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Zorluk: Çok zorAnalytical Puzzles and Grouping

Six administrative officers—Aarav, Bina, Chetan, Divya, Ekta, and Farhan—belong to three departments: Agriculture, Defense, and Commerce, with exactly two officers per department. They are allocated into two three-member scrutiny committees, Committee 1 and Committee 2, such that each committee contains exactly one representative from each department. Each officer holds one of two designations: Senior Advisor or Junior Advisor.

The allocation follows these analytical rules:
1. Aarav and Farhan belong to the same department (which is not Defense), but are assigned to different committees.
2. Bina and Chetan are the only two officers representing the Defense department, and Bina is assigned to Committee 1.
3. Ekta and Farhan are Senior Advisors, whereas Bina and Divya are Junior Advisors.
4. The Commerce department consists of exactly one Senior Advisor and one Junior Advisor.
5. Chetan and Divya are assigned to the same committee.
6. Aarav is a Junior Advisor, and the Agriculture department officer assigned to Committee 2 is a Senior Advisor.

Based on the above constraints, which officer represents the Agriculture department in Committee 1, and what is their designation?

  1. Aarav, Junior AdvisorCevap
  2. B
    Farhan, Senior Advisor
  3. C
    Ekta, Senior Advisor
  4. D
    Aarav, Senior Advisor

Cevap

Aarav, Junior Advisor is the representative for the Agriculture department in Committee 1.
Through step-by-step constraint elimination, Bina and Chetan form the Defense department, Ekta and Divya form Commerce, and Aarav and Farhan form Agriculture. Since each committee requires one officer per department, Committee 1 gets Bina (Defense) and Ekta (Commerce). By rule 5, Divya joins Chetan in Committee 2. Rule 6 dictates that the Agriculture officer in Committee 2 is a Senior Advisor, which corresponds to Farhan. Therefore, Aarav—who is a Junior Advisor—must represent Agriculture in Committee 1.

Adım Adım Çözüm

1
Determine department memberships
Defense = {Bina, Chetan}. Since Aarav and Farhan are in the same department (not Defense), Agriculture = {Aarav, Farhan}. The remaining two, Commerce = {Ekta, Divya}.
Rule 2 fixes Defense to Bina and Chetan. Rule 1 pairs Aarav and Farhan outside Defense, leaving Ekta and Divya for Commerce.
2
Determine designations by department
Commerce has Ekta (Senior Advisor) and Divya (Junior Advisor). Agriculture has Farhan (Senior Advisor) and Aarav (Junior Advisor).
Rule 3 gives Ekta (Senior), Farhan (Senior), Bina (Junior), Divya (Junior). Rule 4 confirms Commerce has one Senior (Ekta) and one Junior (Divya). Rule 6 confirms Aarav is Junior.
3
Distribute Defense and Commerce officers across committees
Committee 1 has Bina (Defense) and Ekta (Commerce). Committee 2 has Chetan (Defense) and Divya (Commerce).
Each committee gets one Defense officer. Bina is in Committee 1 (Rule 2), so Chetan is in Committee 2. Divya is in Committee 2 with Chetan (Rule 5), leaving Ekta for Committee 1.
4
Distribute Agriculture officers and identify Committee 1 representative
Farhan (Senior Advisor) goes to Committee 2. Aarav (Junior Advisor) goes to Committee 1.
Rule 6 states the Agriculture officer in Committee 2 is a Senior Advisor (Farhan). Thus, Aarav (Junior Advisor) must be in Committee 1.

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