\$760. On Saturday, the theater sold 3535 adult tickets and 3030 student tickets for a total of $930\$930. What is the price, in dollars, of one adult ticket?

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Cevap: 18

Cevap

The price of one adult ticket is 18 dollars.
The price of one adult ticket is 1818. By setting up the system of linear equations representing the total sales on Friday (20x+40y=76020x + 40y = 760) and Saturday (35x+30y=93035x + 30y = 930), where xx is the adult ticket price and yy is the student ticket price, we can simplify them to x+2y=38x + 2y = 38 and 7x+6y=1867x + 6y = 186. Multiplying the first simplified equation by 33 gives 3x+6y=1143x + 6y = 114. Subtracting this equation from 7x+6y=1867x + 6y = 186 eliminates yy and yields 4x=724x = 72, which simplifies to x=18x = 18.

Adım Adım Çözüm

1
Define variables and write the system of linear equations based on the given information.
Let xx represent the price of an adult ticket and yy represent the price of a student ticket. The system of equations is:
20x+40y=76020x + 40y = 760
35x+30y=93035x + 30y = 930
Variables represent the unknown quantities, and the equations relate these quantities to the total sales on Friday and Saturday.
2
Simplify both equations by dividing by their greatest common divisors.
Divide the first equation by 2020:
x+2y=38x + 2y = 38
Divide the second equation by 55:
7x+6y=1867x + 6y = 186
Simplifying equations reduces the coefficient values and minimizes the chance of arithmetic errors in later steps.
3
Use the elimination method to solve for xx. Multiply the first simplified equation by 33 to align the yy-coefficients.
3(x+2y)=3(38)3x+6y=1143(x + 2y) = 3(38) \Rightarrow 3x + 6y = 114
Matching the coefficients of yy allows us to eliminate the variable yy by subtracting the equations.
4
Subtract the equation obtained in Step 3 from the second simplified equation.
(7x+6y)(3x+6y)=1861144x=72(7x + 6y) - (3x + 6y) = 186 - 114 \Rightarrow 4x = 72
Subtracting the equations eliminates yy, leaving a single linear equation in terms of xx.
5
Solve for xx by dividing both sides of the equation by 44.
x=18x = 18
Isolating xx provides the price of one adult ticket.

Anahtar Kavram

Solving a system of linear equations using substitution or elimination.

Alternatif Yöntem

Instead of using elimination on the simplified equations, you can use substitution. Express xx in terms of yy using the first simplified equation: x=382yx = 38 - 2y. Substitute this expression into the second equation: 7(382y)+6y=1867(38 - 2y) + 6y = 186. Expanding this gives 26614y+6y=186266 - 14y + 6y = 186, which simplifies to 2668y=186266 - 8y = 186. Subtracting 266266 from both sides gives 8y=80-8y = -80, which solves to y=10y = 10. Finally, substitute y=10y = 10 back into x=382yx = 38 - 2y to find x=382(10)=18x = 38 - 2(10) = 18.
Tahmini Süre:1m 30s
Soru 319Soru

In the xyxy-plane, a point with coordinates (x,y)(x, y) lies in the region defined by the system of inequalities below.

y+2x12y + 2x \leq 12
x2y6x - 2y \leq 6
x2x \geq 2

What is the maximum possible value of yy?

Cevabı ve açıklamayı göster

Cevap: 8

Cevap

8
The system of inequalities bounds the solution set. The upper boundary is given by y2x+12y \leq -2x + 12. Because the slope is negative, the maximum value of yy on this boundary occurs at the smallest possible value of xx. The constraint x2x \geq 2 dictates that the minimum value of xx is 2. Substituting x=2x = 2 into the boundary equation yields y=2(2)+12=8y = -2(2) + 12 = 8. Checking this coordinate against the third inequality, 22(8)=1462 - 2(8) = -14 \leq 6, verifies that (2,8)(2, 8) is a valid solution.

Adım Adım Çözüm

1
Express the first two inequalities in terms of y.
y2x+12y \leq -2x + 12 and y12x3y \geq \frac{1}{2}x - 3
This helps identify the upper and lower boundaries of the solution region.
2
Determine the boundary line that limits the maximum values of y.
The upper boundary is the line y=2x+12y = -2x + 12.
Since the inequality is y2x+12y \leq -2x + 12, any solution must lie on or below this line.
3
Find the maximum value of y on this boundary line given the constraint x2x \geq 2.
y2(2)+12=8y \leq -2(2) + 12 = 8
Since the slope of the boundary line is negative, y is maximized when x is at its minimum value, which is 2.
4
Verify that the point (2,8)(2, 8) satisfies the inequality x2y6x - 2y \leq 6.
22(8)=1462 - 2(8) = -14 \leq 6, which is true.
This confirms that the point (2,8)(2, 8) is indeed in the solution set of the system.

Anahtar Kavram

Maximizing a coordinate value subject to a system of linear inequalities in two variables

Alternatif Yöntem

Instead of graphing or checking boundaries, we can algebraically solve for the boundary. Since x2x \geq 2, multiplying by 2-2 and reversing the inequality gives 2x4-2x \leq -4. Adding 12 to both sides gives 2x+128-2x + 12 \leq 8. Since y2x+12y \leq -2x + 12, we get y8y \leq 8. Checking if y=8y = 8 and x=2x = 2 satisfies the second inequality x2y6x - 2y \leq 6 confirms that 216=1462 - 16 = -14 \leq 6 is true, meaning y=8y = 8 is indeed a valid solution and thus the maximum.
Tahmini Süre:1m 30s
Soru 320Soru

A shipping container has a maximum weight capacity of 24,15024,150 kilograms. The container is loaded with 1212 machinery units, each weighing 1,1501,150 kilograms. The remaining space will be filled with packing crates, each weighing 180180 kilograms. A safety regulation requires that a clearance weight of at least 15%15\% of the total loaded weight (the combined weight of the machinery units and the packing crates) must be left unused. What is the maximum number of packing crates that can be loaded into the container?

Cevabı ve açıklamayı göster

Cevap: 40

Cevap

The maximum number of packing crates that can be loaded is 40.
By setting up the inequality representing the physical constraints, we find that the number of packing crates, xx, must satisfy x40x \le 40. Since the question asks for the maximum number of packing crates, the maximum value is 40.

Adım Adım Çözüm

1
Calculate the constant weight of the machinery units.
The total weight of the 1212 machinery units is 12×1,150=13,80012 \times 1,150 = 13,800 kilograms.
This establishes the base weight that is already loaded in the container.
2
Define the variable and write the expression for the total loaded weight.
Let xx be the number of packing crates. The total loaded weight is 13,800+180x13,800 + 180x kilograms.
This represents the combined weight of the machinery and the crates in terms of the variable xx.
3
Set up the inequality representing the safety clearance requirement.
24,150(13,800+180x)0.15(13,800+180x)24,150 - (13,800 + 180x) \ge 0.15(13,800 + 180x)
The unused weight capacity (maximum capacity minus loaded weight) must be at least 15%15\% of the loaded weight.
4
Solve the inequality for xx.
24,1501.15(13,800+180x)    21,00013,800+180x    7,200180x    x4024,150 \ge 1.15(13,800 + 180x) \implies 21,000 \ge 13,800 + 180x \implies 7,200 \ge 180x \implies x \le 40.
Isolating xx gives the range of allowable values for the number of packing crates.

Anahtar Kavram

Formulating and solving linear inequalities in one variable based on real-world constraints.
ÖncekiSayfa 16 / 22Sonraki
Algebra Alıştırma Soruları — SAT — Sayfa 16 | Examkin