Systems of Linear Inequalities in Two Variables

48 soru

Soru 41Soru

A nutritionist is designing a meal plan containing xx grams of protein and yy grams of carbohydrates. The meal plan must satisfy the following system of inequalities:

y1.5x+153x+2y120\begin{aligned} y &\ge 1.5x + 15 \\ 3x + 2y &\le 120 \end{aligned}

What is the maximum possible number of grams of protein, xx, that can be included in the meal plan?

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Cevap: 15

Cevap

The maximum possible number of grams of protein that can be included is 15.
To find the maximum possible value of xx, we determine the region defined by the system of inequalities. The system restricts the values to the region above the line y=1.5x+15y = 1.5x + 15 and below the line 3x+2y=1203x + 2y = 120. Since the first inequality limits yy from below and the second limits yy from above, the feasible region narrows as xx increases, terminating at the intersection of the two boundary lines. Substituting y=1.5x+15y = 1.5x + 15 into 3x+2y=1203x + 2y = 120 gives 3x+2(1.5x+15)=1203x + 2(1.5x + 15) = 120. Simplifying this yields 3x+3x+30=1203x + 3x + 30 = 120, which simplifies further to 6x=906x = 90, giving x=15x = 15. Thus, the maximum value of xx is 15.

Adım Adım Çözüm

1
Identify the boundary lines of the system of inequalities.
The boundary lines are y=1.5x+15y = 1.5x + 15 and 3x+2y=1203x + 2y = 120.
The maximum value of xx under these linear constraints occurs at the intersection of the boundary lines of the feasible region.
2
Substitute the expression for yy from the first boundary equation into the second equation.
3x+2(1.5x+15)=1203x + 2(1.5x + 15) = 120
This allows us to solve for xx by eliminating yy.
3
Simplify the equation and solve for xx.
3x+3x+30=120    6x+30=120    6x=90    x=153x + 3x + 30 = 120 \implies 6x + 30 = 120 \implies 6x = 90 \implies x = 15.
Solving the linear equation gives the xx-coordinate of the intersection point.
4
Verify that this point lies in the feasible region and represents the maximum possible value of xx.
At x=15x=15, y=37.5y=37.5. Since y1.5x+15y \ge 1.5x + 15 restricts the region above the line and 3x+2y1203x + 2y \le 120 restricts it below the line, the region lies to the left of the intersection point (15,37.5)(15, 37.5). Thus, the maximum value of xx is 15.
Confirming the geometry of the feasible region ensures the intersection point is indeed the maximum value.

Anahtar Kavram

Solving systems of linear inequalities to find the boundaries and extreme values of a feasible region.
Soru 42Soru

Consider the system of inequalities below:

3x+y>5x2y>4\begin{aligned} 3x + y &> 5 \\ x - 2y &> 4 \end{aligned}

Which of the following coordinate pairs (x,y)(x, y) is a solution to the system?

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Cevap: (4,2)(4, -2)

Cevap

(4,2)(4, -2)
The coordinate pair (4,2)(4, -2) is the correct answer because substituting these values into both inequalities of the system produces true statements: 3(4)+(2)=10>53(4) + (-2) = 10 > 5 and 42(2)=8>44 - 2(-2) = 8 > 4.

Adım Adım Çözüm

1
Substitute the coordinates of the candidate point into the first inequality, 3x+y>53x + y > 5.
For (4,2)(4, -2), we get 3(4)+(2)=122=103(4) + (-2) = 12 - 2 = 10. Since 10>510 > 5, the first inequality is satisfied.
A coordinate pair must satisfy both inequalities in the system to be a solution.
2
Substitute the coordinates of the candidate point into the second inequality, x2y>4x - 2y > 4.
For (4,2)(4, -2), we get 42(2)=4+4=84 - 2(-2) = 4 + 4 = 8. Since 8>48 > 4, the second inequality is also satisfied.
Since both inequalities are true for (4,2)(4, -2), it is a valid solution to the system.

Anahtar Kavram

A coordinate pair (x,y)(x, y) is a solution to a system of linear inequalities if and only if it makes all inequalities in the system true when substituted.
Tahmini Süre:1m 30s
Soru 43Soru

A software programmer is writing test cases for a new application. The programmer must write at least 15 test cases in total, consisting of xx unit tests and yy integration tests. Each unit test takes 10 minutes to write, and each integration test takes 30 minutes to write. If the programmer has at most 300 minutes to write all the test cases, what is the maximum number of integration tests the programmer can write?

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Cevap: 7

Cevap

7

Adım Adım Çözüm

1
Set up the system of inequalities representing the given constraints.
x+y15x + y \ge 15 and 10x+30y30010x + 30y \le 300
The total number of tests must be at least 15, and the total time taken by writing xx unit tests (10 minutes each) and yy integration tests (30 minutes each) cannot exceed 300 minutes.
2
Simplify the time inequality and combine it with the total test count constraint to isolate yy.
x+3y30x + 3y \le 30. Substituting x15yx \ge 15 - y into this inequality yields (15y)+3y30    15+2y30(15 - y) + 3y \le 30 \implies 15 + 2y \le 30.
Simplification and substitution help find the upper bound for the number of integration tests.
3
Solve for yy and determine the maximum integer value.
2y15    y7.52y \le 15 \implies y \le 7.5. The largest integer satisfying this inequality is 7.
The number of integration tests must be a whole number, so we round down to the nearest integer.
4
Verify that a valid integer number of unit tests (xx) exists when y=7y = 7.
When y=7y = 7, we get x157    x8x \ge 15 - 7 \implies x \ge 8 and x+3(7)30    x9x + 3(7) \le 30 \implies x \le 9. The integers x=8x = 8 and x=9x = 9 both satisfy the conditions.
We must confirm that the maximum value of yy is achievable with an integer number of unit tests.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Soru 44Soru

In the xyxy-plane, a system of inequalities consists of the following:

y>12x+2y > -\frac{1}{2}x + 2
y3x1y \leq 3x - 1

Which of the following coordinate pairs (x,y)(x, y) is a solution to this system?

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Cevap: (2,2)(2, 2)

Cevap

The coordinate pair (2,2)(2, 2)
The coordinate pair (2,2)(2, 2) is the correct answer because substituting x=2x = 2 and y=2y = 2 into both inequalities yields true statements. For the first inequality, 2>12(2)+22 > -\frac{1}{2}(2) + 2 simplifies to 2>12 > 1, which is true. For the second inequality, 23(2)12 \leq 3(2) - 1 simplifies to 252 \leq 5, which is also true. Since the point satisfies both inequalities, it lies in the solution region.

Adım Adım Çözüm

1
Understand the definition of a solution to a system of inequalities.
A coordinate pair (x,y)(x, y) is a solution to a system of inequalities if and only if it satisfies both inequalities simultaneously when substituted.
This establishes the verification method for checking the options.
2
Substitute the coordinate pair (2,2)(2, 2) into the first inequality: y>12x+2y > -\frac{1}{2}x + 2.
2>12(2)+2    2>1+2    2>12 > -\frac{1}{2}(2) + 2 \implies 2 > -1 + 2 \implies 2 > 1.
This determines if the coordinate pair satisfies the first boundary condition.
3
Substitute the coordinate pair (2,2)(2, 2) into the second inequality: y3x1y \leq 3x - 1.
23(2)1    261    252 \leq 3(2) - 1 \implies 2 \leq 6 - 1 \implies 2 \leq 5.
This determines if the coordinate pair satisfies the second boundary condition.
4
Conclude whether both statements are true.
Since 2>12 > 1 is true and 252 \leq 5 is true, the coordinate pair (2,2)(2, 2) is a solution to the system.
Both conditions must be met for the coordinate pair to belong to the solution set.

Anahtar Kavram

Verifying coordinate solutions for systems of linear inequalities
Tahmini Süre:1m 30s
Soru 45Soru

A point (x,y)(x, y) in the coordinate plane satisfies the system of inequalities below.

y2x4y \geq 2x - 4
yx+5y \leq -x + 5
x0x \geq 0
y0y \geq 0

What is the maximum possible value of xx for this point?

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Cevap: 3

Cevap

The maximum possible value of xx that satisfies the system of inequalities is 3.
To find the maximum possible value of xx for a point satisfying the system of inequalities, we identify the vertices of the region. The upper-right boundary of the region is formed by the intersection of the lines y=2x4y = 2x - 4 and y=x+5y = -x + 5. Solving 2x4=x+52x - 4 = -x + 5 gives 3x=9    x=33x = 9 \implies x = 3. At this point, y=3+5=2y = -3 + 5 = 2, which satisfies the constraints x0x \geq 0 and y0y \geq 0. The other boundary vertices of the region are (0,0)(0, 0), (2,0)(2, 0), and (0,5)(0, 5). Comparing the x-coordinates of these vertices (00, 22, and 33), we see that the maximum possible value of xx is 33.

Adım Adım Çözüm

1
Find the intersection point of the boundary lines y=2x4y = 2x - 4 and y=x+5y = -x + 5.
x=3x = 3
Setting the two boundary line equations equal to each other (2x4=x+52x - 4 = -x + 5) allows us to find the x-coordinate where the boundaries cross.
2
Substitute x=3x = 3 back into one of the boundary equations to find the y-coordinate.
y=2y = 2
This yields the intersection point (3,2)(3, 2) which lies on both boundary lines.
3
Verify that the intersection point (3,2)(3, 2) satisfies the other constraints: x0x \geq 0 and y0y \geq 0.
303 \geq 0 and 202 \geq 0 (both true)
The point must lie within the first quadrant to be a valid solution.
4
Determine the remaining boundary vertices of the solution region in the first quadrant.
Vertices are (0,0)(0, 0), (0,5)(0, 5), (2,0)(2, 0), and (3,2)(3, 2).
Comparing all vertices will confirm if (3,2)(3, 2) indeed provides the maximum value of xx.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Soru 46Soru

A logistics company uses a delivery drone to transport two types of packages. Let xx represent the number of Type A packages and yy represent the number of Type B packages in a single flight. The drone can carry at most 12 packages in total. Additionally, to balance the drone, the total weight of the cargo must be at least 15 pounds. Each Type A package weighs 2 pounds, and each Type B package weighs 1 pound. Which of the following combinations of Type A and Type B packages is a viable shipment for the drone?

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Cevap: 5 Type A packages and 6 Type B packages

Cevap

5 Type A packages and 6 Type B packages
The correct combination of 5 Type A packages and 6 Type B packages satisfies all system requirements. The total package count of 11 is less than or equal to the drone's limit of 12 packages (5+6125 + 6 \leq 12). Furthermore, the total weight of 16 pounds meets the minimum balance requirement of 15 pounds (2(5)+6152(5) + 6 \geq 15).

Adım Adım Çözüm

1
Write the system of linear inequalities that represents the given constraints.
The capacity constraint is x+y12x + y \leq 12, and the weight constraint is 2x+y152x + y \geq 15, where xx and yy are non-negative integers.
To define the mathematical boundaries for a valid shipment.
2
Substitute the package counts from the correct combination into both inequalities to verify they are satisfied.
For 5 Type A packages (x=5x = 5) and 6 Type B packages (y=6y = 6):
- Package count: 5+6=11125 + 6 = 11 \leq 12 (True)
- Cargo weight: 2(5)+6=16152(5) + 6 = 16 \geq 15 (True)
To confirm that the chosen combination satisfies all system requirements.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Tahmini Süre:1m 30s
Soru 47Soru

In the xyxy-plane, a point with coordinates (x,y)(x, y) lies in the region defined by the system of inequalities below.

y+2x12y + 2x \leq 12
x2y6x - 2y \leq 6
x2x \geq 2

What is the maximum possible value of yy?

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Cevap: 8

Cevap

8
The system of inequalities bounds the solution set. The upper boundary is given by y2x+12y \leq -2x + 12. Because the slope is negative, the maximum value of yy on this boundary occurs at the smallest possible value of xx. The constraint x2x \geq 2 dictates that the minimum value of xx is 2. Substituting x=2x = 2 into the boundary equation yields y=2(2)+12=8y = -2(2) + 12 = 8. Checking this coordinate against the third inequality, 22(8)=1462 - 2(8) = -14 \leq 6, verifies that (2,8)(2, 8) is a valid solution.

Adım Adım Çözüm

1
Express the first two inequalities in terms of y.
y2x+12y \leq -2x + 12 and y12x3y \geq \frac{1}{2}x - 3
This helps identify the upper and lower boundaries of the solution region.
2
Determine the boundary line that limits the maximum values of y.
The upper boundary is the line y=2x+12y = -2x + 12.
Since the inequality is y2x+12y \leq -2x + 12, any solution must lie on or below this line.
3
Find the maximum value of y on this boundary line given the constraint x2x \geq 2.
y2(2)+12=8y \leq -2(2) + 12 = 8
Since the slope of the boundary line is negative, y is maximized when x is at its minimum value, which is 2.
4
Verify that the point (2,8)(2, 8) satisfies the inequality x2y6x - 2y \leq 6.
22(8)=1462 - 2(8) = -14 \leq 6, which is true.
This confirms that the point (2,8)(2, 8) is indeed in the solution set of the system.

Anahtar Kavram

Maximizing a coordinate value subject to a system of linear inequalities in two variables

Alternatif Yöntem

Instead of graphing or checking boundaries, we can algebraically solve for the boundary. Since x2x \geq 2, multiplying by 2-2 and reversing the inequality gives 2x4-2x \leq -4. Adding 12 to both sides gives 2x+128-2x + 12 \leq 8. Since y2x+12y \leq -2x + 12, we get y8y \leq 8. Checking if y=8y = 8 and x=2x = 2 satisfies the second inequality x2y6x - 2y \leq 6 confirms that 216=1462 - 16 = -14 \leq 6 is true, meaning y=8y = 8 is indeed a valid solution and thus the maximum.
Tahmini Süre:1m 30s
Soru 48Soru

An artist creates xx small sculptures and yy large sculptures. Each small sculpture requires 3 hours of crafting and 2 hours of painting. Each large sculpture requires 7 hours of crafting and 3 hours of painting. The artist can spend at most 120 hours on crafting and at most 50 hours on painting. Which of the following pairs of small and large sculptures can the artist create under these constraints?

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Cevap: 10 small sculptures and 8 large sculptures

Cevap

10 small sculptures and 8 large sculptures
The option featuring 10 small sculptures and 8 large sculptures is correct because substituting x=10x = 10 and y=8y = 8 satisfies both linear inequalities representing the constraints. Specifically, the crafting time of 86 hours is less than or equal to the maximum allowed 120 hours (3(10)+7(8)=861203(10) + 7(8) = 86 \leq 120), and the painting time of 44 hours is less than or equal to the maximum allowed 50 hours (2(10)+3(8)=44502(10) + 3(8) = 44 \leq 50).

Adım Adım Çözüm

1
Set up the system of inequalities representing the constraints.
The crafting constraint is 3x+7y1203x + 7y \leq 120. The painting constraint is 2x+3y502x + 3y \leq 50. The variables must be non-negative: x0x \geq 0 and y0y \geq 0.
To model the limits on crafting hours and painting hours mathematically.
2
Substitute the values of each option into the system to verify which one satisfies both inequalities.
For the option with 10 small sculptures and 8 large sculptures (x=10,y=8x = 10, y = 8):
3(10)+7(8)=30+56=861203(10) + 7(8) = 30 + 56 = 86 \leq 120 (True)
2(10)+3(8)=20+24=44502(10) + 3(8) = 20 + 24 = 44 \leq 50 (True)
Only a coordinate pair that makes both inequality statements true is a valid solution.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
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