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Zorluk: ZorData Sufficiency

Is the positive integer nn divisible by 3636?

Statement I: n2n^2 is divisible by 108108.
Statement II: n3n^3 is divisible by 576576.

Which of the following options correctly describes the sufficiency of the statements?

  1. A
    Statement I alone is sufficient to answer the question, but Statement II alone is not sufficient.
  2. B
    Statement II alone is sufficient to answer the question, but Statement I alone is not sufficient.
  3. C
    Either Statement I alone or Statement II alone is sufficient to answer the question.
  4. D
    Neither Statement I nor Statement II is sufficient to answer the question, and additional data is needed.
  5. Both Statement I and Statement II together are sufficient to answer the question, but neither statement alone is sufficient.Cevap

Cevap

Both Statement I and Statement II together are sufficient to answer the question, but neither statement alone is sufficient.
Evaluating both statements together shows that Statement I requires nn to be a multiple of 1818 (21×322^1 \times 3^2) and Statement II requires nn to be a multiple of 1212 (22×312^2 \times 3^1). The least common multiple of 1818 and 1212 is 3636, which proves that nn is guaranteed to be divisible by 3636. Neither statement alone provides both prime factor requirements.

Adım Adım Çözüm

1
Analyze Statement I individually
Statement I states that n2n^2 is divisible by 108=22×33108 = 2^2 \times 3^3. In the prime factorization of a square n2n^2, all exponents must be even numbers. Thus, n2n^2 must contain at least 222^2 and 343^4. Taking square roots, nn must be a multiple of 21×32=182^1 \times 3^2 = 18. If n=18n = 18, nn is NOT divisible by 3636. If n=36n = 36, nn IS divisible by 3636. Because we get both 'No' and 'Yes' answers, Statement I alone is NOT sufficient.
We must test if Statement I uniquely determines whether nn is divisible by 3636.
2
Analyze Statement II individually
Statement II states that n3n^3 is divisible by 576=26×32576 = 2^6 \times 3^2. In the prime factorization of a cube n3n^3, all exponents must be multiples of 33. Thus, n3n^3 must contain at least 262^6 and 333^3. Taking cube roots, nn must be a multiple of 22×31=122^2 \times 3^1 = 12. If n=12n = 12, nn is NOT divisible by 3636. If n=36n = 36, nn IS divisible by 3636. Because we get both 'No' and 'Yes' answers, Statement II alone is NOT sufficient.
We must test if Statement II uniquely determines whether nn is divisible by 3636.
3
Combine Statement I and Statement II
From Statement I, nn contains at least 323^2 in its prime factorization. From Statement II, nn contains at least 222^2 in its prime factorization. Combining these requirements, nn must contain at least 22×32=362^2 \times 3^2 = 36. Therefore, nn is guaranteed to be divisible by 3636. Both statements together yield a definitive 'Yes'.
Evaluating both statements together combines the minimal necessary powers of each prime factor.

Anahtar Kavram

Data Sufficiency evaluation of prime factor exponents and divisibility rules
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