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Zorluk: OrtaDivisibility Rules and Remainder Theorem

An inventory tracking system logs the total number of specialized microchips stored in a warehouse as exactly 5×14333×28505 \times 14^{33} - 3 \times 28^{50} units. These microchips are being shipped out in standard crates that hold exactly 1313 units each. The remaining microchips that do not make a full crate will be set aside for quality assurance testing. How many microchips will be set aside?

Cevap: 6 microchips

Cevap

6 microchips will be set aside for quality assurance testing.
By evaluating the modulo 1313 for each term independently using exponent cyclicity, the expression 5×14335 \times 14^{33} reduces to 55, and 3×28503 \times 28^{50} reduces to 1212. Subtracting these yields an intermediate remainder of 7-7. Since remainders representing physical quantities must be non-negative, we add the divisor (1313) to 7-7, resulting in a final positive remainder of 66.

Adım Adım Çözüm

1
Formulate the modulo expression.
(5×14333×2850)(mod13)(5 \times 14^{33} - 3 \times 28^{50}) \pmod{13}
Finding the remaining chips after filling crates of 13 is equivalent to calculating the remainder when the total is divided by 13.
2
Reduce the base of the first term.
5×133=5(mod13)5 \times 1^{33} = 5 \pmod{13}
1414 leaves a remainder of 11 when divided by 1313. Any power of 11 remains 11.
3
Reduce the base of the second term.
3×250(mod13)3 \times 2^{50} \pmod{13}
2828 divided by 1313 is 22 with a remainder of 22.
4
Apply Fermat's Little Theorem to evaluate 250(mod13)2^{50} \pmod{13}.
2121(mod13)2^{12} \equiv 1 \pmod{13}, so 250224(mod13)2^{50} \equiv 2^2 \equiv 4 \pmod{13}
Powers of 22 repeat every 1212 modulo 1313. Since 50=12×4+250 = 12 \times 4 + 2, the remainder of the exponent is 22.
5
Evaluate the full second term.
3×4=12(mod13)3 \times 4 = 12 \pmod{13}
Multiply the evaluated exponent component by the original coefficient.
6
Subtract to find the initial remainder.
512=75 - 12 = -7
Substitute the evaluated remainders back into the full expression.
7
Convert the negative remainder into a positive value.
7+13=6-7 + 13 = 6
A physical count must be a positive integer. Adding the divisor to a negative remainder gives the true positive remainder.

Anahtar Kavram

Modular arithmetic properties, Fermat's Little Theorem, and conversion of negative remainders.
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