Problem-Solving and Data Analysis

179 soru

Soru 161Soru

A local utility company is evaluating two different methods, Method A and Method B, to reduce electricity distribution losses. The table below shows the modeled annual electricity losses, in megawatt-hours (MWh), for each method over the first two years (t=0t = 0 to t=2t = 2), where tt is the number of years since the evaluation began.

Year (tt)Method A losses (MWh)Method B losses (MWh)
08,0008,000
17,4007,200
26,8006,480

One method is modeled by a linear function, and the other method is modeled by an exponential function. What is the difference, in MWh, between the modeled annual electricity losses for the two methods at t=3t = 3 years?

Cevabı ve açıklamayı göster

Cevap: 368

Cevap

368
To find the difference between the modeled annual electricity losses at t=3t = 3, we first identify the type of model for each method. For Method A, the losses decrease by a constant amount of 600 MWh600\text{ MWh} each year (8,0007,400=6008,000 - 7,400 = 600 and 7,4006,800=6007,400 - 6,800 = 600), which indicates a linear relationship. Thus, the model for Method A is LA(t)=8,000600tL_A(t) = 8,000 - 600t. At t=3t = 3, the losses for Method A are LA(3)=8,000600(3)=6,200 MWhL_A(3) = 8,000 - 600(3) = 6,200\text{ MWh}. For Method B, the losses decrease by a constant percentage of 10%10\% each year, meaning each year's value is 90%90\% of the previous year's value (7,2008,000=0.9\frac{7,200}{8,000} = 0.9 and (6,4807,200=0.9\frac{6,480}{7,200} = 0.9). This indicates an exponential relationship with a decay factor of 0.90.9. Thus, the model for Method B is LB(t)=8,000(0.9)tL_B(t) = 8,000(0.9)^t. At t=3t = 3, the losses for Method B are LB(3)=8,000(0.9)3=8,000(0.729)=5,832 MWhL_B(3) = 8,000(0.9)^3 = 8,000(0.729) = 5,832\text{ MWh}. The difference between the modeled losses is 6,2005,832=368 MWh6,200 - 5,832 = 368\text{ MWh}.

Adım Adım Çözüm

1
Identify the type of model for Method A by examining its rate of change.
Method A decreases by a constant value of 600 MWh600\text{ MWh} each year (8,0007,400=6008,000 - 7,400 = 600 and 7,4006,800=6007,400 - 6,800 = 600), which means it is a linear function.
Linear functions have a constant first difference (constant rate of change).
2
Identify the type of model for Method B by examining its ratios.
Method B decreases by a constant ratio of 0.90.9 each year (7,2008,000=0.9\frac{7,200}{8,000} = 0.9 and (6,4807,200=0.9\frac{6,480}{7,200} = 0.9), which means it is an exponential function.
Exponential functions have a constant ratio between consecutive terms.
3
Formulate the equations for both models.
LA(t)=8,000600tL_A(t) = 8,000 - 600t and LB(t)=8,000(0.9)tL_B(t) = 8,000(0.9)^t.
These equations represent the linear decrease and exponential decay starting from 8,0008,000.
4
Calculate the modeled losses for both methods at t=3t = 3.
LA(3)=8,000600(3)=6,200 MWhL_A(3) = 8,000 - 600(3) = 6,200\text{ MWh} and LB(3)=8,000(0.9)3=8,000(0.729)=5,832 MWhL_B(3) = 8,000(0.9)^3 = 8,000(0.729) = 5,832\text{ MWh}.
To find the values at t=3t = 3, substitute 33 for tt in both equations.
5
Calculate the difference between the two values.
6,2005,832=368 MWh6,200 - 5,832 = 368\text{ MWh}.
Subtract the smaller loss value from the larger loss value to find the difference.

Anahtar Kavram

Identifying and modeling linear growth/decay (constant change per unit time) versus exponential growth/decay (constant percent change per unit time) from data tables.
Soru 162Soru

A food packaging company produces a trail mix containing almonds, cashews, and raisins. The ratio of the weight of almonds to the weight of cashews is 3:23:2, and the ratio of the weight of cashews to the weight of raisins is 5:45:4. If a batch of trail mix contains 360360 ounces of raisins, what is the total weight, in ounces, of the trail mix?

Cevabı ve açıklamayı göster

Cevap: 1,4851,485

Cevap

1,485
To find the total weight of the trail mix, we determine the weights of cashews and almonds using the given ratios and the weight of raisins. The weight of cashews is calculated as 54×360=450\frac{5}{4} \times 360 = 450 ounces. Using the weight of cashews, the weight of almonds is calculated as 32×450=675\frac{3}{2} \times 450 = 675 ounces. Summing the weights of all three components yields 675+450+360=1,485675 + 450 + 360 = 1,485 ounces.

Adım Adım Çözüm

1
Use the given ratio of cashews to raisins to find the weight of the cashews.
The weight of the cashews is 450450 ounces.
Since the ratio of the weight of cashews to raisins is 5:45:4, we set up the proportion cashews360=54\frac{\text{cashews}}{360} = \frac{5}{4}. Solving for cashews gives cashews=360×54=450\text{cashews} = 360 \times \frac{5}{4} = 450 ounces.
2
Use the ratio of almonds to cashews to find the weight of the almonds.
The weight of the almonds is 675675 ounces.
Since the ratio of the weight of almonds to cashews is 3:23:2, we set up the proportion almonds450=32\frac{\text{almonds}}{450} = \frac{3}{2}. Solving for almonds gives almonds=450×32=675\text{almonds} = 450 \times \frac{3}{2} = 675 ounces.
3
Sum the weights of all three ingredients to find the total weight of the trail mix.
The total weight is 1,4851,485 ounces.
The total weight is the sum of the weights of almonds, cashews, and raisins: 675+450+360=1,485675 + 450 + 360 = 1,485 ounces.

Anahtar Kavram

Solving multi-step ratio problems by linking parts using a common element to find the total quantity.
Soru 163Soru

At the beginning of 2015, Forest A had 4,000 trees and Forest B had 3,000 trees. The number of trees in Forest A increases by 150 trees each year. The number of trees in Forest B increases by 4% each year. If A(t)A(t) and B(t)B(t) represent the number of trees in Forest A and Forest B, respectively, tt years after the beginning of 2015, what is the value of A(5)B(5)A(5) - B(5), rounded to the nearest whole number?

Cevabı ve açıklamayı göster

Cevap: 1100

Cevap

The correct value of A(5)B(5)A(5) - B(5) is 1100.
The correct value is 1100. By defining Forest A's population with the linear function A(t)=4000+150tA(t) = 4000 + 150t and Forest B's population with the exponential function B(t)=3000(1.04)tB(t) = 3000(1.04)^t, evaluating both functions at t=5t = 5 yields A(5)=4750A(5) = 4750 and B(5)3650B(5) \approx 3650. The difference is 47503650=11004750 - 3650 = 1100.

Adım Adım Çözüm

1
Formulate the growth model for Forest A.
A(t)=4000+150tA(t) = 4000 + 150t
Forest A grows linearly with a constant increase of 150 trees per year from an initial value of 4,000 trees.
2
Formulate the growth model for Forest B.
B(t)=3000(1.04)tB(t) = 3000(1.04)^t
Forest B grows exponentially with a constant percent increase of 4% per year (growth factor of 1+0.04=1.041 + 0.04 = 1.04) from an initial value of 3,000 trees.
3
Calculate the population of each forest after 5 years (t=5t = 5).
A(5)=4750A(5) = 4750 and B(5)3650B(5) \approx 3650
Substitute t=5t = 5 into both models: A(5)=4000+150(5)=4750A(5) = 4000 + 150(5) = 4750 and B(5)=3000(1.04)53649.96B(5) = 3000(1.04)^5 \approx 3649.96.
4
Calculate the difference A(5)B(5)A(5) - B(5) and round to the nearest whole number.
1100
Subtract: 47503649.96=1100.044750 - 3649.96 = 1100.04. Rounding 1100.04 to the nearest whole number yields 1100.

Anahtar Kavram

Linear vs. Exponential Growth Models

Alternatif Yöntem

Instead of evaluating each function separately, you can construct the difference expression directly as D(t)=(4000+150t)3000(1.04)tD(t) = (4000 + 150t) - 3000(1.04)^t and substitute t=5t = 5 into D(t)D(t) to compute D(5)=47503000(1.04)51100.04D(5) = 4750 - 3000(1.04)^5 \approx 1100.04, which rounds to 1100.
Tahmini Süre:1m 30s
Soru 164Soru

An agricultural irrigation system uses two types of sprinklers, Type A and Type B. Water flows through 33 Type A sprinklers at a combined rate of 1515 gallons per minute. Water flows through 55 Type B sprinklers at a combined rate of 1818 gallons per minute. If a farmer runs 88 Type A sprinklers and 1010 Type B sprinklers simultaneously, what is the total rate of water flow, in gallons per minute?

Cevabı ve açıklamayı göster

Cevap: 76

Cevap

The total rate of water flow is 76 gallons per minute.
To find the total water flow rate, determine the rate of a single sprinkler of each type first. For Type A, the rate is 15 gallons per minute÷3=5 gallons per minute15 \text{ gallons per minute} \div 3 = 5 \text{ gallons per minute}. For Type B, the rate is 18 gallons per minute÷5=3.6 gallons per minute18 \text{ gallons per minute} \div 5 = 3.6 \text{ gallons per minute}. Running 88 Type A sprinklers and 1010 Type B sprinklers simultaneously yields a total rate of (8×5)+(10×3.6)=40+36=76(8 \times 5) + (10 \times 3.6) = 40 + 36 = 76 gallons per minute.

Adım Adım Çözüm

1
Find the rate of water flow for a single Type A sprinkler.
Each Type A sprinkler has a water flow rate of 55 gallons per minute.
Dividing the combined rate of 1515 gallons per minute by the 33 sprinklers gives the individual rate.
2
Find the rate of water flow for a single Type B sprinkler.
Each Type B sprinkler has a water flow rate of 3.63.6 gallons per minute.
Dividing the combined rate of 1818 gallons per minute by the 55 sprinklers gives the individual rate.
3
Calculate the total water flow rate for the combined group of active sprinklers.
The total combined flow rate is 7676 gallons per minute.
Multiplying the individual rate of each type by the respective count of active sprinklers and summing the results: (8×5)+(10×3.6)=40+36=76(8 \times 5) + (10 \times 3.6) = 40 + 36 = 76.

Anahtar Kavram

Combining rates of individual components to find a total rate.
Tahmini Süre:1m 30s
Soru 165Soru

A marine biologist wants to estimate the number of blue crabs in a bay that are infected with a specific parasite. The biologist captures a random sample of 250250 blue crabs from the bay, finds that 1515 of the crabs are infected, and then releases them. Based on this sample, if there is a total population of 12,00012,000 blue crabs in the bay, what is the best estimate of the total number of blue crabs infected with the parasite?

Cevabı ve açıklamayı göster

Cevap: 720

Cevap

The best estimate of the total number of blue crabs infected with the parasite is 720.
The correct answer is found by establishing the sample proportion of infected crabs, which is 15 out of 250, or 6%. Multiplying this rate by the total estimated population of 12,000 crabs yields 720.

Adım Adım Çözüm

1
Calculate the proportion of infected crabs in the sample.
15250=0.06\frac{15}{250} = 0.06
To determine the rate of infection in the representative sample.
2
Multiply the sample proportion by the total population of blue crabs in the bay.
0.06×12,000=7200.06 \times 12,000 = 720
To generalize the sample rate to the entire population of crabs in the bay.

Anahtar Kavram

Generalizing a sample proportion to estimate a population parameter.
Soru 166Soru

A dermatologist at a medical clinic wants to estimate the proportion of residents in a city who experience seasonal dry skin. The dermatologist surveys a random sample of 150 patients who visited the clinic in December and finds that 90 of them (60%) reported experiencing seasonal dry skin. Which of the following is the most appropriate conclusion based on this study?

Cevabı ve açıklamayı göster

Cevap: No reliable conclusion can be drawn about the proportion of all residents in the city who experience seasonal dry skin because the sample is not representative of the city's population.

Cevap

No reliable conclusion can be drawn about the proportion of all residents in the city who experience seasonal dry skin because the sample is not representative of the city's population.
The correct conclusion is that no reliable conclusion can be drawn about all residents of the city. For a sample's findings to be generalized to a larger population, the sample must be randomly selected from that population. In this study, the sample is composed of patients at a dermatology clinic, who are more likely to have skin concerns, and the study was done in December, when dry skin is seasonally more common. Therefore, the sample is not representative of the city's general population, and we cannot generalize the 60% statistic to the entire city.

Adım Adım Çözüm

1
Identify the population of interest and the sample group.
The population of interest is all residents of the city. The sample group is 150 patients visiting a dermatology clinic in December.
Understanding the relationship between the sample and the population is necessary to determine if generalization is valid.
2
Evaluate whether the sample is representative of the population of interest.
The sample is not representative because dermatology patients are more likely to have skin issues than the average resident, and December is a winter month when dry skin is more common.
A sample must be randomly selected and representative of the target population to allow for valid generalization.
3
Select the conclusion that reflects the limitation of the sample.
The only appropriate conclusion is that no reliable conclusion can be drawn about the general city population from this biased sample.
Since the sample is biased and non-representative, generalizing the results would lead to an incorrect conclusion about the population of all city residents.

Anahtar Kavram

Generalizability of study results based on sample selection and representativeness.
Soru 167Soru

An educational organization wants to estimate the number of high school seniors in a school district who plan to major in a STEM field. A random sample of 320320 high school seniors in the district was surveyed, and 35%35\% of the surveyed students reported that they plan to major in a STEM field. The survey has an associated margin of error of 4%4\%. There are 4,5004,500 high school seniors in the school district. Based on these results, what is the maximum estimated number of high school seniors in the district who plan to major in a STEM field?

Cevabı ve açıklamayı göster

Cevap: 1755

Cevap

1755
The survey estimate for the proportion of students who plan to major in a STEM field is 35%35\% with a margin of error of 4%4\%. This means the true proportion is estimated to be between 35%4%=31%35\% - 4\% = 31\% and 35%+4%=39%35\% + 4\% = 39\%. To find the maximum estimated number of students in the population of 4,5004,500, we use the maximum estimated proportion of 39%39\% (or 0.390.39). Multiplying 0.390.39 by 4,5004,500 yields 1,7551,755.

Adım Adım Çözüm

1
Calculate the maximum estimated percentage of students by adding the margin of error to the sample percentage.
39%39\% (or 0.390.39)
The margin of error gives the range of values above and below the sample estimate that represents the true population proportion. The maximum value of this range is found by adding the margin of error.
2
Multiply the maximum estimated proportion by the total number of high school seniors in the district.
1,755
To generalize the sample results to the entire population of 4,5004,500 seniors, multiply the maximum proportion by the total population size.

Anahtar Kavram

Estimating population parameters using sample proportions and margin of error
Soru 168Soru

A juice mixture is made by combining orange concentrate and water in a ratio of 22 to 55 by volume. To make a large batch of this mixture, a worker uses a total of 3535 liters of water. If the worker wants to dilute the mixture so that the new ratio of orange concentrate to water is 11 to 44 by volume, how many additional liters of water must be added?

Cevabı ve açıklamayı göster

Cevap: 21

Cevap

21
The correct answer is 21. First, we find the volume of orange concentrate in the initial mixture. The ratio of orange concentrate to water is 2 to 5, and the volume of water is 35 liters. Setting up the proportion 25=concentrate35\frac{2}{5} = \frac{\text{concentrate}}{35} gives a concentrate volume of 14 liters. When the mixture is diluted, the amount of orange concentrate remains 14 liters, but the ratio of concentrate to water becomes 1 to 4. Setting up the new proportion 14=14new water\frac{1}{4} = \frac{14}{\text{new water}} gives a new water volume of 56 liters. The additional water required is the difference between the final and initial water volumes, which is 5635=2156 - 35 = 21 liters.

Adım Adım Çözüm

1
Determine the volume of orange concentrate in the initial mixture.
The initial ratio of orange concentrate to water is 2:52:5. Since the mixture contains 3535 liters of water, the volume of orange concentrate, xx, can be found using the proportion 25=x35\frac{2}{5} = \frac{x}{35}. Solving for xx gives x=2×355=14x = \frac{2 \times 35}{5} = 14 liters.
The amount of orange concentrate must be determined because it remains constant during dilution.
2
Calculate the total volume of water needed for the diluted mixture.
In the diluted mixture, the ratio of orange concentrate to water is 1:41:4. Since the amount of orange concentrate is still 1414 liters, the new volume of water, yy, can be found using the proportion 14=14y\frac{1}{4} = \frac{14}{y}. Solving for yy gives y=14×4=56y = 14 \times 4 = 56 liters.
The final volume of water is required to determine the additional amount of water that needs to be added.
3
Find the additional volume of water that must be added.
Subtract the initial volume of water from the final volume of water: 5635=2156 - 35 = 21 liters.
Subtracting the starting amount of water gives the volume of new water needed to achieve the target ratio.

Anahtar Kavram

Using proportions to solve multi-step mixture and dilution problems.
Soru 169Soru

A consumer electronics reviewer is tracking the resale value of two different smartphone models. At the time of purchase (t=0t = 0 years), Smartphone A and Smartphone B each have a retail value of 1,0001,000 dollars. The value of Smartphone A decreases by 10%10\% of its value from the previous year each year. The value of Smartphone B decreases by a constant amount of 100100 dollars each year. What is the difference, in dollars, between the values of the two smartphones 33 years after they were purchased?

Cevabı ve açıklamayı göster

Cevap: 29

Cevap

The difference between the values of the two smartphones is 29 dollars.
The correct answer is the option showing a difference of 2929 dollars. To solve this, we model each smartphone's resale value over time. Smartphone A experiences exponential decay with a decay factor of 0.900.90. Its value after 33 years is 1,000(0.90)3=7291,000(0.90)^3 = 729 dollars. Smartphone B experiences linear decay with a constant rate of decrease of 100100 dollars per year. Its value after 33 years is 1,000100(3)=7001,000 - 100(3) = 700 dollars. The difference between these two values is 729700=29729 - 700 = 29 dollars.

Adım Adım Çözüm

1
Find the value of Smartphone A at t=3t = 3 years.
The resale value of Smartphone A is 1,000(10.10)3=1,000(0.90)3=1,000(0.729)=7291,000(1 - 0.10)^3 = 1,000(0.90)^3 = 1,000(0.729) = 729 dollars.
Smartphone A decreases by a constant percentage of 10%10\% each year, which represents exponential decay.
2
Find the value of Smartphone B at t=3t = 3 years.
The resale value of Smartphone B is 1,000100(3)=1,000300=7001,000 - 100(3) = 1,000 - 300 = 700 dollars.
Smartphone B decreases by a constant absolute amount of 100100 dollars each year, which represents linear decay.
3
Calculate the difference between the two values at t=3t = 3 years.
729700=29729 - 700 = 29 dollars.
Subtract the smaller value from the larger value to find the positive difference.

Anahtar Kavram

Linear and Exponential Growth and Decay
Soru 170Soru

A network router transmits data from two sources, Server AA and Server BB, at a constant ratio of 55 megabytes (MB\text{MB}) from Server AA for every 3 MB3\text{ MB} from Server BB. In a single session, the router transmitted a combined total of 160 MB160\text{ MB} of data from both servers. During the next session, the router transmits data at the same ratio, but the amount of data transmitted from Server AA is 20%20\% greater than the amount of data transmitted from Server AA in the first session. How many megabytes of data are transmitted from Server BB in the second session?

Cevabı ve açıklamayı göster

Cevap: 72

Cevap

The amount of data transmitted from Server B in the second session is 72 megabytes.
To find the data transmitted from Server B in the second session, we first determine the individual data amounts from the first session. Given the ratio of data from Server A to Server B is 5:35:3 and the total is 160 MB160\text{ MB}, we can express their data amounts as 5x5x and 3x3x. Solving 5x+3x=1605x + 3x = 160 yields x=20x = 20. Thus, Server A transmitted 5×20=100 MB5 \times 20 = 100\text{ MB} and Server B transmitted 3×20=60 MB3 \times 20 = 60\text{ MB} in the first session. In the second session, the data from Server A increased by 20%20\%, yielding 100×1.20=120 MB100 \times 1.20 = 120\text{ MB}. Since the transmission ratio between Server A and Server B remains constant at 5:35:3, we can set up the proportion 120B=53\frac{120}{B} = \frac{5}{3}. Cross-multiplying gives 5B=3605B = 360, which solves to B=72B = 72 megabytes.

Adım Adım Çözüm

1
Set up an equation for the total data in the first session.
5x+3x=160    8x=160    x=205x + 3x = 160 \implies 8x = 160 \implies x = 20
The ratio of data from Server A to Server B is 5:35:3, meaning the amounts can be represented as 5x5x and 3x3x for some multiplier xx.
2
Calculate the data transmitted from Server A in the first session.
A1=5(20)=100 MBA_1 = 5(20) = 100\text{ MB}
Multiply the ratio term for Server A by the scale factor xx to find its initial data contribution.
3
Calculate the increased data from Server A in the second session.
A2=100×(1+0.20)=120 MBA_2 = 100 \times (1 + 0.20) = 120\text{ MB}
Increase the first session's data from Server A by 20%20\%.
4
Use the constant ratio to find the data from Server B in the second session.
B2=72 MBB_2 = 72\text{ MB}
Set up the proportion 120B2=53\frac{120}{B_2} = \frac{5}{3} and solve for B2B_2 by cross-multiplying.

Anahtar Kavram

Solving part-to-part and part-to-whole ratio problems under proportional changes
Soru 171Soru

An agricultural researcher wants to evaluate the effectiveness of a new organic fertilizer. The researcher selects a random sample of 8080 tomato plants of a specific variety from a greenhouse containing 1,2001,200 tomato plants of this variety. The researcher randomly assigns 4040 of the selected plants to receive the organic fertilizer and the remaining 4040 plants to receive a standard chemical fertilizer. At the end of the study, the plants that received the organic fertilizer produced a significantly higher average yield of tomatoes than the plants that received the standard chemical fertilizer. Based on this information, which of the following is the most appropriate conclusion?

Cevabı ve açıklamayı göster

Cevap: The organic fertilizer causes a higher average yield of tomatoes than the standard chemical fertilizer for the 1,2001,200 tomato plants of this variety in the greenhouse.

Cevap

The organic fertilizer causes a higher average yield of tomatoes than the standard chemical fertilizer for the 1,2001,200 tomato plants of this variety in the greenhouse.
The study design includes both random sampling from a defined population (the 1,2001,200 tomato plants of this variety in the greenhouse) and random assignment of treatments (the fertilizers). Random assignment allows the researcher to conclude that the organic fertilizer caused the difference in yield, while random sampling allows this causal conclusion to be generalized to the entire population of 1,2001,200 tomato plants.

Adım Adım Çözüm

1
Determine if a cause-and-effect relationship can be established.
A cause-and-effect relationship can be established because the treatments (organic fertilizer vs. standard chemical fertilizer) were randomly assigned to the selected plants.
Random assignment of treatments minimizes the influence of confounding variables, allowing the researcher to conclude that differences in the outcome are caused by the treatments.
2
Identify the population to which the causal conclusion can be generalized.
The causal conclusion can be generalized only to the 1,2001,200 tomato plants of this specific variety in this greenhouse.
The sample of 8080 plants was randomly selected from this specific population of 1,2001,200 plants in the greenhouse. Generalizing to all tomato plants of this variety everywhere is not valid because the sample may not represent plants in other environments. Generalizing to other species of plants in the greenhouse is not valid because only one specific variety of tomato plant was studied.

Anahtar Kavram

Generalizability and causal inference in statistical studies.
Soru 172Soru

An older printing press can produce 420420 brochures every 1515 minutes. A newer printing press can produce brochures at a rate that is 1.51.5 times the rate of the older press. If both presses run simultaneously at their respective constant rates, how many minutes will it take them to produce a total of 2,1002,100 brochures?

Cevabı ve açıklamayı göster

Cevap: 30

Cevap

The correct answer is 3030 minutes.
To find the time needed, first calculate the individual rates in brochures per minute. The older press prints 420420 brochures in 1515 minutes, which is 42015=28\frac{420}{15} = 28 brochures per minute. The newer press prints at 1.51.5 times this rate, which is 1.5×28=421.5 \times 28 = 42 brochures per minute. Working together, their combined rate is 28+42=7028 + 42 = 70 brochures per minute. Dividing the total target of 2,1002,100 brochures by the combined rate of 7070 brochures per minute yields 2,10070=30\frac{2,100}{70} = 30 minutes. Thus, the correct option is 3030.

Adım Adım Çözüm

1
Calculate the rate of the older printing press in brochures per minute.
The older press prints at a rate of 42015=28\frac{420}{15} = 28 brochures per minute.
Finding the unit rate allows us to easily combine and compare the performance of both presses.
2
Calculate the rate of the newer printing press.
The newer press prints at a rate of 28×1.5=4228 \times 1.5 = 42 brochures per minute.
The problem states the newer press operates at 1.51.5 times the rate of the older press.
3
Determine the combined rate of both presses working together.
The combined rate is 28+42=7028 + 42 = 70 brochures per minute.
When both presses run simultaneously, their rates add up to form the total production rate.
4
Calculate the time required to produce 2,1002,100 brochures.
The required time is 2,10070=30\frac{2,100}{70} = 30 minutes.
Dividing the total work by the combined rate gives the total time needed to complete the task.

Anahtar Kavram

Solving rate problems by finding individual unit rates and combining them to find the total time required for a joint task.
Soru 173Soru

At a currency exchange booth, 44 US dollars (USD) can be exchanged for 55 local credits, and 66 local credits can be exchanged for 1515 reward coupons. Based on these rates, what is the total number of reward coupons that can be obtained in exchange for 2424 USD?

Cevabı ve açıklamayı göster

Cevap: 75

Cevap

75
To find the number of reward coupons obtained from 2424 USD, we perform a two-step rate conversion. First, convert USD to local credits: 24 USD×5 local credits4 USD=30 local credits24\text{ USD} \times \frac{5\text{ local credits}}{4\text{ USD}} = 30\text{ local credits}. Second, convert local credits to reward coupons: 30 local credits×15 coupons6 local credits=75 coupons30\text{ local credits} \times \frac{15\text{ coupons}}{6\text{ local credits}} = 75\text{ coupons}. Thus, the final value is 7575.

Adım Adım Çözüm

1
Set up a proportion to find the number of local credits equivalent to 2424 USD.
3030 local credits
Using the exchange rate of 44 USD to 55 local credits, multiply the starting value of 2424 USD by the conversion factor 54\frac{5}{4}.
2
Set up a proportion to find the number of coupons equivalent to 3030 local credits.
7575 coupons
Using the exchange rate of 66 local credits to 1515 coupons, multiply the 3030 local credits by the conversion factor 156\frac{15}{6}.

Anahtar Kavram

Multi-step rate conversion and unit analysis
Soru 174Soru

In a science department, the ratio of the number of students enrolled in Chemistry to the number of students enrolled in Physics is 55 to 33. The ratio of the number of students enrolled in Physics to the number of students enrolled in Biology is 22 to 77. If no student is enrolled in more than one of these courses and there are 105105 students enrolled in Biology, what is the total number of students enrolled in these three courses?

Cevabı ve açıklamayı göster

Cevap: 185

Cevap

185
To find the total number of students, we must determine the enrollment in each course. The number of Biology students is given as 105105. The ratio of Physics to Biology students is 22 to 77, which means the number of Physics students is 105×27=30105 \times \frac{2}{7} = 30. The ratio of Chemistry to Physics students is 55 to 33, so the number of Chemistry students is 30×53=5030 \times \frac{5}{3} = 50. Summing these values gives the total enrollment: 50+30+105=18550 + 30 + 105 = 185.

Adım Adım Çözüm

1
Calculate the number of students enrolled in Physics
30 students
Since the ratio of Physics to Biology is 22 to 77 and there are 105105 students in Biology, we set up the proportion Physics105=27\frac{\text{Physics}}{105} = \frac{2}{7}, which yields Physics=105×27=30\text{Physics} = 105 \times \frac{2}{7} = 30.
2
Calculate the number of students enrolled in Chemistry
50 students
Since the ratio of Chemistry to Physics is 55 to 33 and there are 3030 students in Physics, we set up the proportion Chemistry30=53\frac{\text{Chemistry}}{30} = \frac{5}{3}, which yields Chemistry=30×53=50\text{Chemistry} = 30 \times \frac{5}{3} = 50.
3
Calculate the total number of students enrolled in the three courses
185 students
Add the students enrolled in all three courses: 50 (Chemistry)+30 (Physics)+105 (Biology)=18550 \text{ (Chemistry)} + 30 \text{ (Physics)} + 105 \text{ (Biology)} = 185.

Anahtar Kavram

Solving multi-step ratio problems by finding a common variable to link multiple ratios.
Soru 175Soru

A solar energy storage system collects electricity from two solar panel arrays, Array XX and Array YY. Array XX produces 33 kilowatt-hours (kWh) of electricity for every 44 hours of direct sunlight. Array YY produces 55 kWh of electricity for every 66 hours of direct sunlight. If both arrays receive direct sunlight simultaneously, how many hours of direct sunlight are required for the two arrays to produce a combined total of 3838 kWh of electricity?

Cevabı ve açıklamayı göster

Cevap: 24

Cevap

24
The correct answer is 2424. First, find the rate of each array in kWh per hour: Array XX has a rate of 34\frac{3}{4} kWh/hour and Array YY has a rate of 56\frac{5}{6} kWh/hour. Since the arrays operate simultaneously, add their individual rates to find the combined rate of 34+56=912+1012=1912\frac{3}{4} + \frac{5}{6} = \frac{9}{12} + \frac{10}{12} = \frac{19}{12} kWh/hour. To find the total hours tt needed to produce 3838 kWh, set up the equation 1912t=38\frac{19}{12}t = 38. Solving for tt gives t=38×1219=24t = 38 \times \frac{12}{19} = 24 hours.

Adım Adım Çözüm

1
Calculate the individual hourly rates of electricity production for Array XX and Array YY.
Array XX produces at a rate of 34\frac{3}{4} kWh per hour, and Array YY produces at a rate of 56\frac{5}{6} kWh per hour.
Converting the given production rates to unit rates (kWh per hour) allows them to be directly compared and combined.
2
Add the individual rates to find the combined rate of both arrays operating simultaneously.
Combined rate is 1912\frac{19}{12} kWh per hour.
Since both arrays operate simultaneously, their rates of production add together. The common denominator for 44 and 66 is 1212, so 34+56=912+1012=1912\frac{3}{4} + \frac{5}{6} = \frac{9}{12} + \frac{10}{12} = \frac{19}{12}.
3
Determine the time required to produce a combined total of 3838 kWh.
2424 hours.
Divide the total target production of 3838 kWh by the combined rate of 1912\frac{19}{12} kWh per hour: 38÷1912=38×1219=2×12=2438 \div \frac{19}{12} = 38 \times \frac{12}{19} = 2 \times 12 = 24.

Anahtar Kavram

Ratios, Rates, and Proportions
Tahmini Süre:1m 30s
Soru 176Soru

A quality control inspector at an electronics factory found that in a large shipment of smartphone screens, the ratio of the number of damaged screens to the number of undamaged screens was 33 to 2222. If the shipment contained a total of 6,6006,600 smartphone screens, how many of the screens in the shipment were damaged?

Cevabı ve açıklamayı göster

Cevap: 792

Cevap

792
The correct value of 792792 is obtained by first determining the total number of parts in the ratio, which is 3+22=253 + 22 = 25. The fraction of damaged screens in the shipment is therefore 325\frac{3}{25}. Multiplying this fraction by the total number of screens in the shipment (6,6006,600) yields 325×6,600=792\frac{3}{25} \times 6,600 = 792.

Adım Adım Çözüm

1
Determine the total number of parts in the ratio.
3+22=253 + 22 = 25 total parts
To find the fraction of the total shipment that is damaged, we must add the parts of the damaged and undamaged screens.
2
Set up the fraction of the shipment that is damaged.
325\frac{3}{25}
Since there are 33 damaged screens for every 2525 total screens, the proportion of damaged screens is 325\frac{3}{25}.
3
Multiply the fraction by the total number of screens in the shipment.
325×6,600=792\frac{3}{25} \times 6,600 = 792
Multiplying the proportion of damaged screens by the total size of the shipment gives the total number of damaged screens.

Anahtar Kavram

Applying part-to-whole ratios to solve for a specific quantity in a given total.
Tahmini Süre:1m 15s
Soru 177Soru

To create a specific type of mortar, a builder mixes cement and sand in a ratio of 22 to 55 by weight. To create a concrete mixture, the builder mixes this mortar with gravel in a ratio of 77 to 33 by weight. If the builder prepares 300300 kilograms of the concrete mixture, how many kilograms of sand are needed?

Cevabı ve açıklamayı göster

Cevap: 150

Cevap

150
To find the weight of the sand needed, first determine the weight of the mortar in the concrete mixture. The ratio of mortar to gravel is 77 to 33, meaning mortar represents 710\frac{7}{10} of the total 300300-kilogram concrete mixture. The weight of the mortar is 710×300=210\frac{7}{10} \times 300 = 210 kilograms. Next, since mortar consists of cement and sand in a ratio of 22 to 55, the sand represents 57\frac{5}{7} of the mortar's weight. Calculating 57\frac{5}{7} of 210210 kilograms yields 150150 kilograms. Therefore, the weight of the sand needed is 150150 kilograms.

Adım Adım Çözüm

1
Find the total weight of the mortar in the concrete mixture.
210210 kilograms
The concrete mixture has a ratio of mortar to gravel of 77 to 33 by weight. This means mortar makes up 77+3=710\frac{7}{7+3} = \frac{7}{10} of the total concrete weight. Multiplying this fraction by the total weight of 300300 kilograms gives 710×300=210\frac{7}{10} \times 300 = 210 kilograms of mortar.
2
Find the weight of the sand within the mortar.
150150 kilograms
The mortar is composed of cement and sand in a ratio of 22 to 55 by weight. Thus, sand makes up 52+5=57\frac{5}{2+5} = \frac{5}{7} of the mortar's weight. Multiplying this fraction by the mortar's weight of 210210 kilograms yields 57×210=150\frac{5}{7} \times 210 = 150 kilograms of sand.

Anahtar Kavram

Solving multi-step ratio problems by determining part-to-whole relationships and compounding ratios.
Soru 178Soru

In a hydroponic farming system, a nutrient solution is created by mixing a liquid fertilizer concentrate with water in a ratio of 33 to 5050 by volume. To fill a reservoir, a technician needs to prepare a total of 318318 liters of this nutrient solution. How many liters of the liquid fertilizer concentrate are required to prepare the solution?

Cevabı ve açıklamayı göster

Cevap: 18

Cevap

18
To find the amount of liquid fertilizer concentrate needed, we first express the ratio in terms of the total mixture. The ratio of concentrate to water is 33 to 5050, meaning there are 33 parts of concentrate for every 5050 parts of water, making a total of 3+50=533 + 50 = 53 parts. Since the total volume of the solution is 318318 liters, each part represents 31853=6\frac{318}{53} = 6 liters. The amount of concentrate required is 33 parts, which corresponds to 3×6=183 \times 6 = 18 liters.

Adım Adım Çözüm

1
Calculate the total parts represented in the ratio of liquid fertilizer concentrate to water.
The total number of parts is 3+50=533 + 50 = 53.
Since the ratio of concentrate to water is 33 to 5050, the entire nutrient solution is divided into 5353 equal parts.
2
Find the volume of solution that corresponds to one part.
One part is equal to 31853=6\frac{318}{53} = 6 liters.
Dividing the total volume of the nutrient solution (318318 liters) by the total number of parts (5353) gives the volume of a single part.
3
Calculate the total volume of liquid fertilizer concentrate needed.
The volume of concentrate required is 3×6=183 \times 6 = 18 liters.
Since the concentrate accounts for 33 parts of the total mixture, multiplying the volume of one part by 33 gives the total amount of concentrate needed.

Anahtar Kavram

Solving part-to-whole ratio problems by determining the value of a single unit or part from a given total quantity.

Alternatif Yöntem

Let the volume of the fertilizer concentrate be 3x3x and the volume of water be 50x50x. The total volume of the nutrient solution is 3x+50x=53x3x + 50x = 53x. Given that the total volume is 318318 liters, we can set up the equation 53x=31853x = 318. Solving for xx gives x=6x = 6. The volume of the concentrate is 3x=3(6)=183x = 3(6) = 18 liters.
Tahmini Süre:1m 15s
Soru 179Soru

A chef prepares a spice mix by combining paprika, cumin, and coriander in a ratio of 8:5:28 : 5 : 2 by weight. If the chef wants to make a total of 6060 ounces of the spice mix, how many ounces of cumin are needed?

Cevabı ve açıklamayı göster

Cevap: 20

Cevap

The correct answer is 20 ounces.
The correct answer is 20 ounces. To find the amount of cumin needed, first sum the parts of the ratio to find the total parts of the mixture: 8+5+2=158 + 5 + 2 = 15 parts. Since cumin represents 5 of these 15 parts, the fraction of the spice mix that is cumin is 515\frac{5}{15}, which simplifies to 13\frac{1}{3}. Multiplying this fraction by the total desired weight of the spice mix gives 13×60=20\frac{1}{3} \times 60 = 20 ounces.

Adım Adım Çözüm

1
Calculate the total number of parts in the ratio.
8+5+2=158 + 5 + 2 = 15 parts.
Determining the total parts is necessary to find what fraction of the whole mixture is represented by cumin.
2
Determine the fractional portion of the mixture that is cumin.
The fraction is 515\frac{5}{15}, which simplifies to 13\frac{1}{3}.
This fraction represents the ratio of the cumin parts to the total parts of the spice mix.
3
Multiply the cumin fraction by the total weight of the mix to find the weight of cumin.
13×60=20\frac{1}{3} \times 60 = 20 ounces.
Multiplying the proportion of cumin by the total desired weight of the spice mix yields the required ounces of cumin.

Anahtar Kavram

Solving part-to-whole ratio problems by finding the total number of parts and applying the fraction to the overall amount.
Tahmini Süre:1m 15s
ÖncekiSayfa 9 / 9
Problem-Solving and Data Analysis Alıştırma Soruları — SAT — Sayfa 9 | Examkin