Algebra

432 soru

Soru 41Soru
In a science experiment, the temperature yy, in degrees Celsius, and the time xx, in minutes, are related by a system of equations. The relationships are given by:
y=2x3y = 2x - 3
3xy=83x - y = 8
What is the value of xx in the solution to this system?
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Cevap: 5

Cevap

5
The correct answer is 5. Substituting the expression for yy from the first equation into the second equation yields 3x(2x3)=83x - (2x - 3) = 8. Distributing the negative sign results in 3x2x+3=83x - 2x + 3 = 8. Combining the variable terms gives x+3=8x + 3 = 8. Subtracting 3 from both sides isolates xx, giving x=5x = 5.

Adım Adım Çözüm

1
Substitute the expression for yy from the first equation, y=2x3y = 2x - 3, into the second equation.
3x(2x3)=83x - (2x - 3) = 8
This eliminates the variable yy so the equation can be solved directly for xx.
2
Distribute the negative sign to both terms inside the parentheses.
3x2x+3=83x - 2x + 3 = 8
Distributing the negative sign to both 2x2x and 3-3 simplifies the expression correctly.
3
Combine like terms on the left side of the equation.
x+3=8x + 3 = 8
Subtracting 2x2x from 3x3x leaves a single xx term.
4
Subtract 3 from both sides of the equation to isolate xx.
x=5x = 5
This isolates the variable xx to find the final solution.

Anahtar Kavram

Solving systems of linear equations using substitution
Tahmini Süre:1m 0s
Soru 42Soru
In the equation below, aa and bb are constants.
a(x1)2(3x+b)3=4(x5)a(bx)6\frac{a(x - 1) - 2(3x + b)}{3} = \frac{4(x - 5) - a(b - x)}{6}
If the equation has infinitely many solutions for xx, what is the value of aba - b?
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Cevap: 15

Cevap

The value of aba - b is 15.
The correct answer is 15. Multiplying the entire equation by 6 to clear the denominators, distributing the terms, and grouping them yields (2a12)x(2a+4b)=(a+4)x(ab+20)(2a - 12)x - (2a + 4b) = (a + 4)x - (ab + 20). For the equation to have infinitely many solutions, the coefficients of xx on both sides must be equal (2a12=a+42a - 12 = a + 4), and the constant terms must also be equal (2a+4b=ab+202a + 4b = ab + 20). Solving this system of equations yields a=16a = 16 and b=1b = 1. The difference aba - b is 161=1516 - 1 = 15.

Adım Adım Çözüm

1
Eliminate the denominators by multiplying both sides of the equation by 6.
2[a(x1)2(3x+b)]=4(x5)a(bx)2[a(x - 1) - 2(3x + b)] = 4(x - 5) - a(b - x)
Multiplying both sides by the least common multiple of 3 and 6 simplifies the equation by removing the fractions.
2
Expand both sides of the equation using the distributive property.
2[axa6x2b]=4x20ab+ax2[ax - a - 6x - 2b] = 4x - 20 - ab + ax which simplifies to 2ax2a12x4b=ax+4xab202ax - 2a - 12x - 4b = ax + 4x - ab - 20
Distributing the constants outside the parentheses allows us to group like terms.
3
Group the xx-terms and constant terms on each side of the equation.
(2a12)x(2a+4b)=(a+4)x(ab+20)(2a - 12)x - (2a + 4b) = (a + 4)x - (ab + 20)
Structuring the equation in the form Ax+B=Cx+DAx + B = Cx + D makes it easier to compare the coefficients.
4
Set up a system of equations by equating the coefficients of xx and the constant terms from both sides.
2a12=a+42a - 12 = a + 4 and 2a+4b=ab+202a + 4b = ab + 20
For a linear equation to have infinitely many solutions, the coefficient of xx on both sides must be equal, and the constant terms on both sides must also be equal.
5
Solve the first equation for aa.
a=16a = 16
Subtracting aa and adding 12 to both sides isolates the variable aa.
6
Substitute a=16a = 16 into the second equation and solve for bb.
2(16)+4b=16b+20    32+4b=16b+20    12=12b    b=12(16) + 4b = 16b + 20 \implies 32 + 4b = 16b + 20 \implies 12 = 12b \implies b = 1
Substituting the known value of aa leaves a single linear equation in terms of bb.
7
Calculate the value of aba - b.
161=1516 - 1 = 15
This is the final value requested by the question.

Anahtar Kavram

Solving linear equations in one variable with infinitely many solutions by equating coefficients on both sides of the equation.
Soru 43Soru

A water tank contains 24 gallons of water. Water is being drained from the tank at a constant rate. After 8 minutes, the tank contains 14 gallons of water. If the volume of water in the tank, in gallons, is a linear function of the time in minutes, how many minutes will it take for the tank to contain exactly 4 gallons of water?

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Cevap: 16

Cevap

16
The volume of water in the tank decreases linearly from an initial value of 2424 gallons at t=0t = 0 to 1414 gallons at t=8t = 8. The constant rate of change (slope) is calculated by dividing the change in volume by the change in time: 142480=1.25\frac{14 - 24}{8 - 0} = -1.25 gallons per minute. Using the slope-intercept form, the volume VV at time tt is given by V=1.25t+24V = -1.25t + 24. Setting the volume V=4V = 4 gives the equation 4=1.25t+244 = -1.25t + 24. Solving for tt yields 20=1.25t-20 = -1.25t, which simplifies to t=16t = 16.

Adım Adım Çözüm

1
Determine the initial state and the state after 8 minutes as coordinate points.
The initial state is (0,24)(0, 24) and the state after 88 minutes is (8,14)(8, 14).
These coordinates represent the relationship between time and volume of water in the tank.
2
Calculate the slope (constant rate of change) of the linear function.
Slope m=142480=1.25m = \frac{14 - 24}{8 - 0} = -1.25
The slope represents the constant rate at which water is being drained from the tank.
3
Formulate the linear equation.
V(t)=1.25t+24V(t) = -1.25t + 24
Using the slope-intercept form V(t)=mt+bV(t) = mt + b, where b=24b = 24 is the vertical intercept representing the initial volume.
4
Solve for the time tt when the volume of water is 44 gallons.
4=1.25t+24    20=1.25t    t=164 = -1.25t + 24 \implies -20 = -1.25t \implies t = 16
To find the time at which the volume decreases to exactly 44 gallons.

Anahtar Kavram

Linear Functions and Graphs
Soru 44Soru

If 5(x3)2x=95(x - 3) - 2x = 9, what is the value of xx?

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Cevap: 8

Cevap

The value of xx is 88.
To solve the equation, distribute the 5 to the terms inside the parentheses to get 5x152x=95x - 15 - 2x = 9. Combine the like terms 5x5x and 2x-2x to simplify the equation to 3x15=93x - 15 = 9. Add 15 to both sides to isolate the variable term, which yields 3x=243x = 24. Finally, divide both sides by 3 to find x=8x = 8.

Adım Adım Çözüm

1
Distribute the 55 to the terms inside the parentheses.
5x152x=95x - 15 - 2x = 9
To remove the parentheses and begin simplifying the equation.
2
Combine the like variable terms 5x5x and 2x-2x.
3x15=93x - 15 = 9
To group the x terms together.
3
Add 1515 to both sides of the equation.
3x=243x = 24
To isolate the term with the variable on one side.
4
Divide both sides of the equation by 33.
x=8x = 8
To solve for xx.

Anahtar Kavram

Solving linear equations in one variable using the distributive property, combining like terms, and applying inverse operations.
Tahmini Süre:45s
Soru 45Soru

If 25(3x4)13(2x+5)=15x+1115\frac{2}{5}(3x - 4) - \frac{1}{3}(2x + 5) = \frac{1}{5}x + \frac{11}{15}, what is the value of 2x72x - 7?

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Cevap: 17

Cevap

The correct answer is 17.
To find the value of 2x72x - 7, first solve the linear equation for xx. Distributing the coefficients on the left side of the equation gives 65x8523x53=15x+1115\frac{6}{5}x - \frac{8}{5} - \frac{2}{3}x - \frac{5}{3} = \frac{1}{5}x + \frac{11}{15}. Combining the variable terms and constants on the left side results in 815x4915=315x+1115\frac{8}{15}x - \frac{49}{15} = \frac{3}{15}x + \frac{11}{15}. Subtracting 315x\frac{3}{15}x and adding 4915\frac{49}{15} to both sides yields 515x=6015\frac{5}{15}x = \frac{60}{15}, which simplifies to 13x=4\frac{1}{3}x = 4, or x=12x = 12. Finally, substituting 12 into the expression 2x72x - 7 gives 2(12)7=172(12) - 7 = 17.

Adım Adım Çözüm

1
Distribute the coefficients to the terms inside the parentheses.
65x8523x53=15x+1115\frac{6}{5}x - \frac{8}{5} - \frac{2}{3}x - \frac{5}{3} = \frac{1}{5}x + \frac{11}{15}
To eliminate parentheses and allow grouping of like terms.
2
Combine the variable terms and the constant terms on the left side using a common denominator of 15.
815x4915=315x+1115\frac{8}{15}x - \frac{49}{15} = \frac{3}{15}x + \frac{11}{15}
To simplify the linear equation into a standard two-sided form.
3
Subtract the variable term from the right side and add the constant term from the left side.
515x=6015\frac{5}{15}x = \frac{60}{15}, which simplifies to x=12x = 12
To isolate the variable xx on one side of the equation.
4
Evaluate the expression 2x72x - 7 using the value of xx.
2(12)7=172(12) - 7 = 17
To solve for the final requested quantity.

Anahtar Kavram

Linear Equations in One Variable
Soru 46Soru

The table below shows some values of the linear function ff.

xxf(x)f(x)
221111
441717
662323

What is the yy-coordinate of the yy-intercept of the graph of y=f(x)y = f(x) in the xyxy-plane?

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Cevap: 5

Cevap

The correct answer is 5, representing the y-coordinate of the y-intercept of the graph of f.
To find the yy-intercept of the linear function, we first determine its slope using the points (2,11)(2, 11) and (4,17)(4, 17) from the table. The slope mm is 171142=62=3\frac{17 - 11}{4 - 2} = \frac{6}{2} = 3. Next, we use the slope-intercept equation f(x)=mx+bf(x) = mx + b. Substituting m=3m = 3 and the point (2,11)(2, 11) gives 11=3(2)+b11 = 3(2) + b, which simplifies to 11=6+b11 = 6 + b. Solving for bb yields 55. Therefore, the yy-coordinate of the yy-intercept of the graph of ff is 55.

Adım Adım Çözüm

1
Calculate the slope (mm) of the linear function using two coordinate pairs from the table.
The slope is m=3m = 3.
A linear function has a constant slope, which can be found using the formula m=f(x2)f(x1)x2x1m = \frac{f(x_2) - f(x_1)}{x_2 - x_1}.
2
Substitute the slope and one of the points into the slope-intercept equation f(x)=mx+bf(x) = mx + b to solve for the yy-intercept bb.
The yy-intercept bb is 55.
The yy-coordinate of the yy-intercept of the graph of y=f(x)y = f(x) is the value of bb in the equation f(x)=mx+bf(x) = mx + b.

Anahtar Kavram

Finding the y-intercept of a linear function from a table of values.
Tahmini Süre:45s
Soru 47Soru

In the xyxy-plane, line l1l_1 passes through the origin and has a positive slope. Line l2l_2 is perpendicular to l1l_1 and intersects the xx-axis at (d,0)(d, 0), where d>0d > 0. The two lines intersect at the point (a,b)(a, b) in the first quadrant. If the ratio of aa to bb is 33 to 44, and the area of the triangle bounded by l1l_1, l2l_2, and the xx-axis is AA, which of the following expressions represents dd in terms of AA?

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Cevap: 56A6\frac{5\sqrt{6A}}{6}

Cevap

The expression 56A6\frac{5\sqrt{6A}}{6} represents dd in terms of AA.
The correct expression is 56A6\frac{5\sqrt{6A}}{6}. The slope of line l1l_1 passing through the origin and (a,b)(a,b) is given by m1=bam_1 = \frac{b}{a}. Since the ratio of aa to bb is 33 to 44, we have ab=34\frac{a}{b} = \frac{3}{4}, which implies the slope m1=43m_1 = \frac{4}{3}. Because line l2l_2 is perpendicular to l1l_1, its slope is m2=34m_2 = -\frac{3}{4}. The equation of l2l_2 passing through (d,0)(d,0) is y=34(xd)y = -\frac{3}{4}(x - d). Solving the system of equations gives the intersection coordinates a=925da = \frac{9}{25}d and b=1225db = \frac{12}{25}d. The area of the triangle bounded by the two lines and the xx-axis is A=12×d×b=625d2A = \frac{1}{2} \times d \times b = \frac{6}{25}d^2. Solving for dd yields d=25A6=56A6d = \sqrt{\frac{25A}{6}} = \frac{5\sqrt{6A}}{6}.

Adım Adım Çözüm

1
Determine the slope and equation of line l1l_1.
Slope m1=43m_1 = \frac{4}{3}, and the equation of the line is y=43xy = \frac{4}{3}x.
Since l1l_1 passes through (0,0)(0,0) and the point (a,b)(a,b) in the first quadrant, its slope is m1=bam_1 = \frac{b}{a}. Since the ratio of aa to bb is 33 to 44, we have ab=34    ba=43\frac{a}{b} = \frac{3}{4} \implies \frac{b}{a} = \frac{4}{3}.
2
Determine the equation of line l2l_2.
The equation of the line is y=34(xd)y = -\frac{3}{4}(x - d).
Line l2l_2 is perpendicular to l1l_1, so its slope is the negative reciprocal of m1m_1, which is m2=34m_2 = -\frac{3}{4}. Using the point-slope form with the xx-intercept (d,0)(d,0), the equation is y0=34(xd)y - 0 = -\frac{3}{4}(x - d).
3
Find the coordinates of the intersection point (a,b)(a,b) in terms of dd.
a=925da = \frac{9}{25}d and b=1225db = \frac{12}{25}d.
Set the two equations equal to find the xx-coordinate of the intersection: 43x=34(xd)    43x=34x+34d    2512x=34d    x=925d\frac{4}{3}x = -\frac{3}{4}(x - d) \implies \frac{4}{3}x = -\frac{3}{4}x + \frac{3}{4}d \implies \frac{25}{12}x = \frac{3}{4}d \implies x = \frac{9}{25}d. Substituting this back into the equation of l1l_1 yields the yy-coordinate: y=43(925d)=1225dy = \frac{4}{3}\left(\frac{9}{25}d\right) = \frac{12}{25}d.
4
Express the area of the triangle in terms of dd.
A=625d2A = \frac{6}{25}d^2.
The base of the triangle along the xx-axis is dd (from x=0x=0 to x=dx=d). The height of the triangle is the yy-coordinate of the intersection point, b=1225db = \frac{12}{25}d. The area of the triangle is given by A=12×base×height=12d(1225d)=625d2A = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2}d\left(\frac{12}{25}d\right) = \frac{6}{25}d^2.
5
Solve for dd in terms of AA.
d=56A6d = \frac{5\sqrt{6A}}{6}.
Isolate d2d^2 to get d2=25A6d^2 = \frac{25A}{6}. Taking the square root of both sides gives d=25A6=5A6=56A6d = \sqrt{\frac{25A}{6}} = \frac{5\sqrt{A}}{\sqrt{6}} = \frac{5\sqrt{6A}}{6}.

Anahtar Kavram

Using the properties of perpendicular lines, setting up equations from coordinate parameters, and applying geometric formulas to relate parameters in linear systems.

Alternatif Yöntem

Using the geometric mean theorem (altitude rule) in a right triangle, the altitude bb divides the hypotenuse dd into segments aa and dad-a, such that b2=a(da)b^2 = a(d-a). Since b=43ab = \frac{4}{3}a, we can substitute this to find a=925da = \frac{9}{25}d and b=1225db = \frac{12}{25}d directly without finding the line equations. Then, A=12db=625d2A = \frac{1}{2} d b = \frac{6}{25}d^2, which solves to d=56A6d = \frac{5\sqrt{6A}}{6}.
Tahmini Süre:3m 0s
Soru 48Soru

In the xyxy-plane, the graph of the linear function ff is perpendicular to the line with equation 3x+4y=483x + 4y = 48. The graph of ff intersects the xx-axis at the point (p,0)(p, 0) and the yy-axis at the point (0,q)(0, q), where q>0q > 0. If the distance between the points (p,0)(p, 0) and (0,q)(0, q) is 1515, what is the value of qq?

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Cevap: 12

Cevap

12
First, find the slope of the given line by rewriting 3x+4y=483x + 4y = 48 in slope-intercept form: y=34x+12y = -\frac{3}{4}x + 12. The slope is 34-\frac{3}{4}. The graph of the linear function ff is perpendicular to this line, so its slope is the negative reciprocal, 43\frac{4}{3}. With a yy-intercept of (0,q)(0, q), the equation of ff is y=43x+qy = \frac{4}{3}x + q. Setting y=0y = 0 gives the xx-intercept (p,0)=(34q,0)(p, 0) = (-\frac{3}{4}q, 0). The distance between these intercepts is (34q)2+q2=2516q2=54q\sqrt{(-\frac{3}{4}q)^2 + q^2} = \sqrt{\frac{25}{16}q^2} = \frac{5}{4}q (since q>0q > 0). Given that the distance is 1515, we solve 54q=15\frac{5}{4}q = 15 to find q=12q = 12.

Adım Adım Çözüm

1
Find the slope of the line 3x+4y=483x + 4y = 48.
The slope of the line is 34-\frac{3}{4}.
To find the slope of the perpendicular line ff, we first need the slope of the given line. Rewriting 3x+4y=483x + 4y = 48 in slope-intercept form gives y=34x+12y = -\frac{3}{4}x + 12.
2
Determine the slope of ff.
The slope of ff is 43\frac{4}{3}.
Perpendicular lines have slopes that are negative reciprocals of each other.
3
Find the xx-intercept of ff in terms of qq.
The xx-intercept of ff is (34q,0)(-\frac{3}{4}q, 0).
Since the yy-intercept of ff is (0,q)(0, q), the equation of ff is y=43x+qy = \frac{4}{3}x + q. Setting y=0y = 0 gives 0=43x+q0 = \frac{4}{3}x + q, which simplifies to x=34qx = -\frac{3}{4}q.
4
Use the distance formula between the intercepts to solve for qq.
The value of qq is 1212.
The distance between (34q,0)(-\frac{3}{4}q, 0) and (0,q)(0, q) is (34q)2+q2=2516q2=54q\sqrt{(-\frac{3}{4}q)^2 + q^2} = \sqrt{\frac{25}{16}q^2} = \frac{5}{4}q since q>0q > 0. Setting this distance to 1515 gives 54q=15\frac{5}{4}q = 15, which yields q=12q = 12.

Anahtar Kavram

Properties of perpendicular lines, finding intercepts, and utilizing the distance formula in coordinate geometry.
Soru 49Soru

An online store charges a flat shipping fee of 8.508.50 dollars for orders under 100100 dollars. A customer purchases 55 identical shirts and uses a coupon for 12.0012.00 dollars off the total price of the shirts. If the total charge for the order, including shipping, is 86.5086.50 dollars, what is the price, in dollars, of one shirt?

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Cevap: 18.0018.00

Cevap

The price of one shirt is 18.0018.00 dollars.
To find the price of one shirt, we set up a linear equation. Let ss represent the price of one shirt. The cost of 55 shirts after applying the 12.0012.00 dollar coupon is 5s12.005s - 12.00. Since this amount is under 100100 dollars, the flat shipping fee of 8.508.50 dollars is added to the total. This gives the equation 5s12.00+8.50=86.505s - 12.00 + 8.50 = 86.50. Combining the constants on the left side results in 5s3.50=86.505s - 3.50 = 86.50. Adding 3.503.50 to both sides yields 5s=90.005s = 90.00. Dividing both sides by 55 gives s=18.00s = 18.00. Thus, the price of one shirt is 18.0018.00 dollars.

Adım Adım Çözüm

1
Represent the cost of the shirts using a variable.
Let ss represent the price of one shirt. The cost of 55 shirts with the 12.0012.00 dollar coupon discount is 5s12.005s - 12.00 dollars.
This establishes the variable for the unknown value we need to find.
2
Set up the full linear equation by including the shipping fee and total charge.
Since 5s12.005s - 12.00 is under 100100 dollars (which we verify at the end), a flat shipping fee of 8.508.50 dollars applies. The equation is 5s12.00+8.50=86.505s - 12.00 + 8.50 = 86.50.
This relates all parts of the word problem into a single solvable mathematical statement.
3
Simplify the equation by combining the constant values on the left side.
5s3.50=86.505s - 3.50 = 86.50
Combining like terms simplifies the algebraic expression.
4
Isolate the variable term by adding 3.503.50 to both sides.
5s=90.005s = 90.00
This moves all constant terms to one side of the equation.
5
Solve for the variable by dividing both sides of the equation by 55.
s=18.00s = 18.00
Dividing by the coefficient of the variable isolates ss to find the final value.

Anahtar Kavram

Linear Equations in One Variable
Soru 50Soru

In the xyxy-plane, the graph of a linear function ff has a yy-intercept of (0,r)(0, r) and an xx-intercept of (s,0)(s, 0), where rr and ss are nonzero constants. A second line, gg, is perpendicular to the graph of ff and passes through the point (s,r)(s, r). Which of the following expressions represents the xx-intercept of line gg?

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Cevap: s2r2s\frac{s^2 - r^2}{s}

Cevap

The expression s2r2s\frac{s^2 - r^2}{s}
The slope of line ff is found using its intercepts (0,r)(0, r) and (s,0)(s, 0), which gives a slope of mf=rsm_f = -\frac{r}{s}. Since line gg is perpendicular to line ff, its slope is the negative reciprocal, mg=srm_g = \frac{s}{r}. Using the point-slope form with the point (s,r)(s, r), the equation for line gg is yr=sr(xs)y - r = \frac{s}{r}(x - s). Setting y=0y = 0 to find the xx-intercept yields x=s2r2sx = \frac{s^2 - r^2}{s}.

Adım Adım Çözüm

1
Determine the slope of the linear function ff using its intercepts.
The slope of ff is mf=0rs0=rsm_f = \frac{0 - r}{s - 0} = -\frac{r}{s}.
The slope of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
2
Find the slope of line gg, which is perpendicular to the graph of ff.
The slope of line gg is mg=1mf=1r/s=srm_g = -\frac{1}{m_f} = -\frac{1}{-r/s} = \frac{s}{r}.
Perpendicular lines have slopes that are negative reciprocals of each other.
3
Write the equation of line gg in point-slope form using the point (s,r)(s, r).
The equation of line gg is yr=sr(xs)y - r = \frac{s}{r}(x - s).
The point-slope form of a linear equation is yy1=m(xx1)y - y_1 = m(x - x_1).
4
Solve for the xx-intercept of line gg by setting y=0y = 0.
Setting y=0y = 0 gives r=sr(xs)    r2s=xs    x=sr2s=s2r2s-r = \frac{s}{r}(x - s) \implies -\frac{r^2}{s} = x - s \implies x = s - \frac{r^2}{s} = \frac{s^2 - r^2}{s}.
The xx-intercept of a line is the value of xx when y=0y = 0.

Anahtar Kavram

Finding the equation of a perpendicular line and its intercepts using algebraic representations.
Soru 51Soru

If 3(2n5)=4n+93(2n - 5) = 4n + 9, what is the value of nn?

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Cevap: 12

Cevap

12
To solve the equation 3(2n5)=4n+93(2n - 5) = 4n + 9, we first distribute the 3 to the terms inside the parentheses to get 6n15=4n+96n - 15 = 4n + 9. Next, we subtract 4n4n from both sides to group the variable terms, giving 2n15=92n - 15 = 9. We then add 15 to both sides to isolate the variable term, resulting in 2n=242n = 24. Finally, dividing both sides by 2 gives the solution n=12n = 12.

Adım Adım Çözüm

1
Distribute 3 to the terms inside the parentheses.
6n15=4n+96n - 15 = 4n + 9
To simplify the left side of the equation and remove parentheses.
2
Subtract 4n4n from both sides of the equation.
2n15=92n - 15 = 9
To group the variable terms on one side of the equation.
3
Add 15 to both sides of the equation.
2n=242n = 24
To isolate the term with the variable nn.
4
Divide both sides of the equation by 2.
n=12n = 12
To solve for nn.

Anahtar Kavram

Solving a linear equation in one variable by applying the distributive property and isolating the variable.
Soru 52Soru

In the xyxy-plane, the graph of the linear function ff passes through the points (2,c)(-2, c) and (c,7)(c, 7), where cc is a constant. If the slope of the graph of ff is 12\frac{1}{2}, what is the value of cc?

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Cevap: 4

Cevap

The value of cc is 4.
Using the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} with the points (2,c)(-2, c) and (c,7)(c, 7) and the slope m=12m = \frac{1}{2} gives 7cc(2)=12\frac{7 - c}{c - (-2)} = \frac{1}{2}. Simplifying the denominator yields 7cc+2=12\frac{7 - c}{c + 2} = \frac{1}{2}. Cross-multiplying gives 2(7c)=c+22(7 - c) = c + 2, which expands to 142c=c+214 - 2c = c + 2. Adding 2c2c to both sides and subtracting 22 from both sides gives 12=3c12 = 3c. Dividing both sides by 33 gives c=4c = 4.

Adım Adım Çözüm

1
Set up the slope formula for the line passing through (2,c)(-2, c) and (c,7)(c, 7).
m=7cc(2)m = \frac{7 - c}{c - (-2)}
The slope of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
2
Substitute the given slope m=12m = \frac{1}{2} into the formula and simplify the denominator.
7cc+2=12\frac{7 - c}{c + 2} = \frac{1}{2}
We are given that the slope of the line is 12\frac{1}{2}.
3
Solve the equation for cc by cross-multiplying and isolating the variable.
2(7c)=c+2    142c=c+2    12=3c    c=42(7 - c) = c + 2 \implies 14 - 2c = c + 2 \implies 12 = 3c \implies c = 4
Cross-multiplying eliminates the fractions, allowing us to solve the linear equation for cc.

Anahtar Kavram

Finding the slope of a line given two points containing an unknown coordinate
Soru 53Soru

Consider the system of equations below.

x=2yx = 2y
3xy=103x - y = 10

If (x,y)(x, y) is the solution to the system of equations above, what is the value of xx?

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Cevap: 4

Cevap

The value of xx is 44.
The system of equations can be solved by substituting x=2yx = 2y from the first equation into the second equation, which gives 3(2y)y=103(2y) - y = 10. Simplifying this equation yields 6yy=106y - y = 10, or 5y=105y = 10. Dividing by 55 gives y=2y = 2. Substituting y=2y = 2 back into the first equation yields x=2(2)=4x = 2(2) = 4. Therefore, the value of xx is 44.

Adım Adım Çözüm

1
Substitute the expression for xx from the first equation into the second equation.
3(2y)y=103(2y) - y = 10
Since the first equation gives xx in terms of yy, substituting it into the second equation reduces the system to a single linear equation in one variable.
2
Solve the resulting equation for yy.
y=2y = 2
Simplifying 3(2y)y=103(2y) - y = 10 yields 6yy=106y - y = 10, which simplifies further to 5y=105y = 10. Dividing both sides by 55 gives y=2y = 2.
3
Substitute the value of yy back into the first equation to solve for xx.
x=4x = 4
Using x=2yx = 2y and substituting y=2y = 2 gives x=2(2)=4x = 2(2) = 4.

Anahtar Kavram

Solving systems of linear equations using the substitution method.
Soru 54Soru
In the equation below, aa and bb are positive constants.
23(32xa)34(8bx)=52(x3)12\frac{2}{3} \left( \frac{3}{2}x - a \right) - \frac{3}{4} \left( 8 - bx \right) = \frac{5}{2}(x - 3) - \frac{1}{2}
If the equation has infinitely many solutions, what is the value of aba^b?
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Cevap: 9

Cevap

The correct answer is 9.
The correct answer is 9. Expanding the left side of the equation yields (1+34b)x(6+23a)\left(1 + \frac{3}{4}b\right)x - \left(6 + \frac{2}{3}a\right), and simplifying the right side yields 52x8\frac{5}{2}x - 8. For the linear equation to have infinitely many solutions, the coefficient of xx on the left, 1+34b1 + \frac{3}{4}b, must equal the coefficient of xx on the right, 52\frac{5}{2}, which gives b=2b = 2. Similarly, the constant term on the left, (6+23a)-\left(6 + \frac{2}{3}a\right), must equal the constant term on the right, 8-8, which simplifies to 6+23a=86 + \frac{2}{3}a = 8 and gives a=3a = 3. Evaluating aba^b with these values yields 32=93^2 = 9.

Adım Adım Çözüm

1
Expand both sides of the equation to collect like terms.
(1+34b)x(6+23a)=52x8\left( 1 + \frac{3}{4}b \right)x - \left( 6 + \frac{2}{3}a \right) = \frac{5}{2}x - 8
Expanding allows us to compare the coefficient of xx and the constant term on each side of the equation.
2
Equate the coefficients of xx on both sides of the equation.
1+34b=52    b=21 + \frac{3}{4}b = \frac{5}{2} \implies b = 2
For a linear equation to have infinitely many solutions, the coefficient of xx must be identical on both sides.
3
Equate the constant terms on both sides of the equation.
(6+23a)=8    a=3-\left( 6 + \frac{2}{3}a \right) = -8 \implies a = 3
For a linear equation to have infinitely many solutions, the constant terms must also be identical on both sides.
4
Calculate the value of aba^b using the solved values of aa and bb.
32=93^2 = 9
The question asks for the value of the expression aba^b where a=3a = 3 and b=2b = 2.

Anahtar Kavram

A linear equation in one variable of the form Ax+B=Cx+DAx + B = Cx + D has infinitely many solutions if and only if A=CA = C and B=DB = D.

Alternatif Yöntem

Since the equation must hold for all values of xx if it has infinitely many solutions, you can substitute convenient values for xx to solve for aa and bb directly. Substituting x=0x = 0 simplifies the equation to 23a6=8-\frac{2}{3}a - 6 = -8, which quickly yields a=3a = 3. Then, substituting x=2x = 2 and a=3a = 3 simplifies the equation to 34(82b)=3-\frac{3}{4}(8 - 2b) = -3, which yields b=2b = 2. Calculating aba^b gives 32=93^2 = 9.
Tahmini Süre:3m 0s
Soru 55Soru

If 53(3x6)12(4x+8)=2\frac{5}{3}(3x - 6) - \frac{1}{2}(4x + 8) = 2, what is the value of 3x53x - 5?

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Cevap: 11

Cevap

11
Distributing the fraction 53\frac{5}{3} to (3x6)(3x - 6) yields 5x105x - 10. Distributing the term 12-\frac{1}{2} to (4x+8)(4x + 8) yields 2x4-2x - 4. Combining these results gives (5x2x)+(104)=2(5x - 2x) + (-10 - 4) = 2, which simplifies to 3x14=23x - 14 = 2. Adding 14 to both sides yields 3x=163x = 16. Finally, subtracting 5 from both sides of this equation gives 3x5=113x - 5 = 11.

Adım Adım Çözüm

1
Distribute 53\frac{5}{3} and 12-\frac{1}{2} to the terms within their respective parentheses.
5x102x4=25x - 10 - 2x - 4 = 2
This removes the parentheses and allows us to group terms.
2
Combine the variable terms and the constant terms on the left side of the equation.
3x14=23x - 14 = 2
Simplifying the expression on the left side makes it easier to solve.
3
Add 14 to both sides of the equation to isolate the term 3x3x.
3x=163x = 16
Since the question asks for the value of 3x53x - 5, isolating 3x3x allows direct evaluation.
4
Subtract 5 from both sides of the equation 3x=163x = 16.
3x5=113x - 5 = 11
This directly yields the required value without needing to compute the fractional value of xx first.

Anahtar Kavram

Solving linear equations in one variable by distribution, combining like terms, and evaluating expressions.
Tahmini Süre:1m 30s
Soru 56Soru

In the xyxy-plane, the graph of a linear function ff has a positive yy-intercept and a positive xx-intercept. The area of the triangular region in the first quadrant bounded by the graph of ff and the coordinate axes is 3636. If the graph of ff passes through the point (4,4)(4, 4) and has a slope less than 1-1, what is the yy-coordinate of the yy-intercept of the graph of ff?

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Cevap: 12

Cevap

The yy-coordinate of the yy-intercept of the graph of ff is 1212.
The correct answer is 1212 because the system of equations derived from the area constraint (qr=72qr = 72) and the point constraint (q+r=18q+r=18) yields two possible values for the yy-intercept: 66 or 1212. The condition that the slope must be less than 1-1 means that the line must be steeper than a slope of 1-1, which requires the yy-intercept to be larger than the xx-intercept (r>qr > q). Thus, the yy-intercept is 1212.

Adım Adım Çözüm

1
Express the equation of the line using intercept form.
xq+yr=1\frac{x}{q} + \frac{y}{r} = 1, where q>0q > 0 is the xx-intercept and r>0r > 0 is the yy-intercept.
Since the line intersects the positive axes, this form directly relates the intercepts to the coordinates of points on the line.
2
Use the area of the triangle to find a relationship between qq and rr.
qr=72qr = 72
The area of the right triangle formed by the axes and the intercepts is given by Area=12×base×height=12qr=36\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2}qr = 36.
3
Substitute the point (4,4)(4, 4) into the equation of the line and simplify using the area relationship.
q+r=18q + r = 18
Plugging in x=4x = 4 and y=4y = 4 yields 4q+4r=1    4(q+r)=qr\frac{4}{q} + \frac{4}{r} = 1 \implies 4(q + r) = qr. Substituting qr=72qr = 72 gives 4(q+r)=72    q+r=184(q + r) = 72 \implies q + r = 18.
4
Solve the system of equations q+r=18q + r = 18 and qr=72qr = 72.
(q,r)=(6,12)(q, r) = (6, 12) or (q,r)=(12,6)(q, r) = (12, 6)
Substituting r=18qr = 18 - q into qr=72qr = 72 yields q(18q)=72    q218q+72=0    (q6)(q12)=0q(18 - q) = 72 \implies q^2 - 18q + 72 = 0 \implies (q - 6)(q - 12) = 0.
5
Apply the slope condition to determine the unique value of rr.
r=12r = 12
The slope of the line is m=rqm = -\frac{r}{q}. If q=12q = 12 and r=6r = 6, then m=0.5m = -0.5, which is not less than 1-1. If q=6q = 6 and r=12r = 12, then m=2m = -2, which is less than 1-1. Thus, r=12r = 12 is the correct yy-intercept.

Anahtar Kavram

Using intercepts and area to determine the equation of a linear function under constraints.
Soru 57Soru

In the equation 3(2xa)4(x+1)=2x+53(2x - a) - 4(x + 1) = 2x + 5, aa is a constant. If the equation has infinitely many solutions, what is the value of aa?

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Cevap: 3-3

Cevap

The value of aa must be 3-3.
The value of 3-3 is correct. Expanding and simplifying the left side of the equation yields 2x3a4=2x+52x - 3a - 4 = 2x + 5. For a linear equation to have infinitely many solutions, the constant terms on both sides must be identical. Setting 3a4=5-3a - 4 = 5 and solving for aa gives 3a=9-3a = 9, which simplifies to a=3a = -3.

Adım Adım Çözüm

1
Distribute the coefficients to the terms inside the parentheses on the left side of the equation.
6x3a4x4=2x+56x - 3a - 4x - 4 = 2x + 5
Distributing eliminates the parentheses, allowing like terms to be combined.
2
Combine the variable terms on the left side of the equation.
2x3a4=2x+52x - 3a - 4 = 2x + 5
Grouping the xx terms (6x4x=2x6x - 4x = 2x) simplifies the structure of the equation.
3
Set up the condition for the equation to have infinitely many solutions.
3a4=5-3a - 4 = 5
For a linear equation to have infinitely many solutions, the coefficients of xx on both sides must be equal, and the constant terms must also be equal. The xx coefficients are already equal (2=22 = 2), so we equate the constants.
4
Isolate the constant aa by adding 44 to both sides and then dividing by 3-3.
a=3a = -3
Adding 44 yields 3a=9-3a = 9, and dividing by 3-3 isolates the variable to find the solution.

Anahtar Kavram

Linear Equations in One Variable

Alternatif Yöntem

Instead of fully simplifying the equation, substitute x=0x = 0 directly into the original equation, since a statement with infinitely many solutions must hold true for all values of xx. Substituting x=0x = 0 gives 3(a)4(1)=53(-a) - 4(1) = 5, which simplifies directly to 3a4=5-3a - 4 = 5, yielding a=3a = -3.
Tahmini Süre:1m 15s
Soru 58Soru

The table below shows some values of xx and the corresponding values of f(x)f(x) for a linear function ff.

xxf(x)f(x)
37
612
917

What is the value of f(15)f(15)?

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Cevap: 27

Cevap

The value of the linear function evaluated at 15 is 27.
To find f(15)f(15) for the linear function, we determine its constant rate of change. Using points (3,7)(3, 7) and (6,12)(6, 12), the change in f(x)f(x) is 127=512 - 7 = 5 for a change in xx of 63=36 - 3 = 3. This gives a slope of 53\frac{5}{3}. Using point-slope form with (3,7)(3, 7) gives the equation f(x)7=53(x3)f(x) - 7 = \frac{5}{3}(x - 3), which simplifies to f(x)=53x+2f(x) = \frac{5}{3}x + 2. Substituting x=15x = 15 yields f(15)=53(15)+2=25+2=27f(15) = \frac{5}{3}(15) + 2 = 25 + 2 = 27. Alternatively, since xx increases by 6 from 9 to 15, which is twice the step size of 3, the value of f(x)f(x) must increase by 2×5=102 \times 5 = 10 from 1717, resulting in 17+10=2717 + 10 = 27.

Adım Adım Çözüm

1
Calculate the slope of the linear function
slope m=53m = \frac{5}{3}
Linear functions have a constant rate of change, which is the slope.
2
Determine the equation of the function
f(x)=53x+2f(x) = \frac{5}{3}x + 2
Using the slope and one point from the table helps define the function for all inputs.
3
Evaluate the function at x=15x = 15
f(15)=27f(15) = 27
Substitute the given input value into the function equation to find the corresponding output value.

Anahtar Kavram

Linear Functions and Graphs
Soru 59Soru

The variables xx and yy satisfy the system of equations below.

y=102xy = 10 - 2x
3xy=53x - y = 5

What is the value of xx?

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Cevap: 3

Cevap

3
Substituting the expression for yy from the first equation, 102x10 - 2x, into the second equation yields 3x(102x)=53x - (10 - 2x) = 5. Distributing the negative sign results in 3x10+2x=53x - 10 + 2x = 5. Combining the like terms of xx gives 5x10=55x - 10 = 5. Adding 10 to both sides of the equation results in 5x=155x = 15. Finally, dividing both sides by 5 gives x=3x = 3.

Adım Adım Çözüm

1
Substitute the expression for yy from the first equation into the second equation.
3x(102x)=53x - (10 - 2x) = 5
To eliminate the variable yy and obtain a single linear equation in terms of xx.
2
Distribute the negative sign through the parentheses and combine like terms.
3x10+2x=53x - 10 + 2x = 5, which simplifies to 5x10=55x - 10 = 5
To simplify the linear equation before isolating the variable.
3
Isolate the variable xx by adding 10 to both sides and then dividing by 5.
5x=155x = 15, which gives x=3x = 3
To determine the value of xx.

Anahtar Kavram

Solving systems of linear equations using substitution
Tahmini Süre:45s
Soru 60Soru

In the system of equations below, what is the value of xx?

3xy=73x - y = 7
x+y=5x + y = 5
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Cevap: 3

Cevap

The value of xx is 33.
Adding the two equations eliminates yy, resulting in 4x=124x = 12. Dividing by 44 gives x=3x = 3.

Adım Adım Çözüm

1
Add the two equations to eliminate yy.
4x=124x = 12
Adding the equations (3xy)+(x+y)=7+5(3x - y) + (x + y) = 7 + 5 eliminates yy because y+y=0-y + y = 0.
2
Solve for xx.
x=3x = 3
Divide both sides of the equation 4x=124x = 12 by 44.

Anahtar Kavram

Solving a system of linear equations by elimination.
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Algebra Alıştırma Soruları — SAT — Sayfa 3 | Examkin