Interpreting Linear Relationships in Context

70 soru

Soru 21Soru

At a municipal water desalination facility, the filtration rate of a reverse osmosis membrane decreases linearly over time due to particle accumulation. The daily volume of purified water, VV, in thousands of gallons per day, can be modeled as a function of the number of days, tt, since the membrane was last serviced. The graph of this relationship in the tVtV-plane has a tt-intercept of 100100 and passes through the point (20,64)(20, 64). Which of the following is the best interpretation of the slope of the graph of this relationship?

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Cevap: The daily volume of purified water decreases by 0.80.8 thousand gallons each day after the membrane is serviced.

Cevap

The daily volume of purified water decreases by 0.80.8 thousand gallons each day after the membrane is serviced.
The correct answer describes that the daily volume of purified water decreases by 0.80.8 thousand gallons each day. The tt-intercept of 100100 indicates the point (100,0)(100, 0) is on the graph, and the problem states the graph passes through (20,64)(20, 64). The slope of the relationship is m=06410020=0.8m = \frac{0 - 64}{100 - 20} = -0.8. Since the vertical axis represents the daily volume of purified water (in thousands of gallons) and the horizontal axis represents the number of days, the slope of 0.8-0.8 represents a decrease of 0.80.8 thousand gallons of water per day.

Adım Adım Çözüm

1
Identify the coordinates of two points on the line from the given context.
The tt-intercept of 100100 corresponds to the point (100,0)(100, 0). The second point is given directly as (20,64)(20, 64).
Two points on the line are needed to calculate the slope of the linear relationship.
2
Calculate the slope (mm) using the slope formula m=V2V1t2t1m = \frac{V_2 - V_1}{t_2 - t_1}.
m=06410020=6480=0.8m = \frac{0 - 64}{100 - 20} = \frac{-64}{80} = -0.8.
The slope of the line represents the rate of change of the daily volume of water (VV) with respect to the elapsed days (tt).
3
Interpret the meaning of the slope in context.
A slope of 0.8-0.8 indicates that for every increase of 11 day in tt, the daily volume of water VV decreases by 0.80.8 units (thousands of gallons).
The slope value of 0.8-0.8 represents a daily reduction of 0.80.8 thousand gallons of purified water.

Anahtar Kavram

Interpreting the slope of a linear model in a real-world context

Alternatif Yöntem

Instead of calculating the slope directly from the formula, one can write the equation of the line in point-slope form or slope-intercept form. Since (100,0)(100,0) is the tt-intercept, the line can be represented as V=m(t100)V = m(t - 100). Substituting the point (20,64)(20, 64) gives 64=m(20100)64 = m(20 - 100), which simplifies to 64=80m64 = -80m, solving to m=0.8m = -0.8. This slope represents the daily change in the volume VV for each unit change in day tt.
Tahmini Süre:2m 30s
Soru 22Soru

For a wireless sensor node in an environmental monitoring network, the battery life BB, in days, when transmitting nn data packets per day is modeled by a linear function. Under standard operating conditions, the node's battery lasts for 120120 days when transmitting 8080 packets per day, and it lasts for 9090 days when transmitting 140140 packets per day. Under a new energy-saving firmware, the battery consumption rate per packet transmitted is reduced by 40%40\%, and the static power draw is also reduced, increasing the maximum battery life (when zero packets are transmitted) by 10%10\%. Under this new firmware, what is the battery life, in days, of a sensor node that transmits 150150 data packets per day?

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Cevap: 131

Cevap

131
To solve this problem, we first determine the linear relationship B=mn+B0B = mn + B_0 under standard operating conditions. The rate of change (slope mm) represents the change in battery life per packet transmitted per day: m=9012014080=0.5m = \frac{90 - 120}{140 - 80} = -0.5 days per packet. Substituting this back into the linear equation gives 120=0.5(80)+B0120 = -0.5(80) + B_0, which simplifies to 120=40+B0120 = -40 + B_0, yielding a y-intercept of B0=160B_0 = 160 days. Under the energy-saving firmware, the battery consumption rate per packet is reduced by 40%40\%. This means the rate at which battery life decreases per packet changes from 0.50.5 to 0.5×(10.40)=0.30.5 \times (1 - 0.40) = 0.3, giving us a new slope of 0.3-0.3. The maximum battery life (y-intercept) increases by 10%10\%, making the new y-intercept 160×1.10=176160 \times 1.10 = 176. The new linear model is Bnew=0.3n+176B_{\text{new}} = -0.3n + 176. Evaluating this equation for n=150n = 150 packets per day yields Bnew=0.3(150)+176=45+176=131B_{\text{new}} = -0.3(150) + 176 = -45 + 176 = 131 days.

Adım Adım Çözüm

1
Determine the linear relationship representing standard operating conditions by using the two given points, (80,120)(80, 120) and (140,90)(140, 90).
Slope m=0.5m = -0.5 days per packet and y-intercept B0=160B_0 = 160 days.
Establishing the initial linear equation is necessary to obtain the base battery consumption rate and maximum battery capacity.
2
Calculate the new slope and y-intercept parameters under the energy-saving firmware by applying the specified percentage changes.
New slope mnew=0.3m_{\text{new}} = -0.3 days per packet and new y-intercept B0,new=176B_{0,\text{new}} = 176 days.
To model the linear relationship under the updated power management firmware.
3
Formulate the new linear function Bnew=0.3n+176B_{\text{new}} = -0.3n + 176 and substitute 150150 for nn.
Battery life B=131B = 131 days.
To find the expected battery life at the target daily packet transmission rate.

Anahtar Kavram

Interpreting how physical rates and initial values map to the slope and y-intercept of a linear model, and applying transformations to these parameters.
Soru 23Soru

A moving company uses the equation C=2.5d+75C = 2.5d + 75 to determine the total charge CC, in dollars, for renting a small truck and driving it dd miles. According to the relationship, what is the charge, in dollars, for each mile the truck is driven?

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Cevap: 2.5

Cevap

The charge for each mile the truck is driven is 2.5 dollars.
In the linear model C=2.5d+75C = 2.5d + 75, the total cost CC is a function of the number of miles driven dd. The rate of change of this function represents the cost per mile driven. In the equation, this rate of change is the coefficient of dd, which is 2.5. Therefore, the charge for each mile the truck is driven is 2.5 dollars.

Adım Adım Çözüm

1
Analyze the linear equation C=2.5d+75C = 2.5d + 75 to determine the relationship between variables.
The total charge CC depends on the number of miles dd driven, with a rate of change of 2.5 dollars per mile and a base fee of 75 dollars.
Understanding the components of a linear equation helps isolate the rate of change.
2
Identify the coefficient of the independent variable dd.
The coefficient of dd is 2.5.
In a linear equation of the form y=mx+by = mx + b, the coefficient of the independent variable represents the rate of change.
3
Interpret the meaning of this coefficient in the context of the problem.
The coefficient 2.5 represents the cost, in dollars, incurred per mile driven.
The question asks for the charge per mile, which corresponds to the rate of change.

Anahtar Kavram

Interpreting Linear Relationships in Context
Soru 24Soru

A commercial cargo aircraft's total weight WW, in kilograms, is modeled as a linear function of the volume of fuel FF, in liters, in its fuel tanks. The equation modeling this relationship is:

W=0.8F+74,000W = 0.8F + 74,000

To comply with runway safety regulations at a destination airport, the aircraft's total weight must not exceed 85,00085,000 kilograms upon landing. The aircraft takes off with 18,00018,000 liters of fuel and consumes fuel at a constant rate of 1,7001,700 liters per hour of flight. What is the minimum number of hours the aircraft must fly before it can safely land?

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Cevap: 2.5

Cevap

The minimum number of hours the aircraft must fly is 2.5.
To satisfy runway safety regulations, the aircraft's weight must be at most 85,00085,000 kg. According to the weight model W=0.8F+74,000W = 0.8F + 74,000, we set 0.8F+74,00085,0000.8F + 74,000 \leq 85,000, which simplifies to 0.8F11,0000.8F \leq 11,000. Dividing by the density coefficient 0.80.8 yields F13,750F \leq 13,750 liters as the maximum amount of fuel the aircraft can contain at landing. Since the aircraft takes off with 18,00018,000 liters of fuel and consumes 1,7001,700 liters per hour, the fuel remaining after tt hours is 18,0001,700t18,000 - 1,700t. To ensure the remaining fuel is less than or equal to 13,75013,750 liters, we solve 18,0001,700t13,75018,000 - 1,700t \leq 13,750, which simplifies to 4,2501,700t4,250 \leq 1,700t, or t2.5t \geq 2.5 hours. Therefore, the minimum duration of the flight is 2.5 hours.

Adım Adım Çözüm

1
Formulate the weight limit inequality using the linear relationship.
0.8F+74,00085,0000.8F + 74,000 \leq 85,000
The aircraft's weight WW is given by 0.8F+74,0000.8F + 74,000, where 0.80.8 represents the density of the fuel in kg/L and 74,00074,000 represents the weight of the empty aircraft and its cargo. This total weight must not exceed 85,00085,000 kg.
2
Calculate the maximum fuel capacity allowed at landing by solving the inequality.
F13,750F \leq 13,750
Subtracting 74,00074,000 from both sides yields 0.8F11,0000.8F \leq 11,000. Dividing by 0.80.8 gives F13,750F \leq 13,750 liters as the fuel ceiling for landing.
3
Use the fuel consumption rate to find the minimum flight time.
t2.5t \geq 2.5
With an initial fuel volume of 18,00018,000 liters and a burn rate of 1,7001,700 liters/hour, the fuel remaining after tt hours is 18,0001,700t18,000 - 1,700t. Setting this expression to be at most 13,75013,750 liters yields 18,0001,700t13,75018,000 - 1,700t \leq 13,750. Subtracting 18,00018,000 gives 1,700t4,250-1,700t \leq -4,250, and dividing by 1,700-1,700 results in t2.5t \geq 2.5 hours.

Anahtar Kavram

Interpreting linear coefficients in context and setting up linear inequalities with rates to model real-world constraints.
Tahmini Süre:2m 30s
Soru 25Soru

At a local coffee shop, the remaining weight of coffee beans CC, in pounds, after preparing nn cups of espresso is modeled by the equation C=800.04nC = 80 - 0.04n. What is the best interpretation of the number 0.040.04 in this context?

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Cevap: The weight of coffee beans, in pounds, used to prepare each cup of espresso

Cevap

The weight of coffee beans, in pounds, used to prepare each cup of espresso
The correct answer is the option stating that 0.040.04 is the weight of coffee beans, in pounds, used to prepare each cup of espresso. In the linear relationship C=800.04nC = 80 - 0.04n, the slope is 0.04-0.04, which represents the rate of change of the remaining weight of coffee beans with respect to the number of cups of espresso prepared. A rate of 0.04-0.04 pounds per cup means that for every cup prepared, the remaining coffee beans decrease by 0.040.04 pounds, indicating that 0.040.04 pounds of beans are consumed per cup.

Adım Adım Çözüm

1
Analyze the structure of the linear equation C=800.04nC = 80 - 0.04n.
The equation is in the slope-intercept form y=mx+by = mx + b, where the dependent variable is CC (remaining coffee beans in pounds), the independent variable is nn (number of cups of espresso), the constant (y-intercept) is 8080, and the slope (coefficient of nn) is 0.04-0.04.
Identifying the components of the linear equation helps in assigning their real-world contextual meanings.
2
Interpret the meaning of the slope in the context of the variables.
The slope of 0.04-0.04 represents the change in the remaining coffee beans (CC) for every 11-unit increase in the number of cups of espresso (nn). This means the remaining weight decreases by 0.040.04 pounds per cup.
The slope of a linear model shows the constant rate of change of the dependent variable per unit of the independent variable.
3
Relate the rate of decrease to the options.
A decrease of 0.040.04 pounds of remaining beans per cup of espresso means that 0.040.04 pounds of coffee beans are used to prepare each cup of espresso.
Translating the decrease rate into consumption rate matches the physical scenario described.

Anahtar Kavram

Interpreting Linear Relationships in Context
Tahmini Süre:45s
Soru 26Soru

A local gym charges a one-time registration fee plus a constant monthly fee. The total cost, CC, in dollars, for a membership of mm months is modeled by the equation C=35m+50C = 35m + 50. What is the one-time registration fee, in dollars, for the gym?

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Cevap: 50

Cevap

The one-time registration fee is 50 dollars.
In the linear model C=35m+50C = 35m + 50, the constant term 5050 represents the value of the function when m=0m = 0. In this context, m=0m = 0 corresponds to 00 months of membership, meaning no monthly fees have been incurred yet. Therefore, the value of 5050 represents the initial, one-time registration fee.

Adım Adım Çözüm

1
Analyze the linear equation C=35m+50C = 35m + 50 to identify the slope and the y-intercept.
The slope is 3535 (the coefficient of mm) and the y-intercept is 5050 (the constant term).
In a linear equation of the form y=mx+by = mx + b, the constant bb represents the value of yy when x=0x = 0 (the y-intercept), and the coefficient mm represents the rate of change (the slope).
2
Interpret the meaning of the y-intercept in the given context.
At m=0m = 0 months, the total cost CC is C=35(0)+50=50C = 35(0) + 50 = 50 dollars.
The cost at 00 months represents the upfront, one-time fee before any monthly fees are added, which is the registration fee.

Anahtar Kavram

Interpreting the y-intercept of a linear function in a real-world context.
Soru 27Soru

A deep-sea research submersible's internal cabin pressure, PP, in atmospheres (atm\text{atm}), is modeled by a linear function of its depth below the ocean surface, dd, in meters. At the surface (d=0d = 0), the internal pressure is 1.0 atm1.0\text{ atm}. For every increase in depth of 100 meters100\text{ meters}, the internal pressure increases by 0.05 atm0.05\text{ atm}. The submersible descends from the surface at a constant rate of 2.5 meters per second2.5\text{ meters per second}. What is the rate of increase of the internal cabin pressure, in atm\text{atm} per hour, as the submersible descends?

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Cevap: 4.5

Cevap

The rate of increase of the internal cabin pressure is 4.54.5 atmospheres per hour.
The rate of change of internal pressure with depth is 0.05 atm100 m=0.0005 atm/m\frac{0.05\text{ atm}}{100\text{ m}} = 0.0005\text{ atm/m}. Since the submersible descends at a rate of 2.5 m/s2.5\text{ m/s}, we convert this rate of depth change to hours: 2.5 m/s×3600 s/hr=9000 m/hr2.5\text{ m/s} \times 3600\text{ s/hr} = 9000\text{ m/hr}. Multiplying the pressure change per meter by the depth change per hour gives the rate of change of the internal pressure per hour: 0.0005 atm/m×9000 m/hr=4.5 atm/hr0.0005\text{ atm/m} \times 9000\text{ m/hr} = 4.5\text{ atm/hr}.

Adım Adım Çözüm

1
Calculate the rate of pressure increase per meter of depth.
0.0005 atm/m0.0005\text{ atm/m}
The pressure increases by 0.05 atm0.05\text{ atm} for every 100 meters100\text{ meters} of depth, giving a rate of change of 0.05 atm100 m=0.0005 atm/m\frac{0.05\text{ atm}}{100\text{ m}} = 0.0005\text{ atm/m}.
2
Determine the distance descended by the submersible in one hour.
9000 meters9000\text{ meters}
With 3600 seconds3600\text{ seconds} in one hour and a descent speed of 2.5 m/s2.5\text{ m/s}, the submersible descends a total of 2.5 m/s×3600 s=9000 meters2.5\text{ m/s} \times 3600\text{ s} = 9000\text{ meters} in one hour.
3
Calculate the rate of internal pressure increase per hour.
4.5 atm/hr4.5\text{ atm/hr}
Multiply the rate of change of pressure per meter (0.0005 atm/m0.0005\text{ atm/m}) by the hourly descent distance (9000 m9000\text{ m}) to obtain 0.0005×9000=4.5 atm/hr0.0005 \times 9000 = 4.5\text{ atm/hr}.

Anahtar Kavram

Interpreting Linear Relationships in Context

Alternatif Yöntem

Write the cabin pressure as a function of time tt, in seconds: P(t)=1.0+0.0005(2.5t)=1.0+0.00125tP(t) = 1.0 + 0.0005(2.5t) = 1.0 + 0.00125t. The slope of this line, 0.00125 atm/s0.00125\text{ atm/s}, represents the rate of increase per second. To convert this rate to hours, multiply by 3600 seconds/hour3600\text{ seconds/hour}: 0.00125×3600=4.5 atm/hr0.00125 \times 3600 = 4.5\text{ atm/hr}.
Tahmini Süre:2m 0s
Soru 28Soru

A geophysicist models the temperature, TT, in degrees Celsius (C^\circ\text{C}), of a rock layer during a deep-crust drilling project using a linear function of the depth, dd, in kilometers (km\text{km}), below the surface. According to the model, for every increase in depth of 0.8 km0.8\text{ km}, the temperature of the rock increases by 22C22^\circ\text{C}. At a depth of 2.4 km2.4\text{ km}, the temperature of the rock is 81C81^\circ\text{C}. According to the model, at what depth, in kilometers, will the temperature of the rock be 114C114^\circ\text{C}?

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Cevap: 3.6

Cevap

The temperature of the rock will reach 114C114^\circ\text{C} at a depth of 3.63.6 kilometers.
The correct answer is 3.63.6. The rate of change of temperature with depth is 22C0.8 km=27.5C/km\frac{22^\circ\text{C}}{0.8\text{ km}} = 27.5^\circ\text{C/km}. The linear relationship between temperature TT and depth dd can be modeled by T=27.5d+T0T = 27.5d + T_0, where T0T_0 is the temperature at the surface. Substituting the known values d=2.4d = 2.4 and T=81T = 81 into the model gives 81=27.5(2.4)+T081 = 27.5(2.4) + T_0, which simplifies to 81=66+T081 = 66 + T_0. Solving for T0T_0 yields T0=15T_0 = 15. Thus, the model is T=27.5d+15T = 27.5d + 15. To find the depth when the temperature is 114C114^\circ\text{C}, substitute T=114T = 114 into the model: 114=27.5d+15114 = 27.5d + 15. Subtracting 1515 from both sides gives 99=27.5d99 = 27.5d, and dividing by 27.527.5 yields d=3.6d = 3.6.

Adım Adım Çözüm

1
Find the rate of change (slope) of the temperature with respect to depth.
The slope is 27.5C/km27.5^\circ\text{C/km}.
The temperature increases by 22C22^\circ\text{C} for every 0.8 km0.8\text{ km} of depth, so the rate of change is 22C0.8 km=27.5C/km\frac{22^\circ\text{C}}{0.8\text{ km}} = 27.5^\circ\text{C/km}.
2
Set up a linear model and find the surface temperature (y-intercept).
The linear model is T=27.5d+15T = 27.5d + 15.
Using the slope-intercept form T=md+T0T = md + T_0 and substituting the given values d=2.4d = 2.4 and T=81T = 81 gives 81=27.5(2.4)+T081 = 27.5(2.4) + T_0, which simplifies to 81=66+T081 = 66 + T_0, so T0=15T_0 = 15.
3
Substitute the target temperature into the linear model and solve for the target depth.
d=3.6d = 3.6
Substitute T=114T = 114 into the equation T=27.5d+15T = 27.5d + 15 to get 114=27.5d+15114 = 27.5d + 15. Subtracting 1515 from both sides gives 99=27.5d99 = 27.5d. Dividing both sides by 27.527.5 yields d=3.6d = 3.6.

Anahtar Kavram

Interpreting slope and solving for values in a linear relationship context.

Alternatif Yöntem

Find the required temperature increase: 114C81C=33C114^\circ\text{C} - 81^\circ\text{C} = 33^\circ\text{C}. Set up a proportion using the rate of 22C22^\circ\text{C} increase per 0.8 km0.8\text{ km} to find the change in depth Δd\Delta d: 33CΔd=22C0.8 km    Δd=33×0.822=1.2 km\frac{33^\circ\text{C}}{\Delta d} = \frac{22^\circ\text{C}}{0.8\text{ km}} \implies \Delta d = \frac{33 \times 0.8}{22} = 1.2\text{ km}. Add this change in depth to the initial depth to find the final depth: 2.4+1.2=3.6 km2.4 + 1.2 = 3.6\text{ km}.
Tahmini Süre:2m 0s
Soru 29Soru

An IT administrator uses the equation T=0.06r+40T = 0.06r + 40 to model the total time TT, in milliseconds, required to retrieve rr records from a cloud database. The constant term in the model represents the total setup time, which consists of network latency and database connection overhead. If the database connection overhead is 20% of the total setup time, which of the following is the best interpretation of the value 8 in this model?

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Cevap: The database connection overhead, in milliseconds, for retrieving any number of records.

Cevap

The database connection overhead, in milliseconds, for retrieving any number of records.
In the linear model T=0.06r+40T = 0.06r + 40, the constant term of 4040 represents the total setup time in milliseconds, which is independent of the number of records rr retrieved. The database connection overhead is 20%20\% of this total setup time, which equals 0.20×40=80.20 \times 40 = 8 milliseconds. Since it is part of the constant term, it represents a fixed overhead of 88 milliseconds for retrieving any number of records.

Adım Adım Çözüm

1
Identify the constant term in the linear model T=0.06r+40T = 0.06r + 40.
The constant term (y-intercept) is 4040, which represents the total setup time of 4040 milliseconds when r=0r = 0 records are retrieved.
In a linear relationship of the form y=mx+by = mx + b, the constant term bb represents the initial value or y-intercept.
2
Calculate the database connection overhead.
The database connection overhead is 20%20\% of the 4040 milliseconds total setup time, which is 0.20×40=80.20 \times 40 = 8 milliseconds.
The problem states that the database connection overhead is 20% of the total setup time.
3
Interpret the calculated value of 8 in the context of the model.
Since the 4040 milliseconds is a constant term that does not depend on the number of records rr, the 88 milliseconds represents a fixed database connection overhead for any number of records retrieved.
The constant term in a linear model represents a fixed value that does not scale with the independent variable.

Anahtar Kavram

Interpreting the constant term (y-intercept) and its components in a linear relationship context.
Soru 30Soru

During a dry season, the volume of water VV, in millions of gallons, in a municipal reservoir dd days after the start of a monitoring period is modeled by the equation V=2481.8dV = 248 - 1.8d, where 0d600 \leq d \leq 60. According to the model, at what rate, in gallons per minute, is water leaving the reservoir?

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Cevap: 1250

Cevap

The reservoir is losing water at a rate of 1,2501,250 gallons per minute.
The slope of the linear equation V=2481.8dV = 248 - 1.8d is 1.8-1.8, indicating a decrease of 1.81.8 million gallons of water per day. To express this rate in gallons per minute, we perform the unit conversion. First, convert 1.81.8 million gallons to gallons: 1.8×1,000,000=1,800,0001.8 \times 1,000,000 = 1,800,000 gallons. Second, convert 11 day to minutes: 24 hours/day×60 minutes/hour=1,44024 \text{ hours/day} \times 60 \text{ minutes/hour} = 1,440 minutes. Finally, divide the total gallons by the total minutes: 1,800,000 gallons1,440 minutes=1,250\frac{1,800,000 \text{ gallons}}{1,440 \text{ minutes}} = 1,250 gallons per minute.

Adım Adım Çözüm

1
Identify the daily rate of water leaving the reservoir from the given linear equation.
The daily rate is 1.81.8 million gallons per day.
The slope of the linear equation V=2481.8dV = 248 - 1.8d is 1.8-1.8, which represents the rate of change of the volume with respect to time in days. The negative sign indicates a decrease, meaning water is leaving at a rate of 1.81.8 million gallons per day.
2
Convert the volume from million gallons to gallons.
1,800,0001,800,000 gallons.
To convert from millions of gallons to gallons, multiply the value by 1,000,0001,000,000, resulting in 1.8×1,000,000=1,800,0001.8 \times 1,000,000 = 1,800,000.
3
Convert the time unit from days to minutes.
1,4401,440 minutes.
There are 2424 hours in a day and 6060 minutes in an hour, so 1 day=24×60=1,440 minutes1 \text{ day} = 24 \times 60 = 1,440 \text{ minutes}.
4
Calculate the rate in gallons per minute.
1,2501,250 gallons per minute.
Divide the volume in gallons by the time in minutes: 1,800,000 gallons1,440 minutes=1,250\frac{1,800,000 \text{ gallons}}{1,440 \text{ minutes}} = 1,250.

Anahtar Kavram

Interpreting the slope of a linear relationship in context and performing unit conversions on rates.
Soru 31Soru

A commercial 3D printer uses a polymer filament to print prototype parts. The remaining mass of the filament spool, MM, in grams, is modeled by a linear function of the total printing time, tt, in minutes. When the printer has been running for 2020 minutes, the spool has 850850 grams of filament remaining. When the printer has been running for 5050 minutes, the spool has 685685 grams of filament remaining. According to the model, how many grams of filament does the printer use per minute?

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Cevap: 5.5

Cevap

The printer uses 5.5 grams of filament per minute.
The relationship between the printing time tt and the remaining mass of the filament MM is linear. The slope of this line represents the change in filament mass per unit of time. Based on the given coordinates (20,850)(20, 850) and (50,685)(50, 685), the slope is calculated as 6858505020=16530=5.5\frac{685 - 850}{50 - 20} = \frac{-165}{30} = -5.5 grams per minute. This means that the remaining mass decreases by 5.55.5 grams for each additional minute the printer runs, which corresponds to a usage rate of 5.55.5 grams of filament per minute.

Adım Adım Çözüm

1
Identify the data points representing time and remaining filament mass from the context.
The two points are (20,850)(20, 850) and (50,685)(50, 685).
These points allow us to calculate the rate at which the mass of the filament is changing over time.
2
Calculate the change in remaining mass and the change in printing time.
Change in mass is 685850=165685 - 850 = -165 grams. Change in time is 5020=3050 - 20 = 30 minutes.
Finding the differences in the dependent variable (mass) and independent variable (time) is the standard method to calculate a rate of change.
3
Calculate the rate of filament usage per minute.
165 grams30 minutes=5.5\frac{-165\text{ grams}}{30\text{ minutes}} = -5.5 grams per minute. The rate of usage is the positive magnitude, which is 5.55.5 grams per minute.
The slope of the linear relationship is negative because the mass is decreasing, but the rate of consumption/usage is represented as a positive quantity.

Anahtar Kavram

Interpreting the slope of a linear function in context as a rate of change.
Soru 32Soru

An agricultural drone is used to spray fertilizer on a crop field. The volume of fertilizer remaining in the drone's tank, FF, in liters, after the drone has been spraying for tt minutes is modeled by the equation F=2403.2tF = 240 - 3.2t, where 0t750 \leq t \leq 75. What is the best interpretation of the number 3.23.2 in this context?

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Cevap: The volume of fertilizer, in liters, sprayed from the tank each minute.

Cevap

The volume of fertilizer, in liters, sprayed from the tank each minute.
In the linear relationship F=2403.2tF = 240 - 3.2t, the variable tt represents time in minutes, and FF represents the remaining volume in liters. The coefficient of tt, which is 3.2-3.2, represents the rate of change of the volume of fertilizer in the tank. A slope of 3.2-3.2 means that the volume decreases by 3.23.2 liters for every additional minute of spraying. Therefore, the number 3.23.2 represents the volume of fertilizer, in liters, that is sprayed from the tank each minute.

Adım Adım Çözüm

1
Identify the structure of the linear equation.
The equation is of the form y=mx+by = mx + b, or in this case, F=3.2t+240F = -3.2t + 240, where the slope is 3.2-3.2 and the FF-intercept (initial value) is 240240.
Analyzing the components of a linear function helps determine what each constant represents in context.
2
Determine the meaning of the slope in context.
The slope is the coefficient of the independent variable tt (time in minutes). The value 3.2-3.2 indicates that for each increase of 11 minute in spraying time, the remaining volume of fertilizer, FF, decreases by 3.23.2 liters.
Slope represents the rate of change of the dependent variable relative to the independent variable.
3
Interpret the absolute value of the slope.
The value 3.23.2 represents the magnitude of this rate, which is the amount of fertilizer sprayed out of the tank per minute (3.23.2 liters per minute).
Matching the mathematical rate of change to the corresponding verbal description provides the correct interpretation.

Anahtar Kavram

Slope in a linear model represents the constant rate of change of the dependent variable per unit increase of the independent variable.
Tahmini Süre:1m 15s
Soru 33Soru

A commercial drone delivery service models the total power remaining in a drone's battery, P(w)P(w), as a percentage, after carrying a payload of weight ww kilograms for a fixed delivery distance of 10 kilometers. The relationship is modeled by the linear function P(w)=8.5w+92P(w) = -8.5w + 92. Which of the following is the best interpretation of the value 92 in this context?

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Cevap: The remaining battery power, as a percentage, after the drone carries a payload of 0 kilograms for the delivery distance.

Cevap

The remaining battery power, as a percentage, after the drone carries a payload of 0 kilograms for the delivery distance.
The linear equation is written in the slope-intercept form P(w)=mw+bP(w) = mw + b, where b=92b = 92 is the vertical intercept (y-intercept). This intercept represents the value of the dependent variable, P(w)P(w), when the independent variable, ww, is equal to 00. In this context, ww is the payload weight in kilograms and P(w)P(w) is the remaining battery power as a percentage. Thus, the value 9292 represents the remaining battery power, as a percentage, when the drone carries a payload of 00 kilograms.

Adım Adım Çözüm

1
Identify the structure of the linear function and the component being interpreted.
The linear equation is given in slope-intercept form, P(w)=mw+bP(w) = mw + b, where m=8.5m = -8.5 is the slope and b=92b = 92 is the P(w)P(w)-intercept (y-intercept).
Understanding the components of a linear function allows us to relate them to their contextual definitions.
2
Evaluate the value of the function at the P(w)P(w)-intercept where the independent variable is zero.
Substitute w=0w = 0 into the equation: P(0)=8.5(0)+92=92P(0) = -8.5(0) + 92 = 92.
The y-intercept represents the value of the dependent variable when the independent variable is equal to 0.
3
Interpret the meaning of w=0w = 0 and P(0)=92P(0) = 92 in the given context.
Since ww represents the payload weight in kilograms and P(w)P(w) represents the remaining battery power as a percentage, w=0w = 0 corresponds to a payload of 0 kilograms, and P(0)=92P(0) = 92 corresponds to a remaining battery power of 92%.
Applying the units and definitions of the variables completes the contextual interpretation of the constant.

Anahtar Kavram

Interpreting the y-intercept of a linear function in a real-world context
Soru 34Soru

A researcher monitors the temperature of a chemical compound during an experiment. The temperature, TT, in degrees Celsius, of the compound mm minutes after heating begins can be modeled by a linear relationship. The temperature increases by 4.54.5 degrees Celsius every 22 minutes. If the temperature of the compound was 12-12 degrees Celsius when heating began, after how many minutes will the temperature of the compound reach 1515 degrees Celsius?

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Cevap: 12

Cevap

The temperature of the compound will reach 1515 degrees Celsius after 1212 minutes.
The correct answer is 1212 because the temperature increases at a constant rate of 2.252.25 degrees Celsius per minute. Starting from an initial temperature of 12-12 degrees Celsius, the equation is T=2.25m12T = 2.25m - 12. Setting T=15T = 15 gives 15=2.25m1215 = 2.25m - 12, which simplifies to 27=2.25m27 = 2.25m, resulting in m=12m = 12.

Adım Adım Çözüm

1
Calculate the constant rate of temperature increase per minute.
2.252.25 degrees Celsius per minute
This rate represents the slope of the linear relationship between time and temperature.
2
Formulate the linear equation representing the temperature TT as a function of the elapsed minutes mm.
T=2.25m12T = 2.25m - 12
The slope is 2.252.25 and the vertical intercept is the initial temperature of 12-12 degrees Celsius.
3
Set T=15T = 15 and solve the linear equation for mm.
m=12m = 12
This determines the exact number of minutes needed for the temperature to reach 1515 degrees Celsius.

Anahtar Kavram

Interpreting and solving linear equations modeled from context
Soru 35Soru

To restore a depleted wetland, conservationists pump water into a basin. The volume of water in the basin, WW, in thousands of gallons, tt hours after the pumping begins is modeled by the equation W=12.5t+85W = 12.5t + 85. According to the model, how many hours of pumping are required for the volume of water in the basin to increase by 150150 thousand gallons?

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Cevap: 12

Cevap

12
The linear equation is given in slope-intercept form, W=mt+bW = mt + b, where m=12.5m = 12.5 is the slope and b=85b = 85 is the y-intercept. In this context, the slope m=12.5m = 12.5 represents the rate at which water is pumped into the basin, which is 12.512.5 thousand gallons per hour. To find the number of hours required for the volume of water to increase by 150150 thousand gallons, divide the total increase by the rate: 15012.5=12\frac{150}{12.5} = 12 hours.

Adım Adım Çözüm

1
Identify the rate of water volume increase per hour from the equation.
The rate is 12.512.5 thousand gallons per hour.
In the linear equation W=12.5t+85W = 12.5t + 85, the coefficient of tt (the slope) represents the rate of change of the water volume with respect to time.
2
Set up a relation to find the time tt for a volume increase of 150150 thousand gallons.
12.5t=15012.5t = 150
The change in volume is equal to the rate of change multiplied by the time elapsed.
3
Solve the equation for tt.
t=12t = 12
Dividing both sides of the equation 12.5t=15012.5t = 150 by 12.512.5 isolates tt.

Anahtar Kavram

Interpreting the slope of a linear equation in context as a rate of change.
Tahmini Süre:1m 30s
Soru 36Soru

A municipal water treatment facility utilizes 3 identical backup filtration units to process stormwater runoff. The average volume of water, V(t)V(t), in thousands of gallons, remaining to be filtered per unit tt hours after the units are activated is modeled by the equation:

3V(t)+14.4t=1623V(t) + 14.4t = 162

where 0t100 \le t \le 10. Which of the following is the best interpretation of the number 14.414.4 in this context?

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Cevap: The rate, in thousands of gallons per hour, at which water is filtered by all 3 units combined.

Cevap

The rate, in thousands of gallons per hour, at which water is filtered by all 3 units combined.
The correct answer is the option stating that 14.4 represents the rate, in thousands of gallons per hour, at which water is filtered by all 3 units combined. In the given equation 3V(t)+14.4t=1623V(t) + 14.4t = 162, we can isolate the total volume remaining, 3V(t)3V(t), as 3V(t)=16214.4t3V(t) = 162 - 14.4t. In this form, the rate of change of the total volume is 14.4-14.4, indicating that the combined remaining volume decreases by 14.4 thousand gallons each hour.

Adım Adım Çözüm

1
Express the total volume of water remaining to be filtered in terms of the variable V(t)V(t).
Since V(t)V(t) is the average volume of water remaining per unit and there are 3 identical units, the total volume of water remaining to be filtered by all 3 units combined is 3V(t)3V(t).
This allows us to analyze the total filtration system rather than the average per unit.
2
Isolate the term representing the total volume remaining, 3V(t)3V(t), in the given equation.
3V(t)=16214.4t3V(t) = 162 - 14.4t
This puts the equation into a standard linear form y=mx+by = mx + b where y=3V(t)y = 3V(t) is the dependent variable (total volume remaining) and x=tx = t is the independent variable (time in hours).
3
Interpret the slope and the y-intercept of the isolated linear equation.
The constant term 162 is the initial total volume of water (in thousands of gallons) remaining at t=0t = 0. The coefficient of tt, which is 14.4-14.4, represents the change in the total volume remaining per hour.
In a linear model y=mx+by = mx + b, the slope mm represents the rate of change of the dependent variable per unit increase of the independent variable.
4
Determine the contextual meaning of the absolute value of the rate of change, 14.4.
A rate of change of 14.4-14.4 thousand gallons per hour means that the total volume of water remaining decreases by 14.4 thousand gallons each hour. Therefore, 14.4 is the rate, in thousands of gallons per hour, at which water is filtered by all 3 units combined.
The rate at which the remaining volume decreases is equal to the rate at which the system filters the water.

Anahtar Kavram

Interpreting coefficients and constants in a linear relationship within a real-world context, particularly when variables represent averages or totals.
Soru 37Soru

A ride-share driver uses a mobile application to track their daily net earnings. The driver's net earnings, EE, in dollars, after completing nn rides in a day can be modeled by the equation E=18n25E = 18n - 25. Which of the following is the best interpretation of the number 2525 in this context?

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Cevap: The driver's daily starting cost, in dollars, before any rides are completed.

Cevap

The driver's daily starting cost, in dollars, before any rides are completed.
In the linear equation E=18n25E = 18n - 25, the variable EE represents net earnings and nn represents the number of rides. The constant term 25-25 represents the value of EE when n=0n = 0. In this context, starting with 25-25 dollars in net earnings means the driver has a daily starting cost or fee of 2525 dollars before completing any rides.

Adım Adım Çözüm

1
Identify the component of the linear equation E=18n25E = 18n - 25 associated with the number 2525.
The number 2525 is part of the constant term 25-25 in the equation.
Linear equations in context are typically written in the form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
2
Determine the contextual meaning of the constant term (y-intercept) in this model.
The constant term 25-25 represents the value of EE when n=0n = 0.
Setting the independent variable nn (number of rides) to 00 gives the starting value of the dependent variable EE (net earnings).
3
Interpret the negative value in terms of daily operations.
An initial net earning of 25-25 dollars means the driver starts with a cost or loss of 2525 dollars.
A negative starting value indicates a cost or fee that must be paid before any revenue is generated.

Anahtar Kavram

Interpreting the y-intercept of a linear model in context.
Soru 38Soru

A botanist models the rate of water transpiration of a plant species under various temperature conditions. The table below shows the estimated transpiration rate, RR, in milligrams of water per square decimeter of leaf area per hour (mg/(dm2h)\text{mg}/(\text{dm}^2\cdot\text{h})), at various ambient temperatures, tt, in degrees Celsius (C^\circ\text{C}).

Temperature (tt)Transpiration rate (RR)
151584.584.5
2020108.5108.5
2525132.5132.5
3030156.5156.5

The relationship between the ambient temperature and the transpiration rate is linear. Based on the model, what is the estimated increase in the transpiration rate, in milligrams of water per square meter of leaf area per minute, for each increase of 11 degree Celsius in the ambient temperature? (Note: 1 square meter=100 square decimeters1\text{ square meter} = 100\text{ square decimeters})

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Cevap: 8

Cevap

8
To find the estimated increase in transpiration rate per degree Celsius in the new units, we first determine the rate of change in the original units from the table. The change in temperature is 2015=5C20 - 15 = 5^\circ\text{C}, and the corresponding change in transpiration rate is 108.584.5=24 mg/(dm2h)108.5 - 84.5 = 24\text{ mg}/(\text{dm}^2\cdot\text{h}). The rate of change is 245=4.8 mg/(dm2h)\frac{24}{5} = 4.8\text{ mg}/(\text{dm}^2\cdot\text{h}) per 1C1^\circ\text{C} temperature increase. Converting this rate to square meters, we multiply by 100100 because 1 square meter=100 square decimeters1\text{ square meter} = 100\text{ square decimeters}, giving 480 mg/(m2h)480\text{ mg}/(\text{m}^2\cdot\text{h}). Finally, to convert to minutes, we divide by 6060 because 1 hour=60 minutes1\text{ hour} = 60\text{ minutes}, which yields 48060=8 mg/(m2min)\frac{480}{60} = 8\text{ mg}/(\text{m}^2\cdot\text{min}) per 1C1^\circ\text{C} temperature increase.

Adım Adım Çözüm

1
Find the rate of change of the transpiration rate with respect to temperature from the given data table.
Slope = 4.8 mg/(dm2h)4.8\text{ mg}/(\text{dm}^2\cdot\text{h}) per 1C1^\circ\text{C}
The rate of change represents the increase in transpiration rate for each 1C1^\circ\text{C} increase in temperature in the original units.
2
Convert the unit of area in the rate of change from square decimeters to square meters.
Rate = 480 mg/(m2h)480\text{ mg}/(\text{m}^2\cdot\text{h}) per 1C1^\circ\text{C}
Since 1 square meter=100 square decimeters1\text{ square meter} = 100\text{ square decimeters}, the rate per square meter is 100100 times the rate per square decimeter.
3
Convert the unit of time in the rate of change from hours to minutes.
Rate = 8 mg/(m2min)8\text{ mg}/(\text{m}^2\cdot\text{min}) per 1C1^\circ\text{C}
Since there are 6060 minutes in an hour, dividing the hourly rate by 6060 gives the rate per minute.

Anahtar Kavram

Interpreting the slope of a linear relationship in context and performing unit conversions.
Tahmini Süre:2m 30s
Soru 39Soru

A commercial hydroponic farm monitors the volume of nutrient solution in a reservoir. The table below shows the volume of solution remaining, VV, in liters, after tt hours of operation.

Time (tt, hours)Volume (VV, liters)
0450
10432
20414
30396

The relationship between the time and the volume of remaining solution can be modeled by a linear equation. Which of the following is the best interpretation of the slope of the graph of this equation in the tVtV-plane?

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Cevap: The nutrient solution is being depleted at a rate of 1.8 liters per hour.

Cevap

The nutrient solution is being depleted at a rate of 1.8 liters per hour.
The slope of a linear function represents the constant rate of change of the dependent variable with respect to the independent variable. By selecting two data points from the table, such as (0,450)(0, 450) and (10,432)(10, 432), the slope is calculated as 432450100=1.8\frac{432 - 450}{10 - 0} = -1.8. Since the volume VV is measured in liters and the time tt is in hours, this slope represents a decrease of 1.81.8 liters of nutrient solution per hour of operation. Therefore, the nutrient solution is being depleted at a rate of 1.81.8 liters per hour.

Adım Adım Çözüm

1
Calculate the slope using two points from the table.
Using the points (0,450)(0, 450) and (10,432)(10, 432), the slope is 432450100=1810=1.8\frac{432 - 450}{10 - 0} = \frac{-18}{10} = -1.8.
The slope of a linear relationship is given by the change in the dependent variable (Volume) divided by the change in the independent variable (Time).
2
Interpret the unit of the slope in context.
The unit of the slope is liters per hour (L/h\text{L/h}), representing a change of 1.8-1.8 liters for every hour of operation.
Determining the units of the rate helps verify what physical quantity the slope represents.
3
Relate the negative sign of the slope to the context of depletion.
A negative slope of 1.8-1.8 means the volume of nutrient solution decreases by 1.81.8 liters each hour, which translates to a depletion rate of 1.81.8 liters per hour.
Connecting the mathematical sign to the real-world action clarifies whether the quantity is increasing or decreasing.

Anahtar Kavram

Interpreting the slope of a linear equation as a constant rate of change in a real-world context.
Tahmini Süre:1m 30s
Soru 40Soru

A commercial bakery uses a mixing bowl that initially contains some flour. A machine adds flour to the bowl at a constant rate. After the machine has been running for 88 minutes, the total mass of the flour in the bowl is 1414 kilograms. After the machine has been running for 2020 minutes, the total mass of the flour in the bowl is 2929 kilograms. The relationship between the total mass of the flour in the bowl, MM, in kilograms, and the time the machine has been running, tt, in minutes, is linear. What is the mass of the flour, in kilograms, in the bowl before the machine starts running?

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Cevap: 4

Cevap

4
The relationship between the total mass of the flour, MM, and the time, tt, is linear and can be represented by the equation M=mt+bM = mt + b, where mm is the rate at which flour is added and bb is the initial mass of the flour in the bowl. Using the two given points, (8,14)(8, 14) and (20,29)(20, 29), the slope mm is calculated as m=2914208=1512=1.25m = \frac{29 - 14}{20 - 8} = \frac{15}{12} = 1.25 kilograms per minute. Substituting m=1.25m = 1.25 and the point (8,14)(8, 14) into the linear equation gives 14=1.25(8)+b14 = 1.25(8) + b, which simplifies to 14=10+b14 = 10 + b. Solving for bb yields b=4b = 4. Therefore, the mass of the flour in the bowl before the machine starts running is 44 kilograms.

Adım Adım Çözüm

1
Find the rate of change (slope) of the linear relationship.
The rate is 1.251.25 kilograms per minute.
The slope of a linear relationship represents the constant rate at which flour is added to the bowl.
2
Set up the linear equation and solve for the y-intercept.
The initial mass is 44 kilograms.
The y-intercept represents the initial mass of the flour in the bowl at t=0t = 0 minutes.

Anahtar Kavram

Interpreting the y-intercept of a linear relationship in context
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